Write a conjecture for the following situation - the product of three odd numbers.

Answers

Answer 1
Answer:

Answer:

5

Step-by-step explanation:


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What is the quotient (x^3+8)/(x+2)

Answers

Answer:

Step-by-step explanation:

The easiest way to do this is by using synthetic division (I really hope you know what I'm talking about!)

If the factor is x + 2 = 0, then the solution or the root is x = -2.  We will put -2 outside the "box" and the coefficients from the terms of the polynomial inside the "box":

-2|   1    0    0    8

Bring down the first number and multiply it by the -2.  Put the product up under the first 0 and add:

-2|   1    0    0    8

           -2

      1   -2  

Now multiply the -2 by the -2, put the product up under the next 0 and add:

-2|   1    0    0    8

           -2    4

      1    -2    4

Now multiply the 4 by the -2, put the product up under the 8 and add:

-2|   1    0    0    8

           -2   4    -8

     1    -2   4    0

Those bold numbers are the coefficients to the quotient, which is another polynomial, but is one degree less than the one you started with:

x² - 2x + 4 = 0

Since there is no remainder, then x = -2 is a zero of x³ + 8, and (x + 2) is a factor.

There is a whole world of stuff to learn about quadratics!!

Does anyone know the pattern to this? Does anyone also know the slope to it and where the line intersects at the y-axis and the equation of the line?

Answers

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y_(2)-y_(1)  )/(x_(2)-x_(1)  )

with (x₁, y₁ ) = (1, 3) and (x₂, y₂ ) = (3, 7) ← 2 ordered pairs from the table

m = (7-3)/(3-1) = (4)/(2) = 2

The line crosses the y- axis at (0, 1 ) ← from table

Then c = 1

y = 2x + 1 ← equation of line

(3-i)+(1-2i) =
O 4 - 3i
O 4 +3i
O 4+i

Answers

Answer:

4+i

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Three roots of the polynomial equation x4 - 4x3 - 2x2 + 12x + 9 = 0 are 3, -1 and -1. Explain why the fourth root must be a real number. Find the fourth root.

Answers

Hello,

P(x)=x^4-4x^3-2x^2+12x+9=0
P(3)=3^4-4*3^3-2*3²+12*3+9=81-108-18+36+9=0
P(-1)=(-1)^4 - 4*(-1)^3 -2*(-1)²+12*(-1)+9=1+4-2-12+9=0
P'(x)=4x^3-12x²-4x+12
P'(-1)=4*(-1)^3-12*(-1)²-4*(-1)+12=-4-12+4+12=0
(-1) is a double root
Ok 3,-1,-1 are roots.

If the 4th root is not a real but a complex (a+ib), its conjugate will be also a root , there would be 5 roots and not 4


So, the 4th root is real and equal to 3 ( a double root)

x^4-4x^3-2x²+12x+9=0
==> x^4+x^3-5x^3-5x²+3x²+3x+9x+9=0
==>x^3(x+1)-5x²(x+1)+3x(x+1)+9(x+1)=0
==>(x+1)(x^3-5x²+3x+9)=0
==>(x+1)(x^3+x²-6x²-6x+9x+9)=0
==>(x+1)[x²(x+1)-6x(x+1)+9(x+1)]=0
==>(x+1)²(x²-6x+9)=0
==>(x+1)²(x-3)²=0


P(x)=(x+1)²*(x-3)²



Use the rule y = -x + 7 to fill in the blank
if (1, y) is on the graph, then y =

Answers

Answer:Y=6

Step-by-step explanation:

Y=-x+7

For -x put 1 for the -x

So y=-1+7

Y=6

Help me pleaseee please

Answers

Answer:

1) c/d = pi

Step-by-step explanation:

since c= pi x d

divide both sides by d

c/d = pi