Which statement is true about points located in quadrant I in the coordinateplane?
A. The x-coordinate is negative, and the y-coordinate is negative.
B. The x-coordinate is positive, and the y-coordinate is positive.
C. The x-coordinate is positive, and the y-coordinate is negative.
O D. The x-coordinate is negative, and the y-coordinate is positive.
Please hurry

Answers

Answer 1

Answer:

The correct answer is B. The x-coordinate is positive, and the y-coordinate is positive, is true about points located in quadrant I in the coordinate plane.

We know that,

Quadrant I is the top-right quadrant of the Cartesian coordinate plane.

In this quadrant, both the x-coordinate and the y-coordinate are positive.

This means that the values of both the horizontal (x) and vertical (y) distances from the origin are increasing as you move to the right and upward from the origin.

Option A is incorrect because it states that both the x-coordinate and y-coordinate are negative, which is not true for points in Quadrant I.

Option C is incorrect because it states that the x-coordinate is positive and the y-coordinate is negative, which is not true for points in Quadrant I.

Option D is incorrect because it states that the x-coordinate is negative and the y-coordinate is positive, which is not true for points in Quadrant I.

Quadrant I is characterized by positive values for both the x-coordinate and the y-coordinate,

so the correct answer is Option B.

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Answer 2

Answer:

Step-by-step explanation:

In Quadrant I, both the x– and y-coordinates are positive; in Quadrant II, the x-coordinate is negative, but the y-coordinate is positive; in Quadrant III both are negative; and in Quadrant IV, x is positive but y is negative.

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0.4p – 5 = 0.08p + 3
Solve pls

Answers

Hey there!

ANSWER: $p=25$

EXPLANATION:

$0.4p-5=0.08p+3$

To solve this inequality, we will need to subtract 0.08p from both sides of the inequality.

$0.4p-5-0.08p=0.08p+3-0.08p\n0.32p-5=3$

Now we have to add both sides by 5.

$0.32p-5+5=3+5\n0.32p=8$

In our last step, we will have to divide both sides by 0.32.

$(0.32p)/(0.32) =(8)/(0.32)\n25\n\text{25 is your answer.}$

Hope this helps!

$\text{-TestedHyperr}$

Answer:

p=25

Step-by-step explanation:

Look at the answer above.

Which of the following is a simplified form of the expression -2(x - 9) - x?

Answers

Answer:

-3x+18

Step-by-step explanation:

Distribute -2 through the parenthesis

-2x+18-x

Collect the like terms

-3x+18

What is f ( 1/3)? When the function is f(x) =-3x+7

Answers

Answer:

f(1/3) = 6

Step-by-step explanation:

f(x) =-3x+7

Let x = 1/3

f(1/3) =-3*1/3+7

= -1 +7

= 6

Answer:

f(1/3) = 6

Step-by-step explanation:

The function is:

● f(x) = -3x+7

Replace x by 1/3 to khow the value of f(1/3)

● f(1/3) = -3×(1/3) +7 = -1 +7 = 6

-5+i/2i how do I break this down?

Answers

Answer:

i2 = -1

Step-by-step explanation:

5i ⋅i⋅(−2i)= −

10 ⋅ i2 ⋅ i= − 10 ⋅ (−1) ⋅ i = 10i

A cube-shaped water tank having 6 ft side lengths is being filled with water. The bottom is solid metal but the sides of the tank are thin glass which can only withstand a maximum force of 200 lb. How high (in ft) can the water reach before the sides shatter?(Assume a density of water rho = 62.4 lb/ft3.
Round your answer to two decimal places.)

Answers

The distance the in which the water will reach before it shatters will be 1.03ft

Data;

Let the integral run from surface (y = 0) to maximum depth (y = d)ft
Let the differential depth = dydt
The area of each depth = 6dy ft^2

The Force Acting at any Depth

Using integration, the force at any depth y is 62.4y lb/ft^3

$200 = \int\limits^d_0 {62.4y} \, 6dy\n 200 = \int\limits^d_0 {374.4y} \, dy\n 200 = \int\limits^6_0 {374.4y} \, dy\n 200 = [374.4/2 y^2]_0^d\n200 = 187.2(d^2 - 0)\n200 = 187.2d^2\nd^2 = 200/187.2\nd = 1.03ft$