A package of 6 pairs of insulated gloves costs $43.14 what is the unit price of the pairs of gloves?
Answers
Answer: 7.19
Step-by-step explanation:
Math
Related Questions
When Maxwell solved his equation, he got 5=5. If he did everything correctly, what does this solution tell him?
What fraction lies exactly halfway between 2/3 and 3/4 ?a) 3/5b) 5/6c) 7/12d) 9/16e) 17/24
If y=kxy=kxy, equals, k, x, where kkk is a constant, and y=24y=24y, equals, 24 when x=6x=6x, equals, 6, what is the value of yyy when x=5x=5x, equals, 5?Please choose from one of the following options. (Choice A)A 666 (Choice B)B 151515 (Choice C)C 202020 (Choice D)D 2323
How long will money in savings take to double at 5% interest compounded annually? Round the answer to the nearest hundredth of a year.
and the point P(-3,6) and then answer the following questions:
a. How would you find the line (B) that passes through point P and is perpendicular to line A? What is the equation of that line?
b. How would you find the length of the segment of line B from point P to line A?
c. How would you find the midpoint between point P and the intersection of line A and line B ?
Answers
Answer:
- y = -6/5x +12/5
- distance from P to A: (66√61)/61 ≈ 8.4504
- midpoint: (-18/61, 168/61) ≈ (-0.2951, 2.7541)
Step-by-step explanation:
a. The slope of the perpendicular line is the negative reciprocal of the slope of the given line, so is ...
m = -1/(5/6) = -6/5
Then the point-slope form of the desired line through (-3, 6) can be written as ...
y = m(x -h) +k . . . . . line with slope m through (h, k)
y = (-6/5)(x +3) +6
y = -6/5x +12/5 . . . equation of line B
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b. The distance from point P to the intersection point (X) can be found from the formula for the distance from a point to a line.
When the line's equation is written in general form, ax+by+c=0, the distance from point (x, y) to the line is ...
d = |ax +by +c|/√(a² +b²)
The equation of line A can be written in general form as ...
y = 5/6x -5/2
6y = 5x -15
5x -6y -15 = 0
Then the distance from P to the line is ...
d = |5(-3) -6(6) -15|/√(5² +(-6)²) = 66/√61
The length of segment PX is (66√61)/61.
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c. To find the midpoint, we need to know the point of intersection, X. We find that by solving the simultaneous equations ...
y = 5/6x -5/2
y = -6/5x +12/5
Equating y-values gives ...
5/6x -5/2 = -6/5x +12/5
Adding 6/5x +5/2 gives ...
x(5/6+6/5) = 12/5 +5/2
x(61/30) = 49/10
x = (49/10)(30/61) = 147/61
y = 5/6(147/61) -5/2 = -30/61
Then the point of intersection of the lines is X = (147/61, -30/61).
So, the midpoint of PX is ...
M = (P +X)/2
M = ((-3, 6) +(147/61, -30/61))/2
M = (-18/61, 168/61)
Final answer:
To find line B perpendicular to line A and pass through point P, calculate the negative reciprocal of line A's slope and use it in the line equation along with point P coordinates to find c. The segment length from point P to line A is calculated using the distance formula and involves finding the intersection point between lines A and B. The midpoint is calculated using the midpoint formula.
Explanation:
To answer this question, we need to understand that two lines are perpendicular if the product of their slopes is -1. Line A has a slope of 5/6. Therefore, the slope of line B, perpendicular to line A, is -6/5 (the negative reciprocal). The equation of a line is y = mx + c where m is the slope and c is the y-intercept. As line B passes through point P(-3,6), we can substitute these values into the line equation y = -6/5x + c to solve for c. This will give us the equation of line B.
To find the length of the segment from point P to Line A, we would first need to find the intersection point of Line A and B. Then use the distance formula, which is sqrt[(x2-x1)^2 + (y2-y1)^2].
The midpoint of two points, (x1,y1) and (x2,y2) is given by ((x1+x2)/2, (y1+y2)/2). This formula can be used to find the midpoint between point P and the intersection of line A and line B.
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Answers
3/4 = 15/20
2/5 = 8/20
I didn't quite read the question properly, but regardless. Since only 15/20 of the batch has raisins, of which only 8/20 has nuts, we can formulate this equation to solve:
1x15/20x8/20
=3/10
B)-13/2
C)-6x+14
D)-3/2x+5
An airplane's altitude changed -378 feet over 7 minutes. What was the mean change of altitude in feet per minute?
WORK PLEASE
Answers
pemdas
(8-6x+12)
(20-6x)
multiply/distribute
1/4(20-6x)
5-6/4x=5-3/2x=-3/2x+5
the answer is D
so mean is equivilent to average
per minute means x feet for every one minute=xfeet/1miin=x/1
so just divide
-378/7=-54
mean change in altitude
-54 feet per minute
Second Question:
The average (mean) rate of change is just
Hope this helps :D
find the product
(5n+6)(5n-5)
Answers
The solution of expression after multiplying is,
⇒ 25n² + 5n - 30
We have to given that,
To multiplying polynomials is,
⇒ (5n + 6) (5n - 5)
Now, We can multiply as,
⇒ (5n + 6) (5n - 5)
⇒ 5n × 5n + 5n × - 5 + 6 × 5n + 6 × - 5
⇒ 25n² - 25n + 30n - 30
⇒ 25n² + 5n - 30
Therefore, The solution is,
⇒ 25n² + 5n - 30
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large cylinder: 950.02 m3
B.
small cylinder: 972.14 m3
large cylinder: 12,924.24 m3
C.
small cylinder: 851.22 m3
large cylinder: 13,300.25 m3
D.
small cylinder: 682.95 m3
large cylinder: 13,539.68 m3
Answers
r1 : r 2 = 3 : 1.2
r2 = 1.2 · r1 / 3
r 2 = 0.4 · r1
If the two cylinders are similar than also: h 2 = 0.4 · h 2
V 1 = r1² · π · h1
V 2 = ( 0.4 r1)² π · 0.4 · h1 = 0.064 r1² · π · h1
V 2 ( small cylinder )= 0.064 · V 1 ( large cylinder )
851.22 m³= 13.300.25 m³ · 0.064
Answer: C )
Answer: out of all the available options the one that shows the correct volumes for each cylinder is answer choice C) small cylinder: 851.22 m³ & large cylinder: 13,300.25 m³.
I hope it helps, Regards.
Answers
Step-by-step explanation:
A) width × length = area
300 ft × l = 48000 sq ft
B) l = 48000 ÷ 300
l = 160 ft