MATHEMATICS HIGH SCHOOL

1 point1) Taylor and her family took a road trip. She explains that the equation y =
60x describes the proportional relationship between the number of miles,
y, her family traveled, to the number of hours, x, the trip took. Which
statement represents the same proportional relationship? *

Taylor's family traveled 50 miles in 1 hour.

Taylor's family traveled 120 miles in 2 hours.

Taylor's family traveled 180 miles in 4 hours.

Taylor's family traveled 200 miles in 5 hours.

Answers

Answer 1

Answer:

Answer:

120 miles in 2 hours

Step-by-step explanation:

120 = 60(2)

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a piece of licorice is to be cut into 10 equal size pieces. if the length of the piece of licorice is 2/3 yard, how long will each piece of licorice be?

Answers

Sooo, 2/3 of a yard is 2 feet because a yard is 3 feet. If you need 10 of the same pieces and you convert feet to inches you would have 24 inches. 24/10= 2.4. Each piece of licorice would need to be 2.4 inches long if you wanted the same length.

What are the domain and range of the function {(5, 3), (7, 1), (11, –2), (4, 9), (–2, 4)}? A.

Domain: {3, 1, 9, 4}; Range: {5, 7, 11, 4, }

B.
Domain: {5, 7, 11, 4, }; Range: {3, 1, 9, 4}

C.
Domain: {5, 7, 11, 4, –2}; Range: {3, 1, –2, 9, 4}

D.

Domain: {3, 1, –2, 9, 4}; Range: {5, 7, 11, 4, –2}

Answers

Answer is C. Set of first part of the binary set is domain and second part of it is range. So the domain will be {5, 7, 11, 4, –2} and the range will be {3, 1, –2, 9, 4}

Answer:

Domain: {5, 7, 11, 4, –2}; Range: {3, 1, –2, 9, 4}

Step-by-step explanation:

The domain is the X value or the independent in put.

Range is the Y values, or the Dependant input.

Hope this helps!

A.W.E.S.W.A.N

A line contains the points (3, –2) and (–6, –8). Write the equation of the line using point-slope form.

Answers

Y^2 - Y^1/ X^2 - X^1 os the formula that you would use to find the line that passes through those points.

Your literature class will read 4 novels this year, chosen by class vote from a list of 7 possible books offered by the teacher.a) How many different ways could the course unfold, given that it probably matters what order you read the books in?
b) How many different choices of books could the class make?
a) The number of different ways the course could unfold is

Answers

Answer:

a) 840 different ways

b) 35 different choices of books

Step-by-step explanation:

We know that our literature class will read a total of 4 novels this year.

All novels chosen by class vote from a list of 7 possible books offered by the teacher.

Wherever we have an experiment $''N''$ which is formed by sub - experiments that can occurred in $m_(1),m_(2),...,m_(n)$ ways, the total number of ways in which the whole experiment $''N''$ can be developed is :

$m_(1)$ x $m_(2)$ x ... x $m_(n)$

Then, for a) if it matters what order we read the books in, the total number of different ways could the course unfold is :

$(7).(6).(5).(4)=840$ (I)

Because for the first book there are 7 different choices. Now, given that we choose the first book, we only have 6 different choices for the second one.

Continuing with the idea, we deduce the equation (I).

For item b) :

Wherever we have $''n''$ different objects and we want to find the ways that we can choose $''r''$ objects from that group, we need to use the combinatorial number.

We define the combinatorial number as :

$nCr=\left(\begin{array}{c}n&r\end{array}\right)=(n!)/(r!(n-r)!)$

Then, if we apply this to the problem, the total different choices of books if we want 4 novels voting from a total of 7 possible books is :

$7C4=(7!)/(4!(7-4)!)=35$

a) 840 different ways

b) 35 different choices of books

Final answer:

The number of different ways the course could unfold is 210, and the number of different choices of books the class could make is 35.

Explanation:

The number of different ways the course could unfold is equal to the number of permutations of the 4 books chosen from the list of 7. This can be calculated using the formula for permutations: P(n, r) = n! / (n - r)!. In this case, n = 7 (the number of books) and r = 4 (the number of books chosen). Using the formula, we get P(7, 4) = 7! / (7 - 4)! = 7! / 3! = 7 imes 6 imes 5 = 210.

The number of different choices of books the class could make is equal to the number of combinations of the 4 books chosen from the list of 7. This can be calculated using the formula for combinations: C(n, r) = n! / (r! (n - r)!). In this case, n = 7 (the number of books) and r = 4 (the number of books chosen). Using the formula, we get C(7, 4) = 7! / (4! (7 - 4)!) = 7! / (4! imes 3!) = (7 imes 6 imes 5) / (4 imes 3 imes 2) = 35.

Learn more about Combinations and Permutations here:

brainly.com/question/19917646

#SPJ3

Ariana spent a quarter of her allowance on sweets and she put one third of the remainder in her piggy bank. If she had twenty dollars left, what was her allowance

Answers

Answer:

$40

Step-by-step explanation:

Ariana spent a quarter of her allowance

1 - 1/4 = 3/4 was left

put one third of the remainder in her piggy bank

1/3 * 3/4 = 1/4

She spent 1/4 and piggy banked 1/4

so the $20 she had left was half her allowance.

allowance was $40

Ariana gets a very large allowance!

if a and b are the measures of two first quadrant angles and sin a = 4/5 and sin b = 5/13, find sin a+b.

Answers

given that sin a= 4/5
cos a= √(1-sin²a)
   = √(1-16/25)
   = √(9/25)
   = 3/5
sin b=5/13
cos b= √(1-sin²b)
   = √(1-25/169)
   = √(144/169)
   = 12/13

sin(a+b)= sin a· cos b + cos a · sin b
      = 4/5· 12/13 + 3/5· 5/13
      = 48/65+15/65
   = 63/65
hope it helps

Answer:

[A] sin(a + b) = $(63)/(65)$

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