Determine what information you would need to know in order to use SAS to show that the triangles are congruent

Answers

Answer 1

Answer:

Answer:

Option D

Step-by-step explanation:

We already have two reasons to support two sides. We have the reflexive property and that the base is divided by a midpoint. So we will need an angle.

Also, AC is the median so it divides into two congruent angles and parts

Option D, because the reflexive property is then included in that part

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Question Help The bank statement included bank charges. On the bank reconciliation, this item is:
A.
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Answers

an addition to the balance per bank statement.

The correct answer would be B.

Because its a charge so it would be a deduction from the balance.

Caleb bought groceries and paid \$1.60$1.60dollar sign, 1, point, 60 in sales tax. The sales tax rate is 2.5\%2.5%2, point, 5, percent.What was the price of Caleb's groceries, before tax?

Answers

The price before tax would be 1.60/0.025 which equals $64.

Write a corresponding real-world problem for each equation.1. 0.55x + 4.50 = 0.65x + 3.50

2. 8x + 80 = 4x + 120

Answers

Answer:

It is 2 because it is a math question with the factors on the multipulcation

Step-by-step explanation:

Suppose an interval estimate for the population mean was 62.84 to 69.46. The population standard deviation was assumed to be 6.50, and a sample of 100 observations was used. The mean of the sample was: A. 56.34 B. 62.96 C. 6.62 D. 66.15

Answers

Answer: Option D.

Step-by-step explanation:

The given interval for population mean was 62.84 to 69.46.

The sample mean will be at the midpoint of the interval.

That is: $(\left(62.84+69.46\right))/(2)=66.15$ .

Learn more: brainly.com/question/12049968

Answer:

$\bar X = 69.46-3.31= 66.15$

$\bar X = 62.84+3.31= 66.15$

Because the confidence interval is defined as $(\bar X -ME, \bar X + ME)$

The best option is : D. 66.15

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

$\bar X$ represent the sample mean (variable of interest)

$\mu$ population mean

$\sigma=6.50$ represent the population standard deviation

n=100 represent the sample size

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=6.5)$

The sample mean $\bar X$ is distributed on this way:

$\bar X \sim N(\mu, (\sigma)/(√(n)))$

The confidence interval on this case is given by:

$\bar X \pm z_(\alpha/2)(\sigma)/(√(n))$ (1)

We have a confidence interval given (62.84, 69.46). W ecan find the margin of error for this interval with this:

$ME= (69.46-62.84)/(2)=3.31$

With the margin of error we can find the sample mean with this:

$\bar X = 69.46-3.31= 66.15$

$\bar X = 62.84+3.31= 66.15$

Because the confidence interval is defined as $(\bar X -ME, \bar X + ME)$

The best option is : D. 66.15

Please answer this in two minutes

Answers

Hey there! :)

Answer:

m = 1/2.

Step-by-step explanation:

Find the slope using the slope formula:

$m = \frac{\text{rise}}{\text{run}} = (y_2 - y_1)/(x_2 - x_1)$

Points on the graph we can use are:

(0, 3) and (2, 4)

Plug these into the formula:

$m = (4-3)/(2-0)$

Simplify:

$m = (1)/(2)$

Therefore, the slope is 1/2.

Answer:

1/2

Step-by-step explanation:

Rise over run solution:

choose a point and go 1 unit up and 2 to the right!

hope this helped

HELP PLEZ TRIGONOMETRY!

Answers

$(2 \sin ^(2) \alpha-1)/(\sin \alpha+\cos \alpha) = sin \alpha - cos \alpha$

Solution:

Given that we have to simplify:

$(2 \sin ^(2) \alpha-1)/(\sin \alpha+\cos \alpha)$ ---- eqn 1

We know that,

$sin^2 x = 1 - cos^2 x$

Substitute the above identity in eqn 1

$(2\left(1-\cos ^(2) \alpha\right)-1)/(\sin \alpha+\cos \alpha)$

Simplify the above expression

$(2-2 \cos ^(2) \alpha-1)/(\sin \alpha+\cos \alpha)$

$(1-2 \cos ^(2) \alpha)/(\sin \alpha+\cos \alpha)$ ------- eqn 2

By the trignometric identity,

$(sin x + cos x)(sin x - cos x) = 1-2cos^2 x$

Substitute the above identity in eqn 2

$((\sin \alpha+\cos \alpha)(\sin \alpha-\cos \alpha))/(\sin \alpha+\cos \alpha)$

Cancel the common factors in numerator and denominator

$((\sin \alpha+\cos \alpha)(\sin \alpha-\cos \alpha))/(\sin \alpha+\cos \alpha)=\sin \alpha-\cos \alpha$

Thus the simplified expression is:

$(2 \sin ^(2) \alpha-1)/(\sin \alpha+\cos \alpha) = sin \alpha - cos \alpha$

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Unit Activity: Advanced Functions

The equation of a parabola is given.y=−14x2+4x−19What are the coordinates of the vertex of the parabola?Enter your answer in the boxes.