Find the measure of the missing angle

Answer:

56

Step-by-step explanation:

The surface area of the pyramid is calculated by the formula B +(1/2) *P*L.

What is a Regular Pyramid?

A regular pyramid is a three dimensional structure with a regular polygon base and all the lateral surfaces are equal.

The surface area of a Regular Pyramid is the sum of the area of the base and the area of the lateral surface.

Surface area of Pyramid =  Area of base + Lateral surface area of the sides

Surface area of Regular Pyramid = B +(1/2) *P*L

Here P is the perimeter of the base and L is the slant height, B is the area of the base.

Therefore, the surface area of the pyramid is calculated by the formula B +(1/2) *P*L.

To know more about Regular Pyramid

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The lateral surface area of a regular pyramid is the sum of the areas of its lateral faces. The total surface area of a regular pyramid is the sum of the areas of its lateral faces and its base. The general formula for the lateral surface area of a regular pyramid is where p represents the perimeter of the base and l the slant height. Example 1:Find the lateral surface area of a regular pyramid with a triangular base if each edge of the base measures 8 inches and the slant height is 5 inches.The perimeter of the base is the sum of the sides.p = 3(8) = 24 inchesThe general formula for the total surface area of a regular pyramid is where p represents the perimeter of the base, l the slant height and B the area of the base. Example 2:Find the total surface area of a regular pyramid with a square base if each edge of the base measures 16 inches, the slant height of a side is 17 inches and the altitude is 15 inches.The perimeter of the base is 4s since it is a square.p = 4(16) = 64 inches The area of the base is s2.B = 162 = 256 inches2T. S. A. = There is no formula for a surface area of a non-regular pyramid since slant height is not defined.  To find the area, find the area of each face and the area of the base and add them.          

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A graph in which points representing values of a variable for suitable values of an independent variable are connected by a broken line.

Example attached!

Answer: (6\sqrt{5})

Step-by-step explanation:

To simplify the expression (\sqrt{125} - \sqrt{25} + \sqrt{5}), we’ll start by simplifying each square root separately:

1. (\sqrt{125} = \sqrt{25 \times 5} = \sqrt{25} \times \sqrt{5} = 5\sqrt{5}).

2. (\sqrt{25} = 5).

Now, substitute the simplified square roots back into the original expression:

[5\sqrt{5} - 5 + \sqrt{5}]

Now, combine the terms with (\sqrt{5}):

[5\sqrt{5} + \sqrt{5} = 6\sqrt{5}]

So, the simplified expression is (6\sqrt{5}).