Which of the following can be a solution to the inequality below?2x > 6.
Pls send help

Answers

Answer 1
Answer:

Answer:

x>3

Step-by-step explanation:

you divide both sides by 2 then you get three. The sign remains the same.


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I NEED SOME REALLY FAST HELP Which value of x is in the solution set of 2|x – 3| < 4?A.x = 8B.x = 0C.x = 4D.x = –1

Take a look at the figure. What are the coordinates of the point labeled A in the graph shown?A. (2, 2)
B. (–2, 4)
C. (2, –2)
D. (–2, 2)

Answers

The coordinates of the point labeled A in the graph shown is (2,-2). The 2 is in the x axis while -2 is in the y axis of the graph while point B is in coordinates (-2,-2) and  point C is in coordinates (-2,4).

What is 940 divided by
58 equals what's

Answers

154.13793103 it gave it in decimal form


The answer is16.20689655172414


Help me, please!! Estoy desesperada y no hablo inglês!! Help

Answers

Log x^n = nLog x
log x + log x^2 + log x^3
Log x + 2 log x +3 log x = -6
6 log x = -6
Log x = -1
X=10^-1 = 1/10
Respuesta final
X=1/10
D:x>0\n\log x+\log x^2+\log x^3=-6\n\log (x\cdot x^2\cdot x^3)=\log 10^(-6)\nx^6=10^(-6)\nx^6=\left((1)/(10)\right)^6\n \boxed{x=(1)/(10)}

There are 10 marbles in a bag, and the marbles are either red or blue. Eric will randomly choose two marbles from the bag, without replacing the first one. If the probability of both marbles' being red is 2
15, how many RED marbles are in the bag?

Answers

Let the number of red marbles be r. Now we can write the equation:
(r)/(10)*(r-1)/(9)=(2)/(15)
Rearranging the above equation and simplifying gives the quadratic:
r^(2)-r-12=0
which factorizes to:
(r - 4)(r + 3) = 0
Therefore r = 4. there are 4 RED marbles in the bag.

Answer:

6

Step-by-step explanation:

BECAUSE.

at a school choir concert 256 students are standing in rows. if the number of students in each row is equal to the total number of rows find the number of students in each row

Answers

(16 rows) x (16 students/row) = 256 students . 

Help me please I don't get it

Answers

Hey Dude Armando Is Correct!