Blank divided by 8= 6 remainder 2

Answers

Answer 1

Answer:

Answer:

50/8 = 6 remainder 2.

Step-by-step explanation:

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At a large department store, the average number of years of employment for a cashier is 5.7 with a standard deviation of 1.8 years, and the distribution is approximately normal. If an employee is picked at random, what is the probability that the employee has worked at the store for over 10 years? 99.2% 0.8% 49.2% 1.7%

Answers

Answer:

option 0.8%

Step-by-step explanation:

Data provided in the question:

Mean = 5.7 years

Standard deviation, s = 1.8 years

Now,

P(the employee has worked at the store for over 10 years)

= P(X > 10 years)

= $P (Z > (X-Mean)/(\sigma))$

= $P (Z > (10-5.7)/(1.8))$

= P (Z > 2.389 )

= 0.008447 [from standard z table]

= 0.008447 × 100% = 0.84% ≈ 0.8%

Hence,

the correct answer is option 0.8%

Consider random samples of size 40 from a population with proportion 0.15. (a) Find the standard error of the distribution of sample proportions.
Round your answer for the standard error to three decimal places.
mean=______
standard error=_______
(b) Is the sample size large enough for the Central Limit Theorem to apply?
1. Yes
2. No

Answers

The standard error of the distribution of sample proportions is 0.056 and mean is 0.15.

Yes, the sample size is enough for the Central Limit Theorem to apply.

(a). Given that, size of sample, $n=40$

Proportion, $p=0.15$

In the distribution of sample proportions, mean $\mu=p$

and, standard error = $\sqrt{(p(1-p))/(n) }$

So, mean $\mu=0.15$

Standard error = $\sqrt{(0.15(1-0.15))/(40) }=0.056$

(b). The Central Limit Theorem applies if np > 5 .

$np=40*0.15=6>5$

Thus, the Central Limit Theorem is applied.

Learn more:

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Answer:

a) The mean is 0.15 and the standard error is 0.056.

b) 1. Yes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = (\sigma)/(√(n))$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions p, in samples of size n, the mean is $\mu = p$ and the standard error is $s = \sqrt{(p(1-p))/(n)}$ . The Central Limit Theorem applies is np > 5 and np(1-p)>5.

In this question:

$n = 40, p = 0.15$

(a) Find the mean and the standard error of the distribution of sample proportions.

$\mu = 0.15, s = \sqrt{(0.15*0.85)/(40)} = 0.056$

So the mean is 0.15 and the standard error is 0.056.

(b) Is the sample size large enough for the Central Limit Theorem to apply?

np = 40*0.15 = 6 > 5

np(1-p) = 40*0.15*0.85 = 5.1>5

So yes

Do these ordered pairs represent a function? {(4,1), (5,2), (8,2), (9,8)} *

Answers

Answer:

Yes

Step-by-step explanation:

A function is a set of ordered pairs in which each x-element has only ONE y-element associated with it, but while it may NOT have two y-values assigned to the same x-value, it may have two x-values assigned to the same y-value.

The points (5,2) and (8,2) have the same y value, but their x values are different. It is a function (there are no values of x for which we have more than one value of y).

The volume of an object is given as a function of time by V = A + B t + C t4 . Find the dimension of the constant C

Answers

Answer:

The dimensions of constant C are of $[L^(3)T]^(-4)$

Step-by-step explanation:

It is given that

$V(t)=A+Bt+Ct^(3)$

Since the dimensions of volume are $[L^(3)]$

Each of the term shall have a dimension of $[L^(3)]$ since they are in addition.

Thus for third term we can write

Thus we have

$[L^(3)]=[C][T^(4)]\n\n\therefore [C]=[L^(3)][T^(-4)]$

Roy is 11 years old and his uncle is 59 years old. How many years ago was Roy’s uncle 7 times as old as Roy?

Answers

Answer:

answer : 3 years ago

Step-by-step explanation:

Let x years ago.

59−x=7(11−x)

59−x=77−7x

6x=18

x=3

=3 years ago

Solve for x. round to the nearest tenth.

Answers

tan (angle = Opposite / adjacent

tan(28) = 18/x

x = 18 / tan(28)

x = 33.85

Rounded to nearest tenth X = 33.9

Final answer:

The student correctly solved the equations given for x. Note that an equation with an unknown variable squared might have two solutions. The way to solve for x alters according to what the equation requires, whether it is adding, subtracting, or dividing.

Explanation:

It seems like the student is trying to solve equations for x. The equations given were all solved correctly. Keep in mind that when an equation contains an unknown variable squared, there could be two solutions, and one or both could be reasonable depending on the problem. For example, consider the equation x² +0.0211x -0.0211 = 0. This could be rearranged to solve for x. Other variables are known unless additional calculations needed if they are not.

Remember that the principle of altering the equation to solve for x is employed, whether we add, subtract or divide by certain values. Like mentioned in the information provided, when dividing by powers of 10, you would move the decimal to the left, corresponding to the number of zeros in the power of ten.

Learn more about Solving for x here:

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