MATHEMATICS HIGH SCHOOL

There are three consecutive odd integers so that twice the largest of the three is 6 more than the sum of the other two. Find all three consecutive odd integers.

Answers

Answer 1

Answer:

Step-by-step explanation:

ur answer....here u gi

Answer 2

Answer:

Final answer:

The question asks for three consecutive odd numbers under a specified condition. After creating and solving an equation based on the given conditions, we find the numbers to be 5, 7, and 9.

Explanation:

We are given that there are three consecutive odd integers that follow a certain rule. Let's denote the smallest of these three numbers as x. Because the numbers are consecutive and odd, the next two numbers will be x + 2 and x + 4.

The problem states that twice the largest of the three numbers (2*(x+4)) is 6 more than the sum of the other two numbers (x + (x + 2)). In equation form, this is: 2*(x+4) = (x + x + 2) + 6.

Solving for x, we find that x = 5. So, the three consecutive odd numbers are 5, 7, and 9, which meet the conditions provided in the problem.

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Marking as Brainiest!!!!!

12 less than one-eleventh of some number, w"

Answers

The required number is 132.

It is required to find the number.

What is arithmetic?

Arithmetic is the branch of mathematics that deals with the study of numbers using various operations on them. Basic operations of math are addition, subtraction, multiplication and division. These operations are denoted by the given symbols.

Given:

According to given question we have,

Let the number be x.

1/11w - 12

1/11w-12=0

Add 12 both sides we get,

1/11w-12+12=0+12

1/11w=12

w = 132

Therefore, the required number is 132.

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Let w be the number.

1/11w - 12

1/11w-12=0

1/11w-12+12=0+12

1/11w=12

1/11w÷1/11=12÷1/11

w = 132

Therefore, the equation would be 1/11w - 12 and the value of w is 132.

Help solve mathematics question, please. Photo.

Answers

the correct answer is (8,5)
i hope that i have helped today

What does creditworthiness mean?A.) the ability to mortgage a house
B.) the ability to repair bad credit
C.) the ability to repair a debt

Answers

Creditworthiness is the ability to repair a debt.

Option C is the correct answer.

What is creditworthiness?

Creditworthiness is a valuation performed by lenders that tells about the borrower on his debtobligations such as repayment history and credit score.

We have,

Creditworthiness means a person's suitability to receive financial credit based on the reliability of giving back the financial credit in time in the past.

So,

Creditworthiness can also be said as the ability to repair a debt.

Thus,

Creditworthiness is the ability to repair a debt.

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Creditworthiness is a valuation performed by lenders that determines the possibility a borrower may default on his debt obligations. It's basically a measure of your credit. So I would assume it would be C) The ability to repair a debt

253, 248 ,243 find the 49th term

Answers

Answer:

Step-by-step explanation:

253 , 248 243 238 233 228 223 218 213 208 203 198 193 188 183 178 173 168 163 158 153 148 143 138 133 128 123 118 113 108 103 98 93 88 83 78 73 68 63 58 53 48 43 38 33 28 23 18 13 i

ts 13 i think
i just counted down ^^

To find the 49th term of the sequence 253, 248, 243, ... , we notice that the sequence is decreasing by 5 each time. This is an arithmetic sequence with a common difference of -5.

We use the formula for the nth term of an arithmetic sequence, which is:
nth term = first term + (n - 1) * common difference

Here, the first term is 253, the common difference is -5, and we're looking for the 49th term.

Plug these into the formula:
49th term = 253 + (49 - 1) * -5
49th term = 253 + 48 * -5
49th term = 253 - 240
49th term = 13

So, the 49th term of the sequence is 13.

Find the greatest common factor (GCF) for 72, 36, and 24.

Answers

12

Working;
12 is a common factor for all the terms.

The graph of which function has an axis of symmetry at x =-1/4 ?f(x) = 2x2 + x – 1

f(x) = 2x2 – x + 1

f(x) = x2 + 2x – 1

f(x) = x2 – 2x + 1

Answers

we know that

The equation of the vertical parabola in vertex form is equal to

$y=a(x-h)^(2)+k$

where

(h,k) is the vertex

The axis of symmetry is equal to the x-coordinate of the vertex

$x=h$ ------> axis of symmetry of a vertical parabola

we will determine in each case the axis of symmetry to determine the solution

case A) $f(x)=2x^(2)+x-1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+1=2x^(2)+x$

Factor the leading coefficient

$f(x)+1=2(x^(2)+0.5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+1+0.125=2(x^(2)+0.5x+0.0625)$

$f(x)+1.125=2(x^(2)+0.5x+0.0625)$

Rewrite as perfect squares

$f(x)+1.125=2(x+0.25)^(2)$

$f(x)=2(x+0.25)^(2)-1.125$

the vertex is the point $(-0.25,-1.125)$

the axis of symmetry is

$x=-0.25=-(1)/(4)$

therefore

the function $f(x)=2x^(2)+x-1$ has an axis of symmetry at $x=-(1)/(4)$

case B) $f(x)=2x^(2)-x+1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-1=2x^(2)-x$

Factor the leading coefficient

$f(x)-1=2(x^(2)-0.5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-1+0.125=2(x^(2)-0.5x+0.0625)$

$f(x)-0.875=2(x^(2)-0.5x+0.0625)$

Rewrite as perfect squares

$f(x)-0.875=2(x-0.25)^(2)$

$f(x)=2(x-0.25)^(2)+0.875$

the vertex is the point $(0.25,0.875)$

the axis of symmetry is

$x=0.25=(1)/(4)$

therefore

the function $f(x)=2x^(2)-x+1$ does not have a symmetry axis in $x=-(1)/(4)$

case C) $f(x)=x^(2)+2x-1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+1=x^(2)+2x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+1+1=x^(2)+2x+1$

$f(x)+2=x^(2)+2x+1$

Rewrite as perfect squares

$f(x)+2=(x+1)^(2)$

$f(x)=(x+1)^(2)-2$

the vertex is the point $(-1,-2)$

the axis of symmetry is

$x=-1$

therefore

the function $f(x)=x^(2)+2x-1$ does not have a symmetry axis in $x=-(1)/(4)$

case D) $f(x)=x^(2)-2x+1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-1=x^(2)-2x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-1+1=x^(2)-2x+1$

$f(x)=x^(2)-2x+1$

Rewrite as perfect squares

$f(x)=(x-1)^(2)$

the vertex is the point $(1,0)$

the axis of symmetry is

$x=1$

therefore

the function $f(x)=x^(2)-2x+1$ does not have a symmetry axis in $x=-(1)/(4)$

the answer is

$f(x)=2x^(2)+x-1$

axis of symmetry is the x value of the vertex

for
y=ax^2+bx+c
x value of vertex=-b/2a

first one
-1/2(2)=-1/4
wow, that is right

answer is first one
f(x)=2x^2+x-1

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