MATHEMATICS HIGH SCHOOL

Writ an equation of a parabola that has a vertex (1,3) and passes through the point (2,5)

Answers

Answer 1
Answer:

Answer:

y=2x+1

Step-by-step explanation:
Answer 2
Answer: This is what I got hope it helps

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A line contains the point (0, –2). If the slope of the line is m= - 6 write the equation of the line using slope-intercept form.

Answers

y = -6x-2
since -2 is the y intercept

Find the zeros of y=x²-1 from a graph.

Answers

y=x^2-1

0=x^2-1

0=(x+1)(x-1)

x+1=0

x=-1

x-1=0

x=1

zeros:-1,1
y = x² - 1

I can find the zeros from a graph, but that won't help you any, because
I'm not about to draw the graph and then post it here.

y = (x + 1) (x - 1)

y = 0 when x = +1 or x = -1.

There are 3 cans that store 9 tennis balls. write an equation to represent the relationship

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3x=9
X=3

This means that eqch can contains 3 balls

At what point does the graph of 5x + 4y = 12 intersect the y-axis?

Answers

first step is to simplify the equation or calculate..... so the formate of y=mx+b
4y=-5x+12
y=-5/4+3

so slope m=-5/4
b=3
count 3 on the y intercept from zero going up 3,put a dot there . then go down -5 from 3 and then count right 4 and put a dot there.if you need more help ask me or message me.
In there x=0 so 4y=12 or y=3. The point is (0,3)
That x=0 is the definition for x intersecting the axis.
We're at the same lesson now, lol.

A rectangular pool measures 10m by 5m. A deck, of uniform width, is to be built all the way around the pool such that the total area of the pool and deck will be126m2 . Set up and solve a quadratic equation to determine the width of the deck.

Answers

Answer:

The width of the deck is 2m .

Step-by-step explanation:

Let the width of the pool be represented by w. As stated in the problem a deck of uniform width is to be built so the total width of the pool and deck will be w+w = 2w.

Now the total dimensions can be taken as

10m+ 2w and 5m + 2w of both the pool and deck.

Area = length * breadth

126m ²= (10m+ 2w) ( 5m + 2w )

126= 50 + 30 w+ 4w²

0= 50 -126+ 30 w+ 4w²

0 = 30 w+ 4w²- 76

Taking 2 as common

0= 2( 15 w+ 2w² - 38)

2w²+ 15 w - 38= 0

The above equation is the quadratic equation and can be solved as follows.

a= 2 , b= 15 and c= -38

b= -b±√b²- 4ac/2a

Putting the values

b= - 15±√15²- 4( 2)(-38)/2(2)

b= - 15± 23/4

b= - 38/4 or 8/4

b= 2 m

The width cannot be negative so we ignore the negative value

The width of the deck is 2m .

The can be checked by putting the value in the original equation.

126m ²= (10m+ 2w) ( 5m + 2w )

126m ²= (10m+ 2(2)) ( 5m + 2(2) )

126m ²= (10m+ 4) ( 5m + 4 )

126m ²= 14*9

126m ²= 126m ²

Which is an example of an statement that is accepted without proof?A) Parallel Postulate
B) Pythagorean Theorem
C) Betweenness Theorem
D) Right Angle Congruence Theorem

Answers

A. Parallel Postulate
That type of statement is accepted without any proof
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