MATHEMATICS HIGH SCHOOL

Walmart is selling 3 lemons for $1.20.how many does 25 lemons cost

Answers

Answer 1

Answer:

Answer:

10USD

Step-by-step explanation:

For each lemon: 1.20/3=0.4

for 25: 0.4*25=10USD

Related Questions

Look down below for question

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the maximum amount of time the skier is in the air would be the time to "fall" the 50 meters.

$distance = 1/2 a t^2$

$50 = 1/2 (9.8) t^2$

$t= 3.2 seconds$

The width of a rectangle is 61 centimeters more than the length. The perimeter is 406 centimeters. Find the length and the width.

Answers

$Step \; 1: \; Assign \; Variables \; for \; the \; unknown \; that \; we \; need \; to \; find$

$Let \; x \; be \; length \; of \; the \; rectangle$

$Step \; 2: \; Set \; up \; equation \; based \; on \; information \;\n given \; about \; the \; rectangle$

$Statement \; 1: Width \; of \; a \; rectangle \; \nis \; 61cm \; more \; than \; the \; length\n\nWidth \; = \; 61+x\n\nStatement \; 2: \; The \; perimeter \; is \; 406cm\n\nPerimeter=2(Length+Width)\nPerimeter =2(x+61+x)\n\nSo \; the \; mathematical \; equation \; would \; be \n 2(x+61+x)=406$

$Step \; 3: \; Solve \; the \; equation \; by \n undoing \; whatever \; is \; done \; x.\n\n2(x+61+x)=406\nGroup \; and \; Combine \; like \; terms \; inside \; the \; parenthesis\n\n2(2x+61)=406\nDistribute \; 2 \; in \; the \; left \; side \; of \; the \; equation\n\n4x+122=406\nSubtract \; 122 \; on \; both \; sides\n\n4x+122-122=406-122\nSimplify \; on \; both \; sides\n\n4x=284\nDivide \; on \; both \; sides\n\n(4x)/(4)=(284)/(4)\nSimplify \; fractions \; on \; both \; sides\n\nx=71$

$Conclusion:\nLength=x=71cm\nSubstituting \; 71 \; for \; x \; and \; find \; Width \; value.\nWidth=61+x=71+61=132cm\n\nLength \; is \; 71 cm \; and \; Width \; is 132cm$

Final answer:

The length of the rectangle is 71 centimeters and the width is 132 centimeters.

Explanation:

To find the length and width of the rectangle, we can set up a system of equations. Let's denote the length of the rectangle as L and the width as W. We know that W = L + 61. The formula for the perimeter of a rectangle is P = 2L + 2W. Plugging in the given values, we have 406 = 2L + 2(L + 61). Simplifying this equation, we get 406 = 4L + 122. Subtracting 122 from both sides, we obtain 284 = 4L. Dividing both sides by 4, we get L = 71. Finally, substituting the value of L into the equation W = L + 61, we find W = 71 + 61 = 132. Therefore, the length of the rectangle measures 71 centimeters and the width measures 132 centimeters.

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A rancher has 800 feet of fencing to put around a rectangular field and then subdivide the field into 3 identical smaller rectangular plots by placing two fences parallel to one of the field's shorter sides. Find the dimensions that maximize the enclosed area. Write your answers as fractions reduced to lowest terms

Answers

Let x be the shorter side, and y be the longer side

There would be 4 fences along the shorter side, and 2 fences along the longer side

4x + 2y = 800

Rewrite in terms of y:

y = 400 − 2x

The area of the rectangular field is

A = x*y

Replace Y with the equation above:

A = x(400 − 2x)

A = − 2x^2 + 400x

The area is a parabola that opens downward, the maximum area would occur at the parabola vertex.

At the vertex

x = −b/2a

= −400/[2(−2)]

= 100

y = 400 −2x

y = 400 -2(100)

y = 400-200

y = 200

The dimension of the rectangular field that maximize the enclosed area is 100 ft x 200 ft.

The dimension of the rectangular field that maximize the enclosed area is 100 ft by 200 ft.

Application of the vertex of a quadratic equation

The formula for calculating the vertex of a quadratic equation is given as:

x = -b/2a

From the given question

Let the shorter side be x

Let the longer side of the field be y

If there are 4 fences along the shorter side, and 2 fences along the longer side, hence;

4x + 2y = 800

Write the resultinq equation in slope-intecept form

2y = -4x + 800

y = -2x + 400

y = 400 − 2x

Determine the area of the field

Area = x*y

Substitute the expression above into the area to have:

A = x(400 − 2x)

A = − 2x^2 + 400x

Since the parabola opens downward, the maximum area would occur at the parabola vertex as shown;

x = −b/2a

x = −400/2(-2)

x = 400/4

x = 100

Determine the value of y

y = 400 −2x

y = 400 -2(100)

y = 400-200

y = 200

Hence the dimension of the rectangular field that maximize the enclosed area is 100 ft by 200 ft.

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Suppose you deal three cards from a regular deck of 52 cards, What is the probability that they will all be jacks?

Answers

Answer:

$0.00018$

Step-by-step explanation:

The number of ways you can draw 3 cards from the deck of 52 cards is,

$\dbinom{52}{3}=(52!)/(3!\ 49!)=(52* 51* 50)/(6)=22100$

Out of 52, 4 cards are jacks. So the number of ways you can draw 3 jacks out of 4 is,

$\dbinom{4}{3}=(4!)/(3!\ 1!)=(24)/(6)=4$

So, the probability three cards from a regular deck of 52 cards will be,

$(4)/(22100)=0.00018$

Final answer:

The likelihood of pulling three Jacks from a 52-card deck is calculated by multiplying together the probabilities of pulling a Jack on each of the three cards drawn. This comes to approximately 0.000181, or 0.0181%

Explanation:

The question you're asking is about the probability of drawing three Jacks from a 52-card deck. A standard deck has 52 cards, and there are 4 Jacks in the deck. So, when you're dealing the first card, the probability that it's a Jack is 4 out of 52, or 1 out of 13. After one Jack has been dealt, there are now only 3 Jacks left and 51 cards total, so the probability that the second card is a Jack is 3 out of 51. For the third card, because there are only 2 jacks left out of 50 cards, the probability is 2 out of 50. Because you want all these events to happen, you would multiply these probabilities together. Therefore, the probability of getting three Jacks is (4/52) * (3/51) * (2/50), which simplifies to approximately 0.000181.

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10,infinity
Interval notation-
Inequality notation-

Answers

Answer:

Step-by-step explanation:

Which statement is true about a model of a prime polynomial? It cannot be modeled with a rectangle. It can be modeled with a square. It cannot be modeled with all positive tiles. It can only be modeled with an odd number of tiles. please help me

Answers

The correct answer is:

It cannot be modeled with a rectangle.

Explanation:

When using area tiles to represent polynomials, we arrange the tiles into a rectangle in order to find the factors of the polynomial.

Since the area of a rectangle is found by multiplying length and width, if we find the "length" and "width" of the polynomial rectangle, we have the factors that multiply to make up that polynomial.

However, if a polynomial is prime, its only factors are 1 and itself. This means the "length" would be the polynomial itself, and the "width" would be 1. This means we cannot arrange the polynomial into a rectangle.

Answer:

A : it cannot be modeled with a rectangle

Step-by-step explanation:

edge 2020 . good luck !

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