Read the scenario and respond to the following statements and questions. Jeremy went to the mall with $150. He went into one Estimate the total cost of these items, including tax. store where he found the following items that he wanted: Jeans $59.50 each Will Jeremy have enough money to purchase all the items? Shirts $30 each Hats $15.50 each At the store Jeremy is given the choice between two coupons, Jeremy wants to purchase 1 pair of jeans, 3 shirts, 25% off one item or 15% off his entire order, which he can use and 1 hat. The store is having a sale of 10% off all with the 10% off of all shirts. Estimate which coupon will save shirts and the sales tax in Houston is 8.25%, so Jeremy the most money. Jeremy has to take that into consideration when buying his items. . 5

Answers

Answer 1

Answer:

Answer:

kind of confusing

Step-by-step explanation:

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Locate the foci of the ellipse. Show your work.x^2/36+y^2/11=1

Solve to three significant digits 123= 500e ^ -0.12x

Answers

$500{ e }^( -0.12x )=123\n \n { e }^{ -\frac { 12 }{ 100 } x }=\frac { 123 }{ 500 } \n \n { e }^{ -\frac { 3 }{ 25 } x }=\frac { 123 }{ 500 }$

$\n \n { \left( { e }^( x ) \right) }^{ -\frac { 3 }{ 25 } }=\frac { 123 }{ 500 } \n \n { e }^( x )={ \left( \frac { 123 }{ 500 } \right) }^{ \frac { 1 }{ -\frac { 3 }{ 25 } } }$

$\n \n { e }^( x )={ \left( \frac { 123 }{ 500 } \right) }^{ -\frac { 25 }{ 3 } }\n \n \ln { \left( { \left( \frac { 123 }{ 500 } \right) }^{ -\frac { 25 }{ 3 } } \right) } =x$

$\n \n x=-\frac { 25 }{ 3 } \ln { \left( \frac { 123 }{ 500 } \right) }$

$\therefore \quad x\approx 11.7$

Can a system of linear equation have exactly 2 solutions ? why or why not?

Answers

Answer:

Under normal circumstances a system of two linear equations can have 0, 1 or infinitely many solutions.

Step-by-step explanation:

Xian and his cousin Kai both collect stamps, and Kai has 68 stamps. The boys recently joined different stamp collecting clubs. Xian’s club sill send him 12 new stamps per month. Kai’s club will send him 8 new stamps per month. After how many months will Xian and Kai have the same number of stamps? How many stamps will each have?

Answers

Assuming that Xian starts with 0 stamps, you set the equations equal to each other to find what month they have the same amount of stamps.

(68 from Kai's original stamps) (8 from how many per month)
(0 from Xian's original stamps) (12 from how many per month)
68+8m=0+12m
solve for m in this equation and you get 68=4m
and 68/4 = 17 months

For how many stamps each will have, you plug in 17 into m in Xian's equation (you could do either but Xian's is easier):
0+12m
0+12(17)=204
204 stamps.

Hope this helped, it was kinda long lol

Nicole deposited $2,000 at 6% simple interest. How long will it be before she has $2,600 in her account?

Answers

$\bf \qquad \textit{Simple Interest Earned Amount}\n\nA=P(1+rt)\qquad \begin{cases}A=\textit{accumulated amount}\to &2,600\nP=\textit{original amount deposited}\to& \$2,000\nr=rate\to 6\%\to (6)/(100)\to &0.06\nt=years\end{cases}$

solve for "t"

What the difference 400 273

Answers

The difference between the numbers 400 and 273 is 127 obtained by subtracting 273 from 400.

The difference between 400 and 273 is obtained by subtracting 273 from 400:

Four hundred minus two hundred seventy three

400 - 273

= 127

Therefore, the difference between 400 and 273 is 127.

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The difference of 400 and 273

400 - 273 = 127

Answer: 127

*Hope that helps and enjoy Brainly :)

If A = (0, 0) and B = (6, 3), what is the length of ? A.7.73 units B.6.24 units C.5.20 units D.6.71 units

Answers

The length of segment AB is 6.71 units

How to determine the length?

The given parameters are:

A = (0,0) and B = (6,3)

The length AB is calculated using:

$AB = √((x_2 -x_1)^2 + (y_2 -y_1)^2)$

Substitute known values

$AB = √((6 -0)^2 + (3-0)^2)$

Evaluate the sum of exponents

$AB = √(45)$

Evaluate the square root

AB = 6.71

Hence, the length of AB is 6.71 units

Read more about distance at:

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Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].

We have these points: A(0,0) and B(6,3); its distance will be:

dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71

Answer: D. 6.71 units.

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