What two processes are occurring in this picture A.erosion and deposition
B.weathering and deposition
C.weathering and erosion
What two processes are occurring in this picture A.erosion and - 1

Answers

Answer 1
Answer:

Answer:

C. weathering and erosion

Explanation:


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During an experiment, a student adds 2.90 g CaO to 400.0 mL of 1.500 M HCl . The student observes a temperature increase of 6.00 °C . Assuming that the solution's final volume is 400.0 mL , the density is 1.00 g/mL , and the heat capacity is 4.184 J/g⋅°C , calculate the heat of the reaction, ΔHrxn .

Answers

Answer:

ΔHrxn = 193107.69 J/mol

Explanation:

ΔHrxn = mcΔT

m = mass

c = heat capacity

ΔT = temperature variation

density = m/V

m = density x V

m = 1.00 g/mL x 400.0 mL

m = 400.0 g

ΔHrxn = mcΔT

ΔHrxn = 400 g x 4.184 J/g°C x 6.00 °C

ΔHrxn = 10041.6 J

CaO + 2HCl  → CaCl₂ + H₂O

CaO = 56.0774 g/mol

2.90 g CaO = 0.052 mol

400.0 mL of 1.500 mol/L HCl = 0.6 mol HCl

ΔHrxn = 10041.6 J is for 0.052 mol of CaO

ΔHrxn = 193107.69 J is for 1 mol of CaO

Draw the mechanism of the reaction of N,N-dimethylaniline and the diazonium salt of sulfanilic acid to form the azo dye.

Answers

Answer:

See attachment

Explanation:

The amine group of N,N-dimethylaniline is an electron-donating group and will cause the benzene ring to act as a nucleophile in an electrophilic aromatic substitution reaction with the diazonium salt of sulfanilic acid.

Which of the following is true for the quantum mechanical atomic model? A. Atoms absorb or emit electrons from the nucleus when they interact with electromagnetic radiation.

B. Every atom absorbs all wavelengths of light energy or electromagnetic radiation.

C. Electrons give off electromagnetic radiation when they jump from a high to a low energy level.

D. Electrons are perfectly evenly distributed throughout the atom.​​

Answers

Answer: C. Electrons give off electromagnetic radiation when they jump from a high to a low energy level.

Explanation:

 Electrons give off electromagnetic radiation when they jump from a high to a low energy level in the quantum mechanical atomic model. This is known as the emission spectrum of an atom, and each element has its unique emission spectrum. This phenomenon was explained by the Bohr model of the atom and is a fundamental concept of the quantum mechanical atomic model.

 Option A is incorrect because atoms cannot absorb or emit electrons from the nucleus when they interact with electromagnetic radiation. Option B is also incorrect because atoms only absorb certain wavelengths of light energy or electromagnetic radiation, which corresponds to the energy difference between electron energy levels. Option D is incorrect because electrons are not evenly distributed throughout the atom in the quantum mechanical atomic model; instead, they occupy specific energy levels or orbitals.

1‑propanol ( nn ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure and the mole fraction ( yy ) of the vapor phase of each component in equilibrium with each of the given solutions at 25 °C. P∘prop=20.9 TorrPprop°=20.9 Torr and P∘iso=45.2 TorrPiso°=45.2 Torr at 25 °C. A solution with a mole fraction of xprop=0.243xprop=0.243 .

Answers

Answer:

Piso = 32.17 Torr

Pprop = 5.079 Torr

yprop = 0.1364

yiso = 0.8636

Explanation:

From the question; we can opine that :

  • The mole fraction of isopropanol in a mixture of isopropanol and propanol will be 1.
  • The partial pressure of isopropanol will be its mole fraction multiplied by vapor pressure of isopropanol
  • The partial pressure of propanol will be its mole fraction multiplied by vapor pressure of propanol
  • In the vapor, the mole fraction of propanol will be its partial pressure divided by the sum of the two partial pressures      

NOW;

When xprop = 0.243; xisopropanol will be 1- 0.243 = 0.757

P°iso = 45.2 Torr at 25 °C so

Piso will be 45.2 × 0.757 = 32.17 Torr

Pprop will be 20.9 × 0.243 = 5.079 Torr

yprop = 5.079/(5.079 +32.17) = 0.1364

yiso = 1-0.1364 = 0.8636

A 0.7 ft diameter hole forms in a tank containing butane at 19 atmg and 76 degrees Fahrenheit. Determine the maximum possible mass flow rate through this leak in lb m / min, if the external pressure is 1 atm.

Answers

Answer:

Q = 3,534.4 lbm/s = 212,062 lbm/min

Explanation:

Mass flowrate of discharge or leakage mass flowrate (Q) is given as

Q = AC₀√(2ρgP)

A = Cross sectional Area of leakage = (πD²/4) = (π×0.7²)/4

A = 0.385 ft²

C₀ = discharge coefficient = 0.98 (For maximum discharge flow rate, the flow is turbulent with discharge coefficient within 1% of 0.98)

ρ = density of butane at 76°F = 35.771 lbm/ft³

g = acceleration due to gravity = 32.2 lbm.ft/lbf.s²

P = Gauge Pressure in the tank = (absolute pressure) - (external pressure) = 19 - 1 = 18 atm = 38091.9 lbf/ft²

Q = AC₀√(2ρgP)

Q = (0.385)(0.98)√(2×35.771×32.2×38091.9)

Q = 3,534.4 lbm/s = 212,062 lbm/min

Hope this Helps!!!

1. Write the structural formulas and give IUPAC names for all isorneric alcohols of molecular formulaС4Н9OH​

Answers

Explanation:

Butanol (С4Н9OH)

Structural formula is :-

CH3-CH2-CH2-CH2-OH