Someone help me please I don’t know how to do this
serenavass avatar

Answers

Answer 1
Answer:

Step-by-step explanation:

A

y=10x

x:y=x:10x=1:10


Related Questions

Using the quadratic formula to solve 4x^2 – 3x + 9 = 2x + 1, what are the values of x?A: 1+-sqrt159i/8B: 5+-sqrt153i/8C: 5+-sqrt103i/8D: 1+-sqrt153i/8
HELP! What does BM equal? WILL GIVE BRAINLIEST!
For the first 500 minutes used each month, the customer is charged a flat rate of $50. These 500 minutes are "included" in their monthly plan.For any additional minutes used, the customer is charged an additional $.10 per minute.Is it linear
What percent of 45 is 72
The Length of a rectangle is 4 centimeters less than twice its width . The perimeter of the rectangle is 34cm. What are the dimensions of the rectangle ?

Emma works in a department store selling clothing. She makes a guaranteed salary of $200 per week, but is paid a commision on top of her base salary equal to 25% of her total sales for the week. How much would Emma make in a week in which she made $2200 in sales? How much would Emma make in a week if she made x
x dollars in sales?

Answers

Answer:

Step-by-step explanation:

0.25 x 2200 = $55

55+200=255

$255

pt 2: 0.25x+200

Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm to the right and the 12.0 N block moves 75.0cm downward.Find the total work done on 20.0N block if there is no friction between the table and the 20.0N block.

Answers

The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus, 
1.22 a = 12.0 - T  (eqn 1)
and for the 20.0 N block: 
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction) 
2.04 a = T - 6.5  (eqn 2) 

[eqn 1] + [eqn 2] → 3.26 a = 5.5 
a = 1.69 m/s² 


Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5 
T = 9.95 N 

Now want the resultant force acting on the 20.0 N block: 
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N 
Units have to be consistent ... so have to convert 75.0 cm to m: 

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m 
work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J

Final answer:

The total work done on the 20.0 N block as it moves 75.0 cm to the right, with no friction between the table and the block, is 15 Joules.

Explanation:

In physics, work done by a force is given by the formula Work = Force x Distance x Cos θ, where θ is the angle between the force and the direction of motion. Here, the force is the same as the weight of the 20.0 N block (because weight = mass * gravity, and the mass is the weight divided by gravity, so mass * gravity = weight), and because the block moves horizontally (rightward), θ is 0 degrees. The Cos of 0 degrees is 1.

So, the work done on the 20.0 N block as it moves 75.0 cm (or 0.75 meters, because 1 m = 100 cm) to the right is 20.0 N * 0.75 m * 1 = 15 Joules.

Learn more about Work Done here:

brainly.com/question/35917320

#SPJ12

Simplify the expression. Write the answer without using parentheses or negative exponents.((x^4 y^2)^5)/((x^2 y)^2)

Answers

( (x^4 y^2)^5 )/( (x^2 y)^2 ) =( x^(4*5) y ^(2*5) )/( x ^(2*2) y ^2 ) =( x^(20) y ^(10) )/( x^4y^2 ) = x^(20-4) *y^(10-2)= x^(16) *y^(8)


21.034.005.023 word form

Answers

Answer:

twenty-one and thirty-four million five thousand twenty-three billionths

Step-by-step explanation:

What number solves this propoetion? 2.4/m=3/4.5

Answers

\frac { 2.4 }{ m } =\frac { 3 }{ 4.5 } \n \n \frac { 4.5 }{ 3 } \cdot m\cdot \frac { 2.4 }{ m } =\frac { 3 }{ 4.5 } \cdot m\cdot \frac { 4.5 }{ 3 } \n \n m=\frac { \left( 4.5 \right) \left( 2.4 \right) }{ 3 } \n \n m=\frac { \left( 4+\frac { 1 }{ 2 } \right) \left( 2+\frac { 2 }{ 5 } \right) }{ 3 }

\n \n m=\frac { 8+\frac { 8 }{ 5 } +1+\frac { 2 }{ 10 } }{ 3 } \n \n m=\frac { 9+\frac { 16 }{ 10 } +\frac { 2 }{ 10 } }{ 3 } \n \n m=\frac { \frac { 90 }{ 10 } +\frac { 18 }{ 10 } }{ 3 }

\n \n m=\frac { \frac { 108 }{ 10 } }{ 3 } \n \n m=\frac { 108 }{ 10 } \cdot \frac { 1 }{ 3 } \n \n m=\frac { 108 }{ 30 } \n \n m=\frac { 3\cdot 36 }{ 3\cdot 10 } \n \n m=\frac { 36 }{ 10 } \n \n m=3.6

When y= 234, x= 18. Find the value of x when y= 91. A. 12.75
B. 4.9
C. 7
D. 33.4
F. 13

Answers

Answer:

C

Step-by-step explanation:

Hey! So first divide 234 by 18 to find a ratio. You would get 13:1. So apply this to y=91. 91/13 is 7.

Final answer:

To find the value of x when y = 91, set up a proportion using the given values and cross-multiply. Divide both sides of the equation by the coefficient of x to solve for x. The value of x when y = 91 is 7.

Explanation:

To find the value of x when y = 91, we can use the concept of proportionality. We know that when y = 234, x = 18. We can set up a proportion by cross-multiplying:

(x / 18) = (91 / 234)

Cross-multiplying gives us:

234x = 91 * 18

Dividing both sides by 234 gives us the value of x:

x = (91 * 18) / 234

Simplifying the expression, we get:

x = 7

Therefore, the value of x when y = 91 is 7.

Learn more about Proportionality here:

brainly.com/question/32437705

#SPJ3

Other Questions