Dawn is trying to find out how much weight she can push across the room. She is really trying to find her

Answers

Answer 1

Answer:

Dawn is trying to figure out how much weight she can push with her strength, or what her maximum pushing force is, across the room. She could do an experiment to find out.

She must first prepare a testing space with a flat, smooth surface to reduce friction. She can then progressively add weights to a cart or other object and use all of her strength to try to push it across the room. She can determine her maximum pushing force by noting the heaviest weight she can move. For a variety of jobs, including moving furniture or participating in physical sports that call for pushing heavy things, this knowledge can be essential.

To know more about physical sports, here

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Answer 2

Answer:

Muscular strength

Explanation:

She is testing her strength while pushing the weights

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A car turns from a road into a parking lot and into an available parking space. The car’s initial velocity is 4 m/s [E 45° N]. The car’s velocity just before the driver decreases speed is 4 m/s [E 10° N]. The turn takes 3s. What's the average acceleration of the car during the turn? The answer should have directions with an angle.
Suppose you left a 100-W light bulb on continuously for one month. If the electricity generation and transmission efficiency is 30%, how much chemical energy (in joules) was wasted at the power plant for this oversight? If the fuel consumption for one meal in Cambodia using a kerosene wick stove is 6 MJ (1 MJ = 1,000,000 joules), how many equivalent meals could be cooked with this wasted energy.
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A grandfather clock keeps time using a pendulum consisting of a light rod connected to a small heavy mass. With a rod of length L, the period of oscillation is 2.00 s. What should the length of the rod be for the period of the oscillations to be 1.00 s?

Answers

Answer:

The length of the rod should be

$(L)/(4) \n$

Explanation:

Period of simple pendulum is given by

$T=2\pi\sqrt{(l)/(g)} \n$

We have

$(T_1^2)/(T_2^2)=(l_1)/(l_2)\n\n(2^2)/(1^2)=(L)/(l_2)\n\nl_2=(L)/(4) \n$

The length of the rod should be

$(L)/(4) \n$

A positive magnification means the image is inverted compared to the object

Answers

False

Explanation:

A positive magnification means the image is erect compared to the object. Magnifications with values greater than one represent images that are smaller than the object. A magnification of 1 (plus or minus) means that the image is the same size as the object. If m has a magnitude greater than 1 the image is larger than the object, and an m with a magnitude less than 1 means the image is smaller than the object. If the magnification is positive, the image is upright compared to the object; if m is negative, the image is inverted compared to the object.

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. Unfortunately the archer stands on an elevated platform of unknown height. However, you find the arrow stuck in the ground 67.0 m away, making a 3.00 ∘ angle with the ground.How fast was the arrow shot?

Answers

To develop this problem it is necessary to apply the kinematic equations that describe displacement, velocity and clarification.

By definition we know that velocity is defined as the change of position due to time, therefore

$V = (d)/(t)$

Where,

d = Distance

t = Time

Speed can also be expressed in vector form through its components $V_x$ and $V_y$

In the case of the horizontal component X, we have to

$V_x = (d)/(t)$

Here d means the horizontal displacement, then

$t = (d)/(V_x)$

$t = (67)/(V_x)$

At the same time we have that the vertical component of the velocity is

$V_y = gt$

Here,

g = Gravity

Therefore using the relation previously found we have that

$V_y = g (67)/(V_x)$

The relationship between the two velocities and the angle can be expressed through the Tangent, therefore

$tan\theta = (V_y)/(V_x)$

$tan \theta = (g (67)/(V_x) )/(V_x)$

$tan 3 = (9.8(67)/(V_x) )/(V_x)$

$tan 3 = (9.8*67)/(V_x^2)$

$V_x^2 = (9.8*67)/(tan 3)$

$V_x= \sqrt{ (9.8*67)/(tan 3)}$

$V_x = 111.93m/s \hat{i}$

This is the horizontal component, we could also find the vertical speed and the value of the total speed with the information given,

Then $V_y,$

$V_y = g (67)/(V_x)$

$V_y = 9.8*(67)/(111.93)$

$V_y = 5.866m/s\hat{j}$

$|\vec{V}| = √(111.93^2+5.866^2)$

$|\vec{V}| = 112.084m/s$

A local ice hockey pond is at 4°C when the air temperature falls, causing the water temperature to drop to 0°C with 10.9 cm of ice forming at the surface at a temperature of 0°C. How much heat was lost if the unfrozen pond is 1 m deep and 50 m on each side?

Answers

Answer: 114.4 GJ

Explanation:

Heat loss Q=U×A×ΔT

Heat loss of size A is determined by the U value of materials and the difference in temperature.

From 10.9cm from the ice

50m= 5000cm

A= 5000×5000

Q== (10.9) (5000) (5000)(4.184)(1×4 + 80)

Q = 95,771,760,000J

Q≈ 95.8 GJ

Linear gradient from the bottom of the pond to the ice:

Q = (89.1)(5000)(5000)(4.184)(1*2)

Q = 18,639,720,000J

Q ≈ 18.6 GJ

Total heat loss:

Q= 95.8GJ + 18.6GJ

Q= 114.4 GJ

Much of our knowledge of the interior of the Earth comes from the study of planetary vibrations, which is the science of

Answers

Answer:

Seismology.

Explanation:

Seismology is the beach of physical science that deals with the study of vibrations that comes out from the interior of the earth onto the surface and these vibrations are in the form of seismic waves that are primary, secondary, and surface waves.

The science of seismology tells about the magnitude and intensity of these waves that lead to planetary vibrations. These waves trigger earthquakes, floods, and even landslides.

Why is there so much more carbon dioxide in the atmosphere of Venus than in that of Earth? Why so much more carbon dioxide than on Mars?

Answers

Explanation:

The reason for the more concentration of carbon dioxide in the atmosphere of Venus than in the Earth -

On the Earth , most amount of the carbon dioxide is in the ocean water and in sea sediments .

Considering Venus , in the planet Venus , there is no Ocean water , hence , carbon dioxide can not get dissolved into the water , hence , it is found in the atmosphere .

So , the escape velocity for carbon dioxide on Mars is smaller than Venus .

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