The depictions of ionic compounds do not show distinct compound units but rather a collection of ions in the ratio given by the formula. Explain how the drawing of NaCl both illustrates that the compound exists as a large collection of ions and that the ratio of sodium ions to chloride ions is 1-to-1 as indicated by the formula NaCl.
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Answer:
The ionic compound NaCl has a Face Centered Cubic unit cell
The site for atoms are Face, center and Edges corner.
Effective number of atoms
Na+
1centers + 12edges x = 4 Na+
Cl-
6face x +
x8 corners = 4Cl-
This is just one unit cell effective atom, there are thousand's of such unit cells are combined to form one such structure of NaCl. The real formula of NaCl is Na4Cl4 but for simplicity we use empirical formula that is NaCl.
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(1) N2 (3) Na
(2) NH4+ (4) NaHCO3
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The species that significantly represents a chemical compound is known as NaHCO3. This is also known as Sodium bicarbonate or sodium hydrogen carbonate. Thus, the correct option for this question is D.
What is a Chemical compound?
A chemical compound may be defined as a type of chemical substance that is mainly composed of many similar molecules that contain atoms of more than one chemical element. These atoms are typically held together by chemical bonds.
According to the context of this question, Na is sodium and N2 is dinitrogen or simply nitrogen gas. Both these chemical constituents are classified as the type of chemical element. While NH4+ is a polyatomic ion which is known as an ammonium ion.
So, NaHCO3 is classified into the category of a chemical compound. This is because it mainly consists of sodium, hydrogen, carbon, and oxygen.
Therefore, the species that significantly represents a chemical compound is known as NaHCO3. This is also known as Sodium bicarbonate or sodium hydrogen carbonate. Thus, the correct option for this question is D.
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Answer:
4.) NaHCO3
Explanation:
In a compound, two or more elements are chemically combined. NaHCO3 is a compound containing the elements sodium (Na), hydrogen (H), carbon (C), and oxygen (O). N2 and Na are elements. NH4+ is the polyatomic ion ammonium.Zoom
Answers
Answer:
54.2 g of Ca(OH)â‚‚
Explanation:
Let's determine the moles of solute, we should need
Molarity . volume (L) = moles
Let's convert 600 mL to L
600 mL/ 1000 = 0.6L
1.22 mol/L . 0.6L = 0.732 moles
Finally we must convert the moles to mass ( moles . molar mass)
0.732 mol . 74.08 g/mol = 54.2 g
Answer: 54.2 g Ca(OH)2
Explanation: Molarity is moles of solute / L solution
First convert mL to L
600 mL x 1L / 1000 mL = 0.6 L
Find moles of Ca(OH)2
n= M x L
= 1.22 M x 0.6 L
= 0.732 moles Ca(OH)2
Convert moles to mass using its molar mass of Ca( OH)2 = 74 g
0.732 moles Ca(OH)2 X 74 g Ca(OH)2 / 1 mole Ca(OH)2
= 54.2 g Ca(OH)2
B.) 75g
C.) 120g
D.) 140g
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Answer:
A
Explanation:
Im just guessing its half of 200 as it says
Final answer:
The actual yield of a reaction, where only 50% of a theoretical yield of 200g is formed, is 100g.
Explanation:
The actual yield refers to the amount of product that is actually formed when the reaction is carried out in a real-life setup. In this case, if the theoretical yield (which is the amount of product predicted by stoichiometric calculations) is 200g but only 50% is actually formed, then the actual yield would be 50% of the theoretical yield. Hence, the answer will be 50% of 200g i.e., 100g.
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