What is -6f +13= 2f - 11
Answers
Related Questions
4/7 = x+3/21A) x=9B) x=15C) x= 33 3/4D) x=91-Would it be A??
What is standard form of 4x4x4
Fill in the missing numbers 5,554, 5,274, 4,994, 4,714
Can you help! What is 48771273 + 68296638918
Answers
Answer:
v=8
Step-by-step explanation:
Answers
answer
5
set up equations
daren is 3 years older than tom
D = 3 + T
3 years ago leah will be 14 less than 3 times darren's age
L - 3 = 3(D - 3) - 14
L - 3 = 3D - 9 - 14
L = 3D - 9 - 14 + 3
L = 3D - 20
5 years ago, leah was 2 years less than 2 times tom
L - 5 = 2(T - 5) - 2
L - 5 = 2T - 10 -2
L = 2T - 10 - 2 + 5
L = 2T - 7
find leah's current age
set L = 3D - 20 and L = 2T - 7 equal to each other
3D - 20 = 2T - 7
plug 3 + T into D using the equation D = 3 + T
3D - 20 = 2T - 7
3(3 + T) - 20 = 2T - 7
9 + 3T - 20 = 2T - 7
T = - 7 - 9 + 20
T = 4
plug T back into L = 2T - 7 to find leah's current age
L = 2T - 7
L = 2 * 4 - 7
L = 8 - 7
L = 1
leah's age 4 years from now
add 4 to leah's current age
1 + 4 = 5
Answers
Answer: After 2:29 hours both Aldrin and Jan will be 13 km apart from each other.
Time at that instant will be : 4:00 pm + 2.29 hours= 6:29 pm
Step-by-step explanation:
According to the figure:
Ab= c = 13 Km
AC = b = =5t Km
After two hours the distance covered by the Aldrin say till point D :
Since, we are interested in determining the time at which Aldrin and Jan both 13 Km apart. For that Aldrin Additional distance covered by the Aldrin from point D to B is :
CB= a = CD+DB= 6+3t
We will apply Laws of cosines:
On solving the the above equation by quadratic formula we get two values of 't'
1) t = 2.49 hours , 2) t = -2.80 hours
Since,time cannot be in negative so we will ignore the negative value of t
t = 2.49 = 2:29 hours ,(0.49 hour=0.49 × 60 min=29.4 min)
After 2.49 hours after the walking of Jan. Both Aldrin and Jan will be 13 km apart from each other.
Time at that instant will be : 4:00 pm + 2:29 hours= 6:29 hour
Answers
subtract mentally=6.92
Answers