CHEMISTRY COLLEGE

Which of the following shows the combustion of a hydrocarbon?A. 2C2H2 +502 + 4CO2 + 2H20
O B. CO2 + H2O → H2CO3
O C. NaOH + HCl → NaCl + H20
O D. C2H4 + Cl2 → C2H4Cl2

Answers

Answer 1
Answer:

The chemical equation 2 C₂H₂ +5 O₂ + 4 CO₂ + 2 H₂O is the equation which represents the combustion of a hydrocarbon.

What is a chemical equation?

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

Learn more about chemical equation,here:

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Answer 2
Answer:

Answer:

a

Explanation:

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Isopropyl methyl ether is slightly soluble with water because the oxygen atom of ethers with three or fewer carbon atoms can form a few hydrogen bonds with water.(A) True(B) False

A geochemist in the field takes a 36.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 170 C, and caps the sample carefully. Back in the lab, the geochemist first dilutes the sample with distilled water to 500. mL. Then he filters it and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 3.96 g.Using only the information above, can you calculate yes the solubility of X in water at 17.0 C? If you said yes, calculate it.

Answers

Answer:

solubility of X in water at 17.0 ^(0)\textrm{C} is 0.11 g/mL.

Explanation:

Yes, the solubility of X in water at 17.0 ^(0)\textrm{C} can be calculated using the information given.

Let's assume solubility of X in water at 17.0 ^(0)\textrm{C} is y g/mL

The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.

So, solubility of X in 1 mL of water = y g

Hence, solubility of X in 36.0 mL of water = 36y g

So, 36y = 3.96

   or, y = (3.96)/(36) = 0.11

Hence solubility of X in water at 17.0 ^(0)\textrm{C} is 0.11 g/mL.

.......state Hess law​

Answers

Hess's Law of Constant Heat Summation (or just Hess's Law) states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes. This law is a manifestation that enthalpy is a state function.

Iron has density of 7.9g/cm3. What is the mass of a cube with the length of one side equal to 1.64x10squared cm3?

Answers

Given data:

Density of iron (Fe) = 7.9 g/cm3

Length of one side of the iron cube = 1.64 * 10^2 cm

Now, the volume (V) of a cube in which the length of the side is 'a' cm is given as:

V = a^3

Volume of iron cube = (1.64 *10^2 cm)^3 = 4.41 * 10^6 cm3

The density (D) of an object of mass (m) and volume (V) is given as:

D = m/V

or, m = D*V

Therefore, mass of iron cube = 7.9 g/cm3 * 4.41 * 10^6 cm3

                                                = 34.84 *10^6 g

What is the mass in grams of H₂ that can be formed from 54.6 grams of NH₃ in the following reaction?2 NH₃(g) → 3 H₂(g) + N₂(g)

Answers

9.6 grams of H₂ can be formed from 54.6 grams of NH₃ in the following reaction: 2NH₃(g) → 3H₂(g) + N₂(g).

  • According to this question, the following balanced equation is given: 2NH₃(g) → 3H₂(g) + N₂(g).

  • First, we convert the mass of ammonia (NH3) to moles as follows:

  • moles of NH3 = 54.6g ÷ 17g/mol

  • moles of NH3 = 3.2mol.

  1. If 2 moles of NH3 produces 3 moles of H2.
  2. 3.2 moles of NH3 will produce 4.8 moles of H2.

  • Next, we convert 4.8moles of H2 to mass as follows:

  • mass of H2 = 4.8 × 2

  • mass of H2 = 9.6g of H2.

  • Therefore, 9.6 grams of H₂ can be formed from 54.6 grams of NH₃ in the following reaction: 2NH₃(g) → 3H₂(g) + N₂(g).

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Answer : The mass of H_2 is, 9.64 grams.

Explanation : Given,

Mass of NH_3 = 54.6 g

Molar mass of NH_3 = 17 g/mol

Molar mass of H_2 = 2 g/mol

First we have to calculate the moles of NH_3.

\text{Moles of }NH_3=\frac{\text{Given mass }NH_3}{\text{Molar mass }NH_3}

\text{Moles of }NH_3=(54.6g)/(17g/mol)=3.21mol

Now we have to calculate the moles of H_2

The balanced chemical equation is:

2NH_3(g)\rightarrow 3H_2(g)+N_2(g)

From the balanced reaction we conclude that

As, 2 mole of NH_3 react to give 3 moles of H_2

So, 3.21 mole of NH_3 react to give (3)/(2)* 3.21=4.82 mole of H_2

Now we have to calculate the mass of H_2

\text{ Mass of }H_2=\text{ Moles of }H_2* \text{ Molar mass of }H_2

\text{ Mass of }H_2=(4.82moles)* (2g/mole)=9.64g

Therefore, the mass of H_2 is, 9.64 grams.

A ______________________ is required to cause atoms to bond together or be separated from one another. *a physical change
b phase change
c radioactive decay
d chemical reaction

Answers

Answer:

d chemical reaction..

The speed of light is 3.00×108m/s. How long does it take for light to travel from Earth to the Moon and back again?

Answers

The variable we have to determine for this problem is the time. Since the given information is speed, we have to know the distance so that we can solve for the time. From literature, the distance between the Earth and the moon is 384,400,000 meters. Therefore,

Speed = Distance/Time
Time = Distance/Speed
Time = 384,400,000 m/ 3×10⁸ m/s = 1.28 seconds
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