HELP ME IM TIMED!Which expression best estimates -18
– ,
O 18-3
O -18-3
O-18-(-3)
O 18-(-3)

Answers

Answer 1
Answer: I’m not sure of the context of your class, but the second choice will give you -21 and the third one will give you -15. The first and last choice are positive, so just between those two
Answer 2
Answer:

Answer:I think it’s c

Step-by-step explanation:I’m think me smart


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A community pool office two types of memberships monthly and annual memberships. At the beginning of the year the ratio of monthly annual memberships is 10 to 3. However the pool offered an incentive to have members move the annual membership. After the incentive the ratio is 5 to 8. If there are 50 monthly members after the incentive and how many monthly members were there before?

Answers

Answer:

The number of monthly memberships before the incentive was 100

Step-by-step explanation:

Remember that

The total memberships after the incentive is equal to the total memberships before the incentive

step 1

Find out the annual memberships after the incentive

Let

x -----> monthly memberships after the incentive

y -----> annual memberships after the incentive

we know that

-----> equation A

substitute the value of x in equation A

step 2

Find out the total memberships after the incentive

step 3

Find out the monthly members before the incentive

Let

x -----> monthly memberships before the incentive

y -----> annual memberships before the incentive

we know that

-----> equation A

-----> equation B

substitute equation A in equation B and solve for x

therefore

The number of monthly memberships before the incentive was 100

Final answer:

Initially, there were 100 monthly members at the community pool, before the incentives were offered.

Explanation:

We start with the information that the ratio of monthly to annual memberships was initially 10 to 3, and then became 5 to 8. After the incentive, we're told there are now 50 monthly members.

To solve this problem, we set up a proportion. Since each part of the new ratio equals 10 members (50 monthly members/5 parts = 10 members per part), we can infer that before the incentive there were 10*10=100 monthly members.

Learn more about Proportions here:

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Please help will give brainliest

Answers

Answer:

I'm not completely sure but i'm going to guess on D the domain is 1 < f < 7, the range is 24 < c(f) < 168

Step-by-step explanation:

because 1 cup is < to a cup of Flour (f), and the expression says 7 cups in total so i f is less than or equal to the total number of cups 7. then the range says c(f)=24(f), meaning you get 24 cookies for the input amount "f" of cups of flour. So the range would be 24 is grater of equal to the c(f)which in total (7 x 24) is equal to 168

Ac and bd are perpendicular bisectors of each other. adc. Find eab

Answers

Let ∠ ADC = 2β

Ac and BD are perpendicular bisectors of each other ⇒⇒ (Given information)

∴ BD
bisects the angle ADC
∴ ∠ADE = 0.5 ∠ADC = β

And in ΔADE:
∵∠DEA = 90°    ⇒⇒⇒ from the given information
∴∠DAE = 90° - β

And AC bisects ∠DAB 
⇒⇒⇒ from the given information
∴∠EAB = ∠DAE = 90° - β

<EAB = 180 - 90 - (0.5*<ADC)

What is the value of x?



Enter your answer in the box.

x =

Answers

Answer:

x-4+3x+100=180....by angle sum property

4x=84

x=21

Suppose f(x,y)=xy, P=(−4,−4) and v=2i+3j. A. Find the gradient of f. ∇f= i+ j Note: Your answers should be expressions of x and y; e.g. "3x - 4y" B. Find the gradient of f at the point P. (∇f)(P)= i+ j Note: Your answers should be numbers C. Find the directional derivative of f at P in the direction of v. Duf= Note: Your answer should be a number D. Find the maximum rate of change of f at P. Note: Your answer should be a number E. Find the (unit) direction vector in which the maximum rate of change occurs at P. u= i+ j Note: Your answers should be numbers

Answers

Answers:

  • Gradient of f:    \nabla f =  y\hat{i} + x\hat{j}
  • Gradient of f at point p: \nabla f = -4\hat{i} -4\hat{j}
  • Directional derivative of f and P in direction of v: \nabla f(P)v = -20\n
  • The maximum rate of change of f at P:  | \nabla f(P)| =  4√(2)
  • The (unit) direction vector in which the maximum rate of change occurs at P is:  v =  -(1)/(√(2))\hat{i}-(1)/(√(2))\hat{j}

Step by step solutions:

Given that:

  • f(x,y) = xy
  • P = (-4,4)\n
  • v = 2i + 3j

A: Gradient of f

\nabla f = ((\partial f)/(\partial x), (\partial f)/(\partial y)) = (y,x) = y\hat{i} + x\hat{j}

B: Gradient of f at point P:

Just put the coordinates of p in above formula:

\nabla f = -4\hat{i} -4\hat{j}

C: The directional derivative of f and P in direction of v:

The directional derivative is found by dot product of \nabla f(P) \: \rm and \: \rm  v:

\nabla f(P)v = [-4,4][2,3]^T = -20\n

D: The maximum rate of change of f at P is calculated by evaluating the magnitude of gradient vector at P:

| \nabla f(P)| = √((-4)^2 + (-4)^2) = 4√(2)

E: The (unit) direction vector in which the maximum rate of change occurs at P is:

v = ((-4)/(4√(2)), (-4)/(4√(2))) = -(1)/(√(2))\hat{i}-(1)/(√(2))\hat{j}

That vector v is the needed unit vector in this case.

we divided by 4√(2) to make that vector as of unit length.

Learn more about vectors here:

brainly.com/question/12969462

Answer:

a) The gradient of a function is the vector of partial derivatives. Then

\nabla f=((\partial f)/(\partial x), (\partial f)/(\partial y))=(y,x)=y\hat{i} + x\hat{j}

b) It's enough evaluate P in the gradient.

\nabla f(P)=(-4,-4)=-4\hat{i} - 4 \hat{j}

c) The directional derivative of f at P in direction of V is the dot produtc of \nabla f(P) and v.

\nabla f(P) v=(-4,-4)\left[\begin{array}{ccc}2\n3\end{array}\right] =(-4)2+(-4)3=-20

d) The maximum rate of change of f at P is the magnitude of the gradient vector at P.

||\nabla f(P)||=√((-4)^2+(-4)^2)=√(32)=4√(2)

e) The maximum rate of change occurs in the direction of the gradient. Then

v=(1)/(4√(2))(-4,-4)=((-1)/(√(2)),(-1)/(√(2)))= (-1)/(√(2))\hat{i}-(1)/(√(2))\hat{j}

is the direction vector in which the maximum rate of change occurs at P.

Write an equation for the description . The length of a rectangle is twice its width . The perimeter of the rectangle is 122 feet.

Answers

Answer:

  122 = 2(2w +w)

Step-by-step explanation:

If we let w represent the width of the rectangle, then 2w is the length of it. The perimeter is twice the sum of length and width.

  P = 2(L+W)

  122 = 2(2w +w) . . . . an equation for the description