Calculate the force between one grapefruit as described above and Earth. Earth has a mass of5.9742 × 1024 kg and a radius of 6.3710 × 106 meters. Assume the grapefruit is resting on Earth’s surface.

Answers

Answer 1
Answer: the formula is G=mass(1)x mass(2)
                         -------------------------------
                         6.67x10x-11

note that 10x-11 is in standard form but i could not write it. It is 10 raised to power negative 11


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Which example involves the transformation of chemical energy directly into light energy? A) a wind mill
Reactivate

B) a glow stick
C) photosynthesis
D) a hydroelectric dam

Answers

The question involves the concepts of chemical energy, light energy and energy conversion.

The example which involves the transformation of chemical energy directly into light energy is "B) a glow stick".

A)

In a windmill, the input energy is the wind energy, and that wind energy is then converted to mechanical energy when the rotor blades rotatae. That mechanical energy is then converted to electrical energy. This electrical energy is then used in lamps to get light energy. Hence, the chemcial energy is not directly transformed into light energy in the windmill.

B)

A glow stick uses the chemical energy from the chemicals inside it to produce luminance in the form of light energy. When the stick is bent or broken, it releases the chemicals inside it which undergo a chemical reaction that leads to the conversion of chemical energy into light energy.

C)

During photosynthesis, light energy is used by plants to produce oxygen and energy in the form of sugar (glucose).

D)

A hydroelectric dam receives mechanical energy from water. The gravitational potential energy of water due to its height is converted into kinetic energy when it reaches the turbine. This kinetic energy is then converted to electrical energy.

Hence, the only example where chemical energy is directly converted to light energy is Glow Stick.

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The attached picture shows different energy conversions.

a glow stick because when you crack it in the dark it turns into a light that works in the dark

Help me on this question? log x-log 9=1

Answers

\log { x } -\log { 9 } =1\n \n \log { \left( \frac { x }{ 9 }  \right)  } =1\n \n \log _( 10 ){ \left( \frac { x }{ 9 }  \right)  } =1\n \n { 10 }^( 1 )=\frac { x }{ 9 } \n \n 9\cdot 10=x\n \n x=90

This is because:

\log _( a ){ \left( \frac { x }{ p }  \right)  } \n \n =\log _( a ){ \left( \frac { { a }^( m ) }{ { a }^( n ) }  \right)  } \n \n =\log _( a ){ \left( { a }^( \left( m-n \right)  ) \right)  } \n \n =\left( m-n \right) \cdot \log _( a ){ a } \n \n =m-n\n \n =\log _( a ){ x } -\log _( a ){ p } \n

   log(x) - log(9) = 1

Subtracting the logs of numbers gives you the log of
the quotient of the numbers.

     Log(x) - log(9)  is the log of  (x/9).

So the equation says:    log (x/9) = 1

Raise 10 to the power of each side:  10^(log of x/9) = 10^1

But  10^(log of x/9) is x/9, and 10^1 is 10.

So        x/9 = 10

             x  =  90

Which one of the following lines best illustrates personification? A.She floated graceful as a dove

B.Spring is a dream unsung

C.A narrow wind complains all day

D.The fog comes on little cat feet

Answers

C. A narrow wind complains all day.

Personification is a figure of speech wherein animals, objects, and ideas are given human traits or characteristics.

The narrow wind, which is an unseen object, was given a human trait which is complains.

The lines that best illustrates personification is (D), The fog comes on little cat feet.

What is personification?

Personification is a literary device where inanimate objects are given human qualities. In the line "The fog comes on little cat feet," the fog is given the human qualities of walking and having feet. This is a clear example of personification.

The other lines do not illustrate personification. In line A, "She floated graceful as a dove," the dove is being compared to a graceful woman, but the dove is not being given any human qualities. In line B, "Spring is a dream unsung," spring is being compared to a dream, but spring is not being given any human qualities. In line C, "A narrow wind complains all day," the wind is being compared to a person who is complaining, but the wind is not being given any human qualities.

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A puck moves 2.35 m/s in a -22° direction. A hockey stick pushes it for 0.215 s, changing its velocity to 6.42 m/s in a 50.0° direction. What was the direction of the acceleration?

Answers

The puck starts with velocity vector

\vec v_0=\left(2.35(\rm m)/(\rm s)\right)(\cos(-22^\circ)\,\vec\imath+\sin(-22^\circ)\,\vec\jmath)=(2.18\,\vec\imath-0.880\,\vec\jmath)(\rm m)/(\rm s)

Its velocity at time t is

\vec v=\vec v_0+\vec at

Over the 0.215 s interval, the velocity changes to

\vec v=\left(6.42(\rm m)/(\rm s)\right)(\cos50.0^\circ\,\vec\imath+\sin50.0^\circ\,\vec\jmath)=(4.13\,\vec\imath+4.92\,\vec\jmath)(\rm m)/(\rm s)

Then the acceleration must have been

\vec v=\vec v_0+(0.215\,\mathrm s)\vec a\implies\vec a=(\vec v-\vec v_0)/(0.215\,\rm s)=(9.06\,\vec\imath+27.0\,\vec\jmath)(\rm m)/(\mathrm s^2)

which has a direction of about 71.4^\circ.

Final answer:

The direction of the acceleration is determined by the direction of the change in velocity. This would be calculated by subtracting the initial velocity vector from the final velocity vector. However, the calculation would involve complex trigonometric functions.

Explanation:

In order to find the direction of the acceleration, we need to calculate the direction of the change in velocity and that direction will be the direction of the acceleration.

To calculate the change in velocity, we subtract the initial velocity from the final velocity: (6.42 m/s, 50.0°) - (2.35 m/s, -22°). We then calculate the angle of this vector which represents the change in velocity, and hence the direction of acceleration.

However, this calculation is not straightforward because it involves vector operations and would require the use of trigonometric functions to solve. This is due to the fact that velocity is a vector, meaning it has both a magnitude and a direction. Consequently, this becomes a multi-step process involving trigonometry and physics.

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What is the average speed of a cheetah that runs 70m in 2.5 seconds?

Answers

70m\ in\ 2.5\ seconds\n V=(s)/(t)\n V=(70m)/(2.5s)\n V=28(m)/(s)

How would you characterize the flame test with respect to its sensitivity

Answers

Answer:

Flame test is the procedure to find out the metal ions in the ionic compounds. By observing the color of flame we find out the presence of certain metallic ion. For example if we take the test of copper halide, the flame will become of the bluish green color due to the copper ion. You can perform the test with the common salt. Upon putting it on the flame, the color of flame will become yellow due to the presence of sodium ion. Similarly aluminium shows blue and calcium brick red etc.

Explanation:

Final answer:

The flame test, used in chemistry to identify certain substances through the color of their flame, has limited sensitivity, as some elements produce similar flame colors and multiple elements in a sample can complicate interpretation. Still, it remains a valuable tool in qualitative analysis. Other assessments, such as the NFPA 704 Hazard Identification System, can help understand the reactiveness and flammability of substances.

Explanation:

Characterizing the flame test with respect to its sensitivity involves understanding the minimal amount of a compound that the test can detect. Just like our senses have an absolute threshold for detection, so does the flame test. It can identify the presence of various elements in a compound based on the color of the flame. For example, sodium and its compounds impart a bright yellow color to a flame whereas lithium creates a bright, crimson color.

Despite its usefulness, the flame test may not be the most sensitive method for substance identification. Some elements may produce similar flame colors, making it difficult to distinguish between them. Moreover, the presence of multiple elements in a sample can also complicate the interpretation of flame test results. Therefore, while the flame test is a valuable tool in qualitative analysis, its sensitivity is somewhat limited.

According to the National Fire Protection Agency (NFPA) 704 Hazard Identification System, each substance has its own degree of hazard that ranges from 0 to 4. This information is critical in understanding the reactivity and flammability of substances, and is another aspect to consider when characterizing the sensitivity of the flame test.

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