HELP ME AGAIN FOR BRAINLIEST
muhyj15 avatar

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Answer 1
Answer:

Answer:

1: C

2: a

3: B

4: D

hope this helps


Related Questions

The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with water is __________ kJ. 2Na2O2(s) + 2H2O(l) → 4NaOH(s) + O2(g) The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with water is __________ kJ. 2Na2O2(s) + 2H2O(l) → 4NaOH(s) + O2(g) 40.4 80.8 -126 67.5 20.2
The interaction of tectonic plate boundaries is associated with which of the following events? Hurricanes Tropical storms Earthquakes Tornados Previous Question
This is the metric unit for measuring volume
The difference in the direction is caused by the ______________.Please help!
Describe the difference between the terms “element”, “compound”, “molecule”, and “salt”.

What are metalloids? Give examples.​

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Answer:

Metalloids:

Elements with properties intermediate between metals and nonmetals are known as metalloids.

Examples:

  • Germanium
  • Arsenic
  • Tellurium
  • Boron

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Hope it helps!

Have a good day!

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If the reaction is at dynamic equilibrium at 500 K, which statement applies to the given chemical system?The forward and reverse reactions no longer occur.
The rates of the forward and reverse reactions are unequal.
The concentrations of the products and reactants do not change.
The forward reaction stops at 500 K.

Answers

The correct option is this: THE CONCENTRATION OF THE PRODUCTS AND THE REACTANTS DO NOT CHANGE.

A reversible chemical reaction is said to be in equilibrium if the rate of forward reaction is equal to the rate of backward reaction. At this stage, the concentrations of the products and the reactants remain constant, that is, there is no net change in the concentration even though the reacting species are moving between the forward and the backward reaction.

If the reaction is at dynamic equilibrium at 500 K, the statement that applies to the given chemical system is The concentrations of the products and reactants do not change.

What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl?

Answers

First you need to find the balanced chemical formula.
CuCl₂+2NaNO₃→2NaCl+Cu(NO₃)₂

Then you can find out how much NaCl 31.0g of CuCl₂ should produce using stoichiometry.  Divide 31.0g by the molar mass of CuCl₂ (134.446g/mol) to get 0.2306mol CuCl₂.  Than multiply 0.2306mol CuCl₂ by 2 to get 0.4612mol NaCl.  Than multiply 0.4612mol by the molar mass of NaCl (58.45g/mol) to get 26.95g of NaCl.
that means that 100% yield would give you 26.95g of NaCl so to find percent yield divide 21.2 by 26.95 to get 0.7867 which is 78.7% yield

Therefore the answer is 78.7% yield.
I hope this helps.  Let me know if anything is unclear

What parts of the cell are used to connect an electrochemical cell to a circuit?

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I think it's the Terminals

A solution has a [OH-] = 8.6 x 10-5. Answer the following questions.

pOH =
pH =
[H+] =

Answers

Answer: pOH= 4.06

pH= 9.94

[H^+]=1.14* 10^(-10)M

Explanation: pOH is the negative logarithm of OH^- concentration.

pH is the negative logarithm of H^+ concentration.

pOH=-log[OH^-]

pOH=-log[8.6* 10^(-5)]=4.06

2) pH+pOH=14

pH=14-4.06

pH=9.94

3) pH=-log[H^+]

9.94=-log[H^+]

[H^+]=1.14* 10^(-10)M

pOH = 4
pH = 10
[H+] = 1 X 10^-10

How many moles of magnesium oxide are there in 2.50* 10^25 formula units of MgO?

Answers

just divide 2.50*10^25 by 6.02×10^23 to get to moles
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