11 The net force on a vehicle that is accelerating at a rate of 1.5 m/s² is 2,800 newtons. What isthe mass of the vehicle to the nearest kilogram?

Answers

Answer 1
Answer:

Answer:

Mass = 1867kg

Step-by-step explanation:

Given

Force = 2800N

Acceleration = 1.5m/s^2

Required

Determine the mass of the vehicle

This question will be answered using Newton's second law

Force = Mass * Acceleration

Substitute values for Force and Acceleration

2800 = Mass * 1.5m/s^2

Make Mass the subject

Mass = (2800N)/(1.5m/s^2)

Mass = 1866.6667kg

Mass = 1867kg ---- approximated

Hence, the mass of the vehicle is 1867kg


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A segment has endpoints A (-1, 1) and B (8, 4) .If the segment is divided into four equal parts, the coordinates of the point closest to point A are _____?

Answers

Answer:

fafafsghdjdbdbdgsysvdve. wwmsk

Which procedure would you use to convert a fraction to a decimal?1
Convert to a decimal.
5
to a decimal?

Answers

Answer: Since 1 is a natural number, there is a decimal in every number in history. It is invisible, but that is only because we don't put decimals if it is not needed. But the decimal on the number always exists. Therefore, 1 in a decimal is 1.0. Same with 5. 5 is also written as 5.0.

Hope this helps!

Mr. Cole made this diagram of his bedroom. Which is the area of Mr. Cole’s bedroom? 90 square feet 82 square feet 72 square feet 36 square feet

Answers

The area of Mr. Cole’s bedroom is82 square feet. Therefore, the correct answer is option B.

Area is the amount of space occupied by a two-dimensional figure. In other words, it is the quantity that measures the number of unit squares that cover the surface of a closed figure. The standard unit of area is square units which is generally represented as square inches, square feet, etc.

The given figure can be divided into two rectangles.

One with the dimensions 10 ft by 5 ft.

Other with the dimensions 8 ft by 4t.

We know that, the area of a rectangle is Length×Width.

Here, area of a rectangle with the dimensions 10 ft by 5 ft is

10*5=50 square feet

Area of a rectangle with the dimensions 8 ft by 4 ft is

8*4=32 square feet

Now, area = 50+32

= 82 square feet

Therefore, the correct answer is option B.

Learn more about the area here:

brainly.com/question/27683633.

#SPJ3

Answer:

The answer is 82 square feet

Step-by-step explanation:

An easy way to do this is to split it into two rectanlges. You can do 10*5 and 8*4 as the dimensions to the two rectangles or you can do 2*4 and 9*8.

I am going to do the first option.

The area of a rectangle is length times width.

Rectangle one can be the one with the dimensions 10 and 5 and the length and width.

Rectangle two can be the one with the dimensions 8 and 4 and the length and width.

Area of rectangle one = 50 feet^2

Area of rectangle two = 32 feet^2

Since we split a large irregular shape into two bits, we must add them together, which results in 82 feet^2.  

Solve (3x+7)=4x for x

Answers

Answer:

x=7

Step-by-step explanation:

(3x+7)=4x

Subtract 3x from each side

(3x+7) -3x=4x-3x

7 = x

Which of the following is equivalent to 2 2/5​

Answers

Answer:

0.4 - 0.40 - 4/10 -

Step-by-step explanation:

On an intramural softball team, the proportion of hits to at bats for the entire team during the last season was 30% of 300 attempts. Estimate the true proportion of hits using a 90% CI. The answers need to be proportions (not percents) and rounded to the nearest hundredth (two (2) decimal places) to be counted as correct. (For example, if my CI is (0.1002, 0.2159) then they need to be input as 0.10 and 0.22 to be correct. **These are not the answers to this question :-) **)The lower bound is____ and the upper bound is ____

Answers

Answer: The lower bound is 0.26 and the upper bound is 0.34.

Step-by-step explanation:

Formula to find the confidence interval for population proportion (p) is given by :_

\hat{p}\pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

, where n= sample size

z* = Critical value. (two-tailed)

\hat{p} = Sample proportion.

Let p be the true population proportion of hits to at bats for the entire team during the last season.

As per given , we have

n= 300

\hat{p}=0.30

By z-table , the critical value for 90% confidence interval : z* = 1.645

Now , 90% confidence interval for the proportion of hits to at bats for the entire team during the last season:

0.30\pm (1.645) \sqrt{(0.30(1-0.30))/(300)}

0.30\pm (1.645) √(0.0007)

0.30\pm (1.645) (0.0264575131106)

\approx0.30\pm0.0435

=(0.30-0.0435,\ 0.30+0.0435)\n\n=(0.2565,\ 0.3435)\approx(0.26,\ 0.34)

The lower bound is 0.26 and the upper bound is 0.34.