PHYSICS HIGH SCHOOL

Sa ma ajute cineva va rog mult Ce cantitate de apă poate fi încălzită de la temperatura t 1 = 10 0 C la temperatura finală T 2 = 293, 15 K, dacă i se furnizează căldura de 41850 J ? Se dă căldura specifică a apei : c apă = 4185

Answers

Answer 1

Answer:

Răspuns:

1000 kg

Explicaţie:

Date date

t1 = 10 ° C

t2 = 293,15K = până la grad = 293,15-273 = 20,15 ° C

= 20 ° C aproximativ

Q = 418kJ = 418000J

c = 4180J / kg ° C

m =? Kg

Necesar:

Masa m în kg

Pasul doi:

Formulă:

Q = c * m * Δt

Q = c * m * (t2 -t1)

m = Q / c * (t2-t1)

Calculati:

m = 418000/4180 * (20-10)

m = 100 * 10 kg

m = 1000 kg

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