Write the equation of the chemical reaction of burning glucose (C6H12O6)
Answers
Answer:
C6H12O6 + 6O2 → 6CO2 + 6H2O.
Explanation:
Answer:
please see below
Explanation:
the chemical formula of glucose is C6H12O6
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Answers
the sand, salt, and water from each other?
(1) Evaporate the water, then filter out the salt.
(2) Evaporate the water, then filter out the sand.
(3) Filter out the salt, then evaporate the water.
(4) Filter out the sand, then evaporate the water.
Answers
Answer is (4).
Explanation:
The given mixture contains an insoluble solid and an aqueous solution of salt. The insoluble solid is sand.
First we have to separate insoluble solid. Sand can be separated by doing filtration. When we filter the mixture sand can be seen as the residue on the filter paper.
After filtering the mixture, we should collect the filtrate. Filtrate is the salt solution. By doing evaporation we can get the solid salt.
First and second choices are wrong because after evaporating water filtrationcannot be done and salt and sand will be mixed together.
Salt cannot befiltered out because the salt is soluble and it is inaqueous medium. Hence, third choice is wrong
Answers
Considering the definition of molar mass and molarity, the volume of each compound is:
- NaCl= 0.1355 L
- C₂H₆O = 0.0622 L
- CH₃COOH = 0.047 L
Definition of molar mass
The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
Definition of molarity
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
Molarity is expressed in units.
Volume required
You know that the molar mass of each compound is:
- NaCl = 58.44 g/mol
- C₂H₆O = 46.06 g/mol
- CH₃COOH = 60.0 g/mol
On the other side, you know that the mass of each compound is:
- NaCl = 2.14 g
- C₂H₆O = 4.30 g
- CH₃COOH = 0.85 g
Then, considering the definition of molar mass, the amount of moles of each compound is:
- NaCl =
= 0.0366 moles
- C₂H₆O =
= 0.0933 moles
- CH₃COOH =
= 0.0141 moles
The molarity of each compound is:
- NaCl = 0.27 M
- C₂H₆O = 1.50 M
- CH₃COOH = 0.30 M
Considering the molarity, the volume of each compound is calculated as:
- NaCl =
= 0.1355 L
- C₂H₆O =
= 0.0622 L
- CH₃COOH =
= 0.047 L
Learn more about
molar mass:
molarity:
number of moles : 2.14 / 58.44 = 0.0366 moles
V = n / M => 0.0366 / 0.270 = 0.1355 L
__________________________________________
b) C2H6O = 46.06 g/mol
number of moles : 4.30 / 46.06 = 0.0933 moles
V = n / M => 0.0933 / 1.50 = 0.0622 L
___________________________________________
c) CH3COOH = 60.0 g/mol
number of moles : 0.85 / 60.0= 0.0141 moles
V = n / M => 0.0141 / 0.30 = 0.047 L
___________________________________________
hope this helps!
Answers
Given:
12.0 M HCl
2.0 liters of a 3.0 M HCl
Required:
volume of concentrated hydrochloric acid
Solution:
M1V1 = M2V2
(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)
V1 = (3.0 M HCl)( 2.0 liters)/ (12.0 M HCl)
V1 = 0.5 liters
Answers
(2) melting and evaporating
(3) condensation and sublimation
(4) condensation and deposition
Answers
Melting and evaporating are the physical changes that are endothermic. Therefore, the correct option is option 2.
Physical modifications are those that modify a chemical substance's shape yet do not affect its chemical content. Physical changes may normally be utilised to separate compounds to chemical elements and simpler compounds, but they cannot be utilised for separate mixtures to their individual components. When something changes physically but not chemically, it is said to have undergone a physical transformation. This contrasts to the idea of a chemical change, when a material's composition changes or a substance or substances mix or separate to generate new compounds. Melting and evaporating are the physical changes that are endothermic.
Therefore, the correct option is option 2.
To know more about physical change, here:
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