How can I get the 3 sig figs of this number 187515.4207

Answer:

Skin

Explanation:

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Each line represents a single bond (two electrons), and the lone pairs of electrons are shown as dots. Carbon forms single bonds with three hydrogen atoms and one bromine atom, resulting in a stable Lewis structure that satisfies the octet rule for each element and minimizes formal charges.

To draw the Lewis electron-dot diagram for bromomethane (CH3Br), follow these steps:

Determine the total number of valence electrons for each element in the molecule:

Carbon (C) has 4 valence electrons.

Hydrogen (H) has 1 valence electron.

Bromine (Br) has 7 valence electrons.

Calculate the total number of valence electrons by adding the contributions from each element:

Carbon: 4 electrons x 1 atom = 4 electrons.

Hydrogen: 1 electron x 3 atoms = 3 electrons.

Bromine: 7 electrons x 1 atom = 7 electrons.

Total = 4 + 3 + 7 = 14 electrons.

Determine the central atom. In CH3Br, carbon is the central atom.

Connect the central carbon atom to the surrounding hydrogen and bromine atoms using single bonds (each bond consists of two electrons).

Distribute the remaining valence electrons as lone pairs on the outer atoms to satisfy the octet rule. Hydrogen can only accommodate two electrons (a duet), and bromine can expand its octet.

Calculate the formal charges to ensure that the Lewis structure represents the most stable arrangement of electrons. In CH3Br, the formal charges should ideally be as close to zero as possible.

For more such question on electrons visit:

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Final answer:

The percent by mass of carbon in acetic acid (HC2H3O2) is calculated using the molar masses of its constituent elements. Upon calculation, it is determined that the percent by mass of carbon in acetic acid is 40.00%.

Explanation:

To calculate the percent by mass of carbon in acetic acid (HC2H3O2), we need to use the molar masses of the elements involved. The formula for acetic acid includes two carbon atoms, four hydrogen atoms, and two oxygen atoms. Using the given molar masses (carbon: 12.01 g/mol, hydrogen: 1.008 g/mol, oxygen: 16.00 g/mol), the molar mass of acetic acid can be calculated as follows:

• Carbon: 2 × 12.01 g/mol = 24.02 g/mol
• Hydrogen: 4 × 1.008 g/mol = 4.032 g/mol
• Oxygen: 2 × 16.00 g/mol = 32.00 g/mol

Adding these together gives the molar mass of acetic acid as 60.052 g/mol.

To find the percent by mass of carbon, we take the total mass of carbon in the compound and divide it by the total molar mass of the compound:

(24.02 g/mol / 60.052 g/mol) × 100% = 40.00%

Therefore, the percent by mass of carbon in acetic acid is 40.00%.

Explanation:

General Rules. In general, the electropositive character of the oxide's central atom will determne whether the oxide will be acidic or basic. The more electropositive the central atom the more basic the oxide. The more electronegative the central atom, the more acidic the oxide.

Answer : (C) 854.46 KPa.

Solution : Given,

Initial pressure = 400 KPa

Initial temperature = 110 K

Final temperature = 235 K

According to the Gay-Lussac's law, the absolute pressure is directly proportional to the absolute temperature at constant volume of an ideal gas.

P  ∝  T

Formula used :  

where,

= initial pressure

= final pressure

= initial temperature

= final temperature

Now put all the values in above formula, we get

By rearranging the terms, we get the value of new/final pressure.

= 854.5454 KPa 854.55 KPa