A weather service records 28.8 inches of rain over a 12 month period. What is the average rainfall per month for the year?A:
A)
17 inches
B)
2.4 inches
o
2.9 inches
D)
3.1 inches

Answers

Answer 1
Answer:

Answer:

B) 2.4 inches

Step-by-step explanation:

The total amount of rain is 28.8 inches over 12 months. To find how much rain falls averagely in one month you need to divide the total by the amount of months. 28.8/12 = 2.4


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Answers

X? Not sure what the answer choices are but try that

A social scientist believed that less than 30 percent of adults in the United States watch 15 or fewer hours of television per week. To test the belief, the scientist randomly selected 1,250 adults in the United States. The sample proportion of adults who watch 15 or fewer hours of television per week was 0.28, and the resulting hypothesis test had a p-value of 0.061. The computation of the p- value assumes which of the following is true? (A) The population proportion of adults who watch 15 or fewer hours of television per week is 0.28. Submit

(B) The population proportion of adults who watch 15 or fewer hours of television per week is 0.30.

(C) The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30.

(D) The population mean number of hours adults spend watching television per week is 15.

(E) The population mean number of hours adults spend watching television per week is less than 15.

Answers

The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30.

Given that,

A social scientist believed that less than 30 percent of adults in the United States watch 15 or fewer hours of television per week.

The scientist randomly selected 1,250 adults in the United States. The sample proportion of adults who watch 15 or fewer hours of television per week was 0.28,

And the resulting hypothesis test had a p-value of 0.061.

We have to determine,

The computation of the p- value assumes which of the following is true.

According to the question,

Let, The proportion of adults watching televisionless than or equal to 15% be = x

Null Hypothesis [H0] :  x = 30% = 0.30

Alternate Hypothesis [H1] : x < 30% , or x < 0.30

P value is calculated at z value :

= P_1- \sqrt(p_o(1-p_o))/(n)}

Where p' = 0.28, P_0 = 0.30, P_1= 0.70 ;

Then,

= 0.70- \sqrt(0.30(1-0.30))/(1250)}\n\n= 0.70- \sqrt{(0.30 * 0.70 )/(1250) }\n\n= 0.70 - 0.012\n\n= 0.61

Assuming 10% level of significance, p = 0.10

Therefore, p value 0.061 < 0.10, reject H0 & accept H1. This implies that we conclude that 'x i.e. proportion of adults watching television less than or equal to 15% <  30% or 0.30'

Hence, The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30.

To know more about Sample proportion click the link given below.

brainly.com/question/13846904

Answer:

(C) The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30

Step-by-step explanation:

Let the proportion of adults watching television less than or equal to 15% be = x

  • Null Hypothesis [H0] :  x = 30% = 0.30
  • Alternate Hypothesis [H1] : x < 30% , or x < 0.30

P value is calculated at z value : p' - [ √ { p0 (1- p0) } / n ] ;

where p' = 0.28, p0 = 0.30, p1 = 0.70 ; ∴ p ( z < -1.543) = 0.061

Assuming 10% level of significance, p = 0.10

As p value 0.061 < 0.10, we reject H0 & accept H1. This implies that we conclude that 'x ie proportion of adults watching television less than or equal to 15% <  30% or 0.30'

MATH 1325 – EXAM 4 NAME: ______________________________ SHOW ALL WORK. ANSWERS WITHOUT WORK WILL RECEIVE NO CREDIT. YOU MUST USE A PENCIL. READ ALL DIRECTIONS. POINTS WILL BE DEDUCTED FOR FAILURE TO FOLLOW DIRECTIONS. TRUE/FALSE – WRITE THE WORD THAT BEST DESCRIBES THE GIVEN STATEMENT BY WRITING EITHER "TRUE" OR "FALSE" IN THE SPACE PROVIDED TO THE LEFT OF THE PROBLEM. __________ 1. THE ABSOLUTE MAXIMUM OF A FUNCTION ALWAYS OCCURS WHERE THE DERIVATIVE HAS A CRITICAL FUNCTION. __________ 2. IMPLICIT DIFFERENTIATION CAN BE USED TO FIND dy dx WHEN x IS DEFINED IN TERMS OF y . __________ 3. IN A RELATED RATES PROBLEM, THERE CAN BE MORE THAN TWO QUANTITIES THAT VARY WITH TIME. __________ 4. A CONTINUOUS FUNCTION ON AN OPEN INTERVAL DOES NOT HAVE AN ABSOLUTE MAXIMUM OR MINIMUM. __________ 5. IN A RELATED RATES PROBLEM, ALL DERIVATIVES ARE WITH RESPECT TO TIME. MULTIPLE CHOICE – CHOOSE THE ONE ALTERNATIVE THAT BEST COMPLETES THE STATEMENT OR ANSWERS THE QUESTION BY CIRCLING THE CORRECT LETTER. 6. FIND THE MAXIMUM ABSOLUTE EXTREMUM AS WELL AS ALL VALUES OF x WHERE IT OCCURS ON THE SPECIFIED DOMAIN

Answers

Answer: Please see explanation column for answers. Also check number 6, its question is incomplete.  i used an assumed function, incase its not the same function with the one omitted, just follow steps

Step-by-step explanation: Questions 1-5 do not need any step by step explanation, its purely straight forward but Question 6 involves step by step explanation but  is not a complete question, though i used an assumed function.

FALSE   ---> 1. THE ABSOLUTE MAXIMUM OF A FUNCTION ALWAYS OCCURS WHERE THE DERIVATIVE HAS A CRITICAL FUNCTION. ___TRUE_____-->__ 2. IMPLICIT DIFFERENTIATION CAN BE USED TO FIND dy/dx WHEN x IS DEFINED IN TERMS OF y .

TRUE__--->3. IN A RELATED RATES PROBLEM, THERE CAN BE MORE THAN TWO QUANTITIES THAT VARY WITH TIME.

_FALSE  ---> 4. A CONTINUOUS FUNCTION ON AN OPEN INTERVAL DOES NOT HAVE AN ABSOLUTE MAXIMUM OR MINIMUM.

____TRUE__--->____ 5. IN A RELATED RATES PROBLEM, ALL DERIVATIVES ARE WITH RESPECT TO TIME.

6. FIND THE MAXIMUM ABSOLUTE EXTREMUM AS WELL AS ALL VALUES OF x WHERE IT OCCURS ON THE SPECIFIED DOMAIN

----Incomplete question Please.

But assuming the function---- f(x)= x³ -3x+1

 for (E)=(0,3)

step 1= let us use the power rule to find derivative of   f(x)= x^3 -3x+1

we will have f¹ (x) = 3x² -3

The critical values occurs when  3x² -3 = 0

which makes x=⁺₋1

As can be seen 3x² -3 = 0

                         3x²=3

                          x²=3/3=1

                       x= ⁺₋1

step 2=Now x= -1 cannot be considered because it is not in the interval  of the critical values (0,3)

therefore we consider x=1

step 3=The absolute extremes occurs at x=0, x=1, x=3 forf(x)= x³ -3x+1

when x=0,  f(0)= 0³-3(0)+ 1= 1

         x=1    f(1)=1³-3(1) +1=  -1

         x=3    f(3)= 3³ -3(3)+1= 19

Absolute minimum at x=1 has absolute value of-1

Absolute maximum of x=3 has absolute value of 19

Kellen bought a souvenir cup at the zoo for $7.50. Any time Kellen bringsthe
cup back to the zoo, he can purchase fountain drinks for $0.75 each. If
Kellen has spent $12.75 so far, including the original purchase of the cup,
how many fountain drinks has he purchased?

Answers

Answer:

7 fountain drinks

Step-by-step explanation:

$12.75-$7.50=$5.25

$5.25/$0.75=7

Input numbers have been changed by a rule to get output numbers which of these could be the rule for changing the input numbers to the output numbers? Input: 3,6,9. Output:4,5,6.

Answers

Changes in output are evenly spaced for evenly spaced changes in input, so the rule is linear. Changes in output are 1 for changes in input of 3, so the rule involves a factor of 1/3. One possible rule is

... output = (1/3)·input + 3

If y and x are used to represent output and input, respectively, this is

... y = (1/3)x + 3

2x- y = -2
2x + 4y =8​

Answers

Answer:

x=8

y=4

Step-by-step explanation:

Answer:

Your point would be: (0,2)

x = 0

y = 2

Step-by-step explanation:

This would be the case if you're looking for the point by solving with substitution, or any other methods, of the systems of equations.

In any case, you are looking to find either x or y first.

I will demonstrate with the 'y' value, since it is easier when cancelling out the 'x' value.

2x - y = -2

2x + 4y = 8

(I want to make one of the two equations negative, so that I can eliminate or cancel out the 'x' value(s)).

- (2x - y = -2) --> -2x + y = 2

                          2x +4y = 8

---------------------------------------

                                5y = 10

                                ---     ---

                                 5      5

                              ------------

                                 y = 2

(Reason for putting a negative in front of the equation '2x - y = -2' was made in order to eliminate the value(s) '2x' in both equation, and in order to do that, one equation must be negative, while the other is positive, for example:

x + 2y = 6

x + 3y = 5

(You can make any of these equations negative, but only one equation is needed to be negative for the value you want to cancel out,

DO NOT TRY AND CANCEL OUT BOTH X AND Y)

-(x + 2y = 6)

Turn into:

-x - 2y = -6

x + 3y = 5

---------------

y = -1

(Back to the Original Problem)

We now need to find the 'x' value(s):

4(2x - y = -2)

8x - 4y = -8

2x + 4y = 8

----------------

10x = 0

---     ---

10     10

----------------

x = 0

Your final answer will be:

(0,2)