Erica (39 kg ) and Danny (46 kg ) are bouncing on a trampoline. Just as Erica reaches the high point of her bounce, Danny is moving upward past her at 4.6 m/s . At that instant he grabs hold of her.

Answers

Answer 1
Answer:

Answer:

V = 2.79 m/s

Explanation:

Momentum before = momentum after

Erica's momentum = 0

Danny momentum = 49 kg * 4.9 m/s = 240.1 kg-m/s

240.1 + 0 = (37 + 49) kg * V

86 V = 240.1

V = 2.79 m/s


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1. What causes tides?A. The energy generated by waves.
B. The changes in Earth's climate.
C. The gravitational pull of the Sun on Earth's oceans.
D. The gravitational pull of the Moon on Earth's oceans.

Answers

Answer:

D.) The gravitational pull of the Moon on Earth's oceans.

Explanation:

A.) is incorrect because waves caused by the moon's gravitational pull. Waves and tides are essentially the same thing.

B.) is incorrect because climate change only has a small, indirect effect on the tides (i.e., rising sea levels).

C.) is incorrect because while the gravitational pull of the Sun affects the tides to some extent, it is nowhere near as influential as the Moon's gravitational pull.

D.) is correct because the gravitational forces between the Moon and the Earth are the primary cause of the tides.

it is letter d! :).

NASA decides to put a 128 kg satellite into orbit over the planet Venus because they want to take pictures. The satellite is 37,000,000 m above the surface of venus. Calculate the gravitational field at that altitude. m/s2
how do you calculate this

Answers

1).  Look up the acceleration of gravity on the surface of Venus.  It's 8.87 m/s².
(That's about 10% less than on Earth.)

2).  Look up the radius of Venus.  It's 6051.8 km.  
(That's about 5% less than Earth's.)

3).  Remember that the gravitational field (acceleration, force) changes
opposite to the square of the distance from the planet ... or the distance
between any two masses that are gravitating.

Now we have enough information to do the calculating.  Notice that the question
only asks for the planet's "gravitational field" (acceleration) way out there.  That
has nothing to do with the satellite's mass, or whatever you decide to put out there,
or even if there's nothing out there at all.  It's just a characteristic of Venus at that
distance from it.

The distances we need to compare are the distances from the center of Venus.

On the surface (distance from the center is the radius of Venus), it's 6,051,800 m.
In the orbit, it's 37,000,000 m.

The ratio is (37,000,000 / 6,051,800) = about 6.1 .

The gravity way out in the orbit is less than on the surface, and by the
same amount as the square of the distance ratio.

Surface gravity = 8.87

Gravity out at the orbit = 8.87 divided by (the distance ratio)²

Gravity = 8.87 / (6.1)²

Better way:  Gravity = 8.87 x (6,051,800/37,000,000)² = 0.2373 m/sec²

Which of the following statements are true?A. Energy as heat flows from a lower temperature to a higher temperature
B. Energy as heat flows from a higher temperature to a lower temperature
C. The amount of het in a closed system is constant
D. Energy as heat flowing into an object is determined by the amount of work done on the object.

I know the answer is not C.

Answers

'B' and 'C' are both true.
B. Energy as heat flows from a higher temperature to a lower temperature.

Two polarizers are arranged as shown. How much light will reach point X?0%
more than 50% but less than 100%
50%
less than 50% but more than 0%
100%

Answers

Answer:

50% if light is unpolarized

100% if light is horizontally polarized

0% if light is vertically polarized

Explanation:

A polarizer has an axis that "blocks" the component of light in the direction perpendicular to the direction of the polarizer axis.

When unpolarized light passes through a polarizer, the intensity of light is reduced to (I_0)/(2), where I_0 is the initial intensity of the light: this is because only the component of the light parallel to the axis of the polarizer will pass through, and this component makes 1/2 of the incident light intensity. In this case, since the axis of the polarizer is horizontal, only the horizontal component of the light will pass through, while the vertical component will be blocked. So in this case the final intensity will be 50% of the initial one.

On the other hand, if the incoming light is already horizontally polarized (same orientation as the polarizers), there is no vertical component to block, so all the light passes through the polarizer; therefore, the final intensity will be 100% of the original intensity.

Finally, if the incoming light is vertically polarized, no light will pass through it, because the polarizer's axis is horizontal, so it will block all the vertically polarized light: so the final intensity will be 0% of the original intensity.

All of this is after passing the 1st polarizer; so, after passing the 1st polarizer, the light is now horizontally polarized. Then, the intensity of the light passing through the 2nd polarizer is given by Malus' Law:

I=I_0 cos^2 \theta

where \theta is the angle between the axes of the two polarizers. Since here the two polarizers axes are parallel to each other, \theta=0, so cos \theta=1, and so the intensity after the 2nd polarizer is exactly the same as the intensity after the 1st polarizer.

Formed when wind travels into a low pressure area from opposite directions and creates a spinning storm

Answers

Tornadoes are formed when wind travels into a low pressure area from opposite directions and creates a spinning storm. The tornado comes in contact to the earth’s ground and to the clouds (usually cumulus cloud) having a smaller cross sectional area at the ground than on the sky.

Tornado is your answer.

A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation x = 0.5 sin (pt+p/3). The acceleration (in m/s2) of the body at t = 1.0 s is approximatelya. 3.5
b. 49
c. 14
d. 43
e. 4.3

Answers

I'll tell you how I look at this, although I may be missing something important.

Position = x(t) = 0.5 sin(pt + p/3)

Speed = position' = x'(t) = 0.5 p cos(pt + p/3)

Acceleration = speed' = position ' ' = x ' '(t) = -0.5 p² sin(pt + p/3)

At (t = 1.0),

x ' '(t) = -0.5 p² sin( 4/3 p )

In order to evaluate this, don't I still have to know what 'p' is ? ?

I don't think it can be evaluated with the information given in the question.