Find the missing value for each of the following 3 questions 1. 5% of 60 is _____


2. 40% of 500 is _____


3. 75% of 60 is ______

Answers

Answer 1
Answer:

Answer:

1. 3

2. 200

3. 45

Step-by-step explanation:


Related Questions

The following EXCEL tables are obtained when "Score received on an exam (measured in percentage points)" (Y) is regressed on "percentage attendance" (X) for 22 students in a Statistics for Business and Economics course. Regression Statistics Multiple R 0.142620229 R Square 0.02034053 Standard Error 20.25979924 Observations 22 Coefficients Standard Error T Stat P-value Intercept 39.39027309 37.24347659 1.057642216 0.302826622 Attendance 0.340583573 0.52852452 0.644404489 0.526635689 What is the predicted value received on an exam when Percentage Attendance = 70 a. Approximately 63 b. Approximately 2758 c. Approximately 40 d. Approximately 70
Find the general solution of the following equation: y'(t) = 3y -5
How many numbers are between 0 and 4
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I need help asap will give brainiest

7cm is less than or greater than 3in

Answers

7 cm is less than 3 inches. 7 cm = 2.75 inches

Complete the standard form of the equation of a hyperbola that has vertices at (-10, -15) and (70, -15) and one of its foci at (-11, -15).

Answers

Answer:

((x-30)^(2))/(40^(2)) - ((y+15)^(2))/(3^(2)) = 1

Step-by-step explanation:

The equation of the horizontal hyperbola in standard form is:

((x-k)^(2))/(a^(2)) - ((y-k)^(2))/(b^(2)) = 1

The position of its center is:

C(x,y) = \left((-10 + 70)/(2), -15 \right)

C(x, y) = (30,-15)

The values for c and a are respectively:

a = 70 - 30

a = 40

c = 30 - (-11)

c = 41

The remaining variable is computed from the following Pythagorean identity:

c ^(2) = a^(2) + b^(2)

b = \sqrt{c^(2)-a^(2)}

b = \sqrt{41^(2)-40^(2)}

b = 3

Now, the equation of the hyperbola is:

((x-30)^(2))/(40^(2)) - ((y+15)^(2))/(3^(2)) = 1

Answer:

The above answer is correct but the 3 should be a 9

Step-by-step explanation:

Plato

In a manual on how to have a number one song, it is stated that a song must be no longer than 210 seconds. A simple random sample of 40 current hit songs results in a mean length of 241.4 sec. and a standard deviation of 57.59 sec. Use a 0.05 significance level and the accompanying minitab display to test the claim that the sample is from a population of songs with a mean great thatn 210 sec. What do these results suggest about the advice given in the manual.The mini tab displays the following:

One-sample T

Test of mu=210 vs.>210

N Mean St. Dev SE Mean 95% lower bound T p

40 241.40 57.59 9.11 226.06 3.45 0.001

A H0 u>210 sec. H1 u < 210sec

B H0 u=210 sec. H1 u < 210sec

C H0 u<210 sec. H1 u> 210sec

D H0 u=210 sec. H1 u> 210sec

Identify the test statistic:

T =

Identify the P-Value

P-value=

Stat the final conclusion that addresses the original claim. Choose from below:

A. Reject H0. There is insufficient evidence to support the claim that the sample is from a population of songs with a mean length greater than 210 sec.
B. Fail to reject H0. There is insufficient evidence to support the claim that the sample is from a population of songs with a mean length great thatn 210 sec.
C. Reject H0. There is sufficient evidence to spport the claim that the sample is from a population of songs with a mean length greater than 210 sec.
D. Fail to reject H0. There is sufficient evidence to support the claim tha tthe sample is from a population of songs with a mean lenght greater than 210 sec.

What do the results suggest about the advice given in the manual?

A. The results do not suggest that the advice of writing a song that must be no longer than 210 seconds is not sound advice.
B The results suggest that the advice of writing a song that must be no longer than 210 seconds is not sound advice
C. The results suggest that 241.4 seconds is the best song lenght.
D. The results are inconclusive because the average length of a hit song is constantly changing.

Answers

Answer:

D H0 u=210 sec. H1 u> 210sec

t=(241.4-210)/((57.59)/(√(40)))=3.448    

p_v =P(t_((39))>3.448)=0.000684  

C. Reject H0. There is sufficient evidence to spport the claim that the sample is from a population of songs with a mean length greater than 210 sec.

Step-by-step explanation:

Data given and notation  

\bar X=241.4 represent the sample mean

s=57.59 represent the sample standard deviation for the sample  

n=40 sample size  

\mu_o =210 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is greater than 210 seconds, the system of hypothesis would be:  

Null hypothesis:\mu \leq 210  

Alternative hypothesis:\mu > 210  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=(\bar X-\mu_o)/((s)/(√(n)))  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=(241.4-210)/((57.59)/(√(40)))=3.448    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_((39))>3.448)=0.000684  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v<\alpha so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than 210 seconds.  

C. Reject H0. There is sufficient evidence to spport the claim that the sample is from a population of songs with a mean length greater than 210 sec.

Make sure you complete the work for EACH triangle and answer whether or not it is a right triangle. * If you do this correctly I'll give you 50 points.

Answers

I believe that triangle B and E are right triangles.

What are the zeros of the quadratic function f (x) = 2x^2 -10x-3?

Answers

Answer:

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

Step-by-step explanation:

1. Need to factor or can use the quadratic formula

2x^2-10x-3=0

a=2, b=-10, c=-3

[-b+-sqrt(b^2-4*a*c)]/(2*a)

[10+-sqrt(100-4*(-200)]/4

[10+- sqrt(300)]/4

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

Is this one correct?​

Answers

Answer:

do you expect me to flip sideways just to help you cheat on ur homework

Step-by-step explanation:

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