Please answer quick in need of an answer

Answers

Answer 1

Answer: the above states my answer and workings. hope this helps!

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Circle equal groups to finds the equivalent fraction. 6/6=/3

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The answer would have to be 3/3 to be equal to 6/6

Rename the number 9,200 hundreds

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nine thousand, two hundred

What's the diameter of a circle with a circumference of 48 millimeters

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since we are given circumference, we think the formula for the circumference, which is 2(pi)r or (pi)d where r and d is the radius and diameter respectively. the smarter formula of the 2 is (pi)d because it's d we want to find. setting up our equation:
circumference = (pi)d
48 = (pi)d
dividing both sides by pi gives:
d = 15.29 millimeters

let me know if you have any questions!

Is 5/12 greater than 3/4

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$(5)/(12) \hbox{ and }(3)/(4)=(3 * 3)/(4 * 3)=(9)/(12) \n \n5<9 \Rightarrow (5)/(12) < (9)/(12) \Rightarrow (5)/(12) <(3)/(4)$

No, 3/4 is greater than 5/12.

5/12 is not greater than 3/4 because 3/4 is only 1/4 away from becoming a whole number. On the other hand 5/12 is 7/12 away from becoming a whole number. Hope this helped :)

There is 5/6 of an apple pie left from dinner. Tomorrow, victor plans to eat 1/6 of the pie that was left. How much of the whole pie will be left after he eats tomorrow?

Answers

Answer:- The whole pie will be left after he eats tomorrow is $(25)/(36)$ of the whole pie.

Explanation:-

Pie left from dinner= $(5)/(6)$

If victor plans to eat 1/6 of the pie that was left,

The whole pie will be left = $(5)/(6)-(1)/(6)\ of\ (5)/(6)$

$=(5)/(6)-(1)/(6)*((5)/(6))\n\n=(5)/(6)-(5)/(36)\n\n=(30-5)/(36)=(25)/(36)$

Therefore, the whole pie will be left after he eats tomorrow is $(25)/(36)$ of the whole pie.

5/6 - 1/6 = 4/6 reduced to 2/3

Describe dimension of two different prisms that each have a volume of 2400 cubic

Answers

So look:

1) 20 cm by 20 cm by 6 cm
2) 40 cm by 30 cm by 2 cm

Hope this helps!

Well two different rectangular prisms could be the following:

1) 20 cm by 20 cm by 6 cm
2) 40 cm by 30 cm by 2 cm

I really hope I helped, and tag me if you need more help :)

Thank you,
Darian

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