What is inert pair effect​

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Answer 1
Answer:

Answer:

The inert pair effect is the tendency of the two electrons in the outermost atomic s-orbital to remain unshared in compounds of post-transition metals. The term inert pair effect is often used in relation to the increasing stability of oxidation states that are two less than the group valency for the heavier elements of groups 13, 14, 15 and 16. .[1] The name suggests that the outermost s electrons are more tightly bound to the nucleus in these atoms, and therefore more difficult to ionize or share


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What type of substance reacts with limestone (CaCO3) and produces carbon dioxide gas?

Answers

Acids react with calcium carbonate and more specifically carbonate to form carbon dioxide. An acid will give protons to the carbonate anion to produce carbonic acid which then decomposes into carbon dioxide and water. I hope this helps. Let me know if anything is unclear.

In a bid to produce CO2 from CaCO3 Heat energy and acids(H2SO4) reacts with limestone (CaCO3) and produce carbon dioxide gas(CO2).

What type of substance reacts with limestone (CaCO3) and produces carbon dioxide gas?

Generally, the equation for the Chemical Reaction  is mathematically given as,

CaCO3----->CaO +CO2

This is a decomposition reaction, it occurs when the reaction of heat energy reacts with CaCO3 in the atmosphere to produce CaO(s) +CO2(g).

Also

CaCO3(s) + H2SO4(aq) → CaSO4(s) + H2O(l) + CO2(g)

CaCO3 also reacts with acids to produce CO2 as shown in the balance equation above.

In conclusion, Acids and Heat energy reacts with limestone (CaCO3) and produce carbon dioxide gas.

Read more about Chemical Reaction

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Write a balanced equation for the reaction of NaCH3COO (also written as NaC2H3O2) and HCl.

Answers

The balanced equation is as follows:

\boxed{{\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}}

Further Explanation:

The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

Displacement reactions:

These reactions are also known as replacement or metathesis reactions. These types of reactions occur when one of the reactant is replaced by the other one. Usually the more reactive element displaces the less reactive element. Both metals and non-metals can take part in displacement reactions.

Such reactions are generally expressed as follows:

{\text{A}}+{\text{B}}-{\text{C}}\to{\text{A}}-{\text{C}}+{\text{B}}

Examples of displacement reactions are as follows:

(a) The reaction between copper metal and silver nitrate to form silver metal and copper nitrate as:

{\text{Cu}}+{\text{AgN}}{{\text{O}}_3}\to{\text{Ag}}+{\text{Cu}}{\left({{\text{N}}{{\text{O}}_3}}\right)_2}

(b) The reaction between chlorine gas and potassium bromide to form potassium chloride and bromine gas as:

{\text{C}}{{\text{l}}_2}+{\text{KBr}}\to{\text{B}}{{\text{r}}_2}+{\text{KCl}}

The steps to balance a chemical reaction are as follows:

Step1: Complete the reaction and write the unbalanced symbol equation.

In the displacement reaction, sodium acetate \left({{\text{NaC}}{{\text{H}}_3}{\text{COO}}}\right) reacts with hydrochloric acid \left({{\text{HCl}}}\right) to form NaCl and {\text{C}}{{\text{H}}_3}{\text{COOH}}. The physical state of {\text{NaC}}{{\text{H}}_3}{\text{COO}} , HCl, NaCl and {\text{C}}{{\text{H}}_3}{\text{COOH}}  is aqueous. The unbalanced chemical equation is as follows:

{\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}

Step2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

• On reactant side,

Number of sodium atom is 1.

Number of carbon atoms is 2.

Number of oxygen atoms is 2.

Number of hydrogen atom is 4

Number of chlorine atoms is 1.

• On product side,

Number of sodium atom is 1.

Number of carbon atoms is 2.

Number of oxygen atoms is 2.

Number of hydrogen atom is 4.

Number of chlorine atoms is 1.

Step3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side.

Sodium and chlorine atoms are balanced on both sides. Now the reaction is,

{\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms.

Carbon, hydrogen, and oxygen atoms are balanced on both sides. Now the reaction is,

{\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}

Step5: Finally, we check the number of atoms of each element on both the sides. If the number is same then the chemical equation is balanced.

The balanced chemical equation is as follows:

{\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Number of covalent bonds does nitrogen formed with its unpaired: brainly.com/question/5974553

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Balancing, displacement reaction, NaCl, CH3COOH, CH3COO, NaCH3COO, HCl, atoms, oxygen, carbon, hydrogen, chlorine.

The balance chemical equation is:

NaCH₃COO + HCl → NaCl + HCH₃COO

Make 

If 20.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 37.5 mL of 0.124 M HCl, what is the concentration of the Ca(OH)2 solution? Show all of the work needed to solve this problem. Ca(OH)2 + 2 HCl yields 2 H2 O + CaCl2

Answers

You first need to write the balanced chemical reaction for what is going on.
Ca(OH)₂+2HCl→2H₂O+CaCl₂

After you make the balanced chemical reaction, First you find the moles of HCl used.  To do this multiply 0.0375L by 0.124M to get 0.00465mol HCl.  Then you multiply 0.00465mol HCl by (1mol Ca(OH)₂)/(2mol HCl) to get 0.002325mol Ca(OH)₂.  Finally to find concentration of Ca(OH)₂ used you divide 0.002325mol by 0.020L to get 0.116M Ca(OH)₂.
Therefore the concentration of the unknown solution of Ca(OH)₂ was 0.116M.

I hope this helps.  Let me know if anything is unclear.

Which of the following is the largest contributor to the salt ions in the ocean?Select one of the options below as your answer:a. sodium
b. chloride
c. sulfates
d. calcium

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Option b: chloride.

The table salt is sodium chloride and oceans are rich in it.

In terms of molecular motion, why does an increase in pressure lead to an increased solubility of a gas?

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 We imagine a piston cylinder and a solution of gas and water. Molecules are in constant random motion and some of the gas particles are in the vapor phase while some in the liquid phase. At a specific volume, molecules move freely. However, when the piston is moved down, increasing the pressure, some of the molecules in the vapor are pushed down to the liquid phase in order maintain equilibrium thus increasing solubility 

48dm3 of a gas has a mass of 262g how many moles is this? What is the Mr? What must this element be?

Answers

n=(V)/(V_(0))\n\nV=48dm^(3)\nV_(0)=22.4(dm^(3))/(mol)\n\nn=(48dm^(3))/(22.4(dm^(3))/(mol))\approx2mol\n\nn=(m)/(M_(r)) \ \ \ \Rightarrow \ \ \ M_(r)=(m)/(n)\n\nm=262g\nn=2mol\n\nM_(r)=(262g)/(2mol)=131(g)/(mol)

This element must be xenon.

Final answer:

The number of moles is 1.49 and the molar mass is 176.124 g/mol.

Explanation:

To determine the number of moles, we can use the formula:



moles = mass / molar mass



Given that the mass of the gas is 262g and the molar mass is 176.124 g/mol, we can substitute these values into the formula:



moles = 262g / 176.124 g/mol = 1.49 moles (rounded to two decimal places).



Therefore, the number of moles is 1.49. The molar mass of the compound is 176.124 g/mol. In order to determine what element this is, we would need more information about the compound.

Learn more about molar mass here:

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