If there are 16 of commercials, how long is the television program

Answers

Answer 1
Answer:

Answer:

DEPENDS ON HOW LONG THE COMMERCIALS ARE

Step-by-step explanation:

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4. Find the sum of the first eighteen terms of the arithmetic sequence whose nthterm is an = 15 + 8n.
a. 1438
b. 1638
c. 1836
d. 1783​

Answers

Answer:

The sum of first eighteen terms of the arithmetic sequence is \mathbf{S_(18)=1638}

Option B is correct option.

Step-by-step explanation:

We need to find the sum of the first eighteen terms of the arithmetic sequence whose nth  term is an = 15 + 8n

The formula used to calculate sum of arithmetic sequence is: S_n=(n)/(2)(a_1+a_n)

Finding a₁ by putting n=1

a_n=15+8n\na_(1)=15+8(1)\na_(1)=15+8\na_(1)=23

We have a_1=23

Finding 18th term n=18

a_n=15+8n\na_(18)=15+8(18)\na_(18)=15+144\na_(18)=159

So, the sum of first eighteen terms of the arithmetic sequence is:

S_n=(n)/(2)(a_1+a_n)\nS_(18)=(n)/(2)(a_1+a_(18))\nS_(18)=(18)/(2)( 23+159)\nS_(18)=9(182)\nS_(18)=1638

So, the sum of first eighteen terms of the arithmetic sequence is \mathbf{S_(18)=1638}

Option B is correct option.

What equals 42 & 50 in multiplication Thanks So Much!!!!!!!

Answers

42 = 7 x 6
42 = 21 x 2
42 = 3.5 x 12

50 = 25 x 2
50 = 5 x 10

5 × 10 = 50

6 × 7 = 42

Express
2 ^( - 7)
using a positive exponent.​

Answers

Answer:

(1)/(2^7)

Step-by-step explanation:

To express the number 2⁻⁷ with a positive exponent, we'll make use of the properties of exponents and their relationship with reciprocals.

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Here's a list of the exponent properties:

\boxed{\left\begin{array}{ccc}\text{\underline{Properties of Exponents:}}\n\n1.\ a^0=1\n\n2.\ a^m * a^n=a^(m+n)\n\n3.\ a^m / a^n \ ((a^m)/(a^n) )=a^(m-n)\n\n4.\ (ab)^m=a^mb^m\n\n5.\ (a/b)^m=a^m/b^m\n\n6.\ (a^m)^n=a^(mn)\n\n7.\ a^(-m)=1/a^m\n\n8.\ a^(m/n)=(\sqrt[n]{a} )^m\end{array}\right}

In our case, we will use the reciprocal identity (#7 on the table above).

a^(-m)=(1)/(a^m) \n\n\n\n\therefore 2^(-7)=\boxed{(1)/(2^7) }

Thus, we can represent 2⁻⁷ as a positive exponent .

Find the product.
(n^3)^2 * (n^5)^4

Answers

Hi

(n^3)^2 × (n^5)^4 = n^6 × n^20 = n^26

Answer: n^26

The vertices of a feasible region are (14, 2), (0, 9), (6, 8), and (10, 3). What is the maximum value of P if P = 180x + 250y?

Answers

For this problem, we must first plot of each point using the given points. Assume that each coordinate given is in the (x,y) form. To get the maximum value, we can plus in each coordinate set to the equation to see which P comes out to be the largest. For (14,2), P=3020. For (0,9), P=2250. For (6,8), P=3080. For (10,3), P=2550. The maximum value for P would be P=3080.

Answer:

It’s C

Step-by-step explanation:

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. −2y2 + 6y = −2

Answers

-2y^2 + 6y + 2 = 0
a = -2, b = 6, c = 2
x = (- b + - sqrt(b^2-4ac))/(2a)
x=(-6+-sqrt(36-4*-2*2))/-4
x=(-6+-sqrt(36+16))/-4
x=(-6+-sqrt(52))/-4
x = (-6 +- 2sqrt13)/-4
x = (3 + - sqrt13)/2

Answer:

-0.3 Or 3.3

Step-by-step explanation:

-2y^2 + 6y + 2 = 0

X = -6 + 7.21/-4 or -7 - 7.21/-4

X = -0.3 or X = 3.3