MATHEMATICS HIGH SCHOOL

To get into the carnival, it costs $5. Then each ride costs $2.25. *Use a linear equation to solve the following:If you brought $35, how many rides can you go on?
How much would it cost altogether to ride 7 rides?

Answers

Answer 1

Answer:

Answer:

equation: y=2.25x+5

a: 13 rides

b:$20.75 for 7 rides

explanation:

a: 35=2.25x+5

first subtract 5 from 5 and 35

30=2.25x

divide each side by 2.25

x= 13 1/3

can only go on 13 rides

b: y=2.25(7)+5

2.25×7=15.75

15.75+5=20.75

$20.75 for 7 rides

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Compare partial products and regrouping how the methods are alike and different

Answers

Partial products are different in regrouping in terms of how numbers are clustered from a set equation as a whole delivering it individual but naturally to all the numbers involved in the set.
Regrouping is just like the commutative or associative property of numbers.
Associative property of addition is used when you want to group addends. This is mainly used to cluster set of numbers or in this case, addends. How do you use the associative property when you break apart addends? Simple you group them using the open and closed parentheses or brackets. Take for an example 1 + 1 + 2 = 4. Using the associative property you can have either (1 + 1) + 2 = 4 or 1 + (1 + 2) = 4 clustered into place.

What are the solutions to the quadratic equation x2 – 16 = 0?x = 2 and x = –2
x = 4 and x = –4
x = 8 and x = –8
x = 16 and x = –16

Answers

The correct statement is that the solution of this equation x² – 16 = 0, is 4 and -4.

What is a quadratic equation?

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation. The general form of the quadratic equation is ax² + bx + c = 0

Given

The quadratic equation x² – 16 = 0

To find

The root of the quadratic equtaion?

How do find the solutions to the quadratic equation?

The quadratic equation x² – 16 = 0

We know the formula,

a² - b² = ( a - b ) ( a + b )

Then

x² – 4² = 0

(x - 4)(x + 4) = 0

x = 4 and -4

Thus, the solution of this equation x² – 16 = 0, is 4 and -4.

More about the quadratic equation link is given below.

brainly.com/question/2263981

Answer: The correct option is (B) x = 4 and x = -4.

Step-by-step explanation: We are given to find the solutions to the following quadratic equation :

$x^2-16=0~~~~~~~~~~~~~~~~~~~~~(i)$

Since the coefficient of x is zero in the given equation, so we will be using the method of square root to solve the equation.

From equation (i), we have

$x^2-16=0\n\n\Rightarrow x^2=16\n\n\Rightarrow x=\pm√(16)~~~~~~~\textup{[taking square root on both sides]}\n\n\Rightarrow x=\pm4\n\n\Rightarrow x=4,~-4.$

Thus, the required solution is x = 4 and x = -4.

Option (B) is correct.

Is 3 liters per 60 seconds a unit rate

Answers

No its not a unit rate

"Mia jogs 3 kilometers in 20 minutes. There are about 0.6 miles in a kilometer. What is Mia’s approximate speed in miles per minute?A. 0.25 miles per minute
B. 0.09 miles per minute
C. 4 miles per minute
D. 11 miles per minute"

Answers

First we need to find Mia's speed (v) in km/min

v = distance travelled/ time
v = 3 km/20 minutes
v = 0.15 km /min

in order to convert the speed into mile/min, we need to use the conversion factor given in which for every kilometer, there is 0.6 miles.

v = 0.15 km/min *(0.6 miles/ km)
v =0.09 miles/min

therefore the speed in miles/min is 0.09 miles/min

Answer:

Step-by-step explanation:

I smartest I'm know its B

In accordance with 14 CFR Part 107, at what maximum altitude can you operate an sUAS when inspecting a tower with a top at 1,000 ft AGL at close proximity (within 100 feet)?

Answers

Answer:

The max altitude you can operate an sUAS on these given conditions is 1400ft AGL.

Step-by-step explanation:

A single-cell amoeba doubles every 3 days. how long would it take on amoeba to produce a population of about 10,000 amoebae?

Answers

2^n=10,000
2^14=10,000
d=3n
d=3(14)
d=42

d=days
n=number of times of reproduction

Final answer:

It would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.

Explanation:

To find out how long it would take for a single-cell amoeba to produce a population of about 10,000 amoebae, we need to calculate the number of times the amoeba doubles. Since the amoeba doubles every 3 days, we can find out the number of doubling periods it would take to reach 10,000 amoebae by dividing 10,000 by 2. This equals approximately 9.965, which means the amoeba would need to double about 9.965 times. Since we can't have a fraction of a doubling period, we can round it up to 10.

Each doubling period is 3 days, so to find out how long it would take, we can multiply the number of doubling periods (10) by the time interval for each doubling period (3 days). 10 x 3 = 30. Therefore, it would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.