A system of two equations is shown below: Equation C: a = 2b + 7 Equation D: a = 5b − 3 What value of a can be substituted into equation D to solve the system of equations?

Answer:

The first answer is a = 10, The second answer is b = 7

Step-by-step explanation:

Equation 1: 5a = a + 40

To solve for a, you want to isolate a on one side of the equation. You can do this by subtracting "a" from both sides of the equation:

5a - a = a - a + 40

This simplifies to:

4a = 40

Now, divide both sides by 4 to solve for a:

4a/4 = 40/4

a = 10

So, a = 10.

Equation 2: 3b = 10b - 49

To solve for b, you want to isolate b on one side of the equation. First, let's get the "b" terms on one side by subtracting 10b from both sides:

3b - 10b = 10b - 10b - 49

This simplifies to:

-7b = -49

Now, divide both sides by -7 to solve for b:

(-7b) / (-7) = (-49) / (-7)

b = 7

So, b = 7.

Answer:

x=3

Step-by-step explanation:

Use pemdas!

First use distributive property to get rid of the parenthesis, by multiplying 2 by 3x and -4. Then combine like terms and use inverse operations to simplify each side until you get it down to just x! Hope this helped! :)

Answer:

4. (d) option is correct because -7-(-5) = -7+5 ( Because - and - makes a plus .

Hope it does aid you .

Pls mark brilliant .