Which represents the copernican model that is the most similar to that of Aristarchus?
which represents the copernican model that is the most similar - 1

Answers

Answer 1
Answer:

Answer: A

Explanation: A is the answer

Answer 2
Answer:

Final answer:

The Copernican model that is most similar to Aristarchus' . It is a simple and accurate heliocentric model that explains planetary motion with a small set of rules and a single underlying force.

Explanation:

The Copernican model that is most similar to that of Aristarchus is represented by Figure 6.31(b). In this model, Earth and other planets revolve around the Sun. It is a simpler and more accurate heliocentric model, similar to Aristarchus' idea of a heliocentric solar system. The Copernican model explains planetary motion with a small set of rules and a single underlying force, demonstrating the breadth and simplicity of the laws of physics.

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Calculate the density of argon gas at a pressure of 753 mmHg and a temperature of 35 °C
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Which is not a difference between a population showing exponential growth and a population showing logistic growth?a. food limits
b. disease limits
c. carrying capacity
d. mutation rate

Answers

Answer;

Mutation rate

-Mutation rate is not a difference between a population showing exponential growth and a population showing logistic growth.

Explanation;

-When the resources are unlimited, populations exhibit exponential growth, resulting in a J-shaped curve and when the resources are limited, populations exhibit logistic growth.

-The carrying capacity is the maximum population size of the species that the environment can sustain indefinitely, given the food, habitat, water, and other necessities available in the environment. It affects the size of population and thus has an effect on both exponential and logistic growth.

-Food limits and disease limits are also other factors that may determine the population size in a biological ecosystem.

        Mutation rate is not a difference between a population showing exponential growth and a population showing logistic growth. Hope this helped :D

The two most abundant elements in earth's core are ?

Answers

The most abundant element in the earth core is oxygen the most essential and precious gas. Second most abundant element is silicon.

What are elements?

Elements are the basic things in the universe. Everything in the world is made of elements. Elements combines to form molecules, molecules then forms compounds and compounds makes the macrothings.

There are various kinds of elements such as metals, gases, metalloids. etc. These all elements shows their characteristic physical and chemicals behaviours. Based on their electronic properties all the elements are classified into various groups in periodic table.

Oxygen is the most abundant element in the earth core that we all are used to intake for respiration. Oxygen s 8th element in periodic table and it is in P-block.

Silicon is the second most abundant element in the earth core. Silicon is a metalloids in 14th group of p-block and it is 14th element in periodic table. It is used in many electronic devises.

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The two most abundant elements in Earths core are Iron and Nickel.

Hope this helps!

The ratio of hydrogen atoms to sulfur atoms in sulfuric acid, H2SO4 is

Answers

The question is asking the ratio of H to S in H2SO4.
In the following molecular formula, there are 2 hydrogen and 1 sulfur
This means that the ratio is 2:1.

How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 19.1 moles of water vapor?

Answers

Answer:

19.1 mol H2

Explanation:

1. Hello, first you have to propose the chemical equation:

H2 + CO2 = H2O + CO

The equation has to be balanced, it means that the same quantity of atoms must be in the right and left side of the equation.

2. To do the stochiometric calculus, you need to find which one is the limiting reactant, in the problem says that you are working with an excess of carbon dioxide, so the limiting reactant is hydrogen H2:

Limiting reactant: H2

Excessing reactant : CO2

3. With the limiting reactant and the chemical equation, you have to establish the stichometrical relation to calculate the quantity of all reactants and products:

In a base of the chemical equation, and using the limiting reactant:

1 mol H2 = 1 mol H2O

The exercise says that you have 19.1mol of water vapor (H2O(g)), then to calculate the mol of  H2 you need, you make the calculus as follow:

19.1 mol H2O ×( 1mol H2/1 mol H2O)= 19.1 mol H2

The exercise completed is in the document attached.

balanced equation:
4H2 + CO2 = 2H2O + CH4

so 4 moles H2 : 2 moles H2O = x : 19.1

you ll need x = 2x19.1 / 4 
and that is 9.55 moles of hydrogen gas

Which half-reaction can occur at the anode in avoltaic cell?
(1) Ni2+ + 2e---> Ni (3) Zn--> Zn2+ + 2e-
(2) Sn + 2e---> Sn2+ (4) Fe3+--> Fe2+ + e-

Answers

The answer is (3). The reaction that can occur at the anode is oxidation reaction which will lose electrons. So (1) and (2) are not correct. For (4) Fe3+ can not lose electrons again.

The thirdreaction of the zinc-releasing electron and zinc ion will occur as the half-reaction at the anode of the voltaic cell. Thus, option 3 is the correct option.

What is a half-reaction?

A half-reaction is a depiction of the oxidation or the reduction half of a redox reaction that involves the stating of the oxidation states and the release or the absorption of the electrons.

The anode is an electrode of the voltaic cell where the oxidation reaction takes place. The oxidation results in the loss of the electrons and hence, reactions 1 and 2 cannot occur at the anode. The fourth reaction is also not possible as iron cannot lose its electron.

Therefore, option 3. Zn → Zn²⁺ + 2e⁻ will occur at the anode.

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Argon-39 has a half-life of 269 years. How long will it take for 52.5 g of a 60.0 g sample to decay to its daughter isotope?

Answers

The years that will take or 52.5 g of a 60.0 g sample to decay to its daughter isotope is 807 years.

What is half-life?

Half-life is the time required to decay or undergo half the process of any element.

Given the sample is 60.0 g in which 52.5 g sample has to be decay

so, 60 - 52.5 = 7.5 g

It can be seen that it goes three half life

60 >30 >15 >7.5

Now, the half life is 269

269 × 3 = 807 years.

Thus, the years taken are 807 years.

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For 60.0 g sample, if it remains 60-52.5=7.5 g, it will go through 60->30->15->7.5, 3 half-life. So the time being taken is 269*3=807 years.