3) g(x) = 4x
h(x) = -3x^2 + 4
Find (g + h)(x)

Answers

Answer 1
Answer:

Answer:

The answer is the last line below.

Step-by-step explanation:

g(x) = 4x

h(x) = -3x^2 + 4

(g + h)(x) = 4x - 3x^2 + 4


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A new homeowner is mulching a flower bed in his back yard. The flower bed is 9 feet long and 3.5 feet wide. How many square feet will be needed to cover it in mulch?

Answers

Answer:

31.5ft²

Step-by-step explanation:

Formula for area:

Area = Length * Width

Calculate area by substituting in known values

Area = 9 * 3.5

Area = 31.5ft²

31.5ft²

Hope this helps :)

Plz helpp


I’ll mark you brainliest

Answers

Answer:52°

Step-by-step explanation:

x+x+14=90

Collect like terms

x+x=90-14

2x=76

Divide both sides by 2

2x/2=76/2

x=38

angle (x+14)°=(38+14)°=52° which is vertically opposite to angle PKQ.

Since Vertically opposite angles

Therefore angle PKQ=52

Write an inequality for a game that allows 2 and not more than 4 players

Answers

Answer:

2≤x≤4

Step-by-step explanation:

2 is less than/equal to x; x is less than/equal to 4

What is 10 squared then the cube root of that

Answers

100cubed is 1,00,000

Find a generating function for the sequence of squares: g(x) = P∞ n=0 n 2x n . Then for fun, as above evaluate your expression g(1/100) or g(1/1000) to get a fraction that contains the squares in its decimal expansion.

Answers

The sequence of squares, \{n^2\}_(n\ge0), has generating function

g(x)=\displaystyle\sum_(n=0)^\infty n^2x^n

Recall that for |x|<1,

f(x)=\frac1{1-x}=\displaystyle\sum_(n=0)^\infty x^n

Taking the derivative, we have

f'(x)=\frac1{(1-x)^2}=\displaystyle\sum_(n=0)^\infty nx^(n-1)=\frac1x\sum_(n=0)^\infty nx^n

and taking the derivative again, we have

f''(x)=\frac2{(1-x)^3}=\displaystyle\frac1x\sum_(n=0)^\infty n^2x^(n-1)-\frac1{x^2}\sum_(n=0)^\infty nx^n

f''(x)=\frac2{(1-x)^3}=\displaystyle\frac1{x^2}\left(\sum_(n=0)^\infty n^2x^n-\sum_(n=0)^\infty nx^n\right)

From this we can get an expression for g(x) in terms of the derivatives of f(x):

f''(x)=(g(x)-xf'(x))/(x^2)

\implies g(x)=x^2f''(x)+xf'(x)

\implies g(x)=(2x^2)/((1-x)^3)+\frac x{(1-x)^2}

\implies\boxed{g(x)=(x^2+x)/((1-x)^3)}

Then

g\left(\frac1{100}\right)=(10,100)/(970,299)\approx0.\underline{01}\,\underline{04}\,\underline{09}\,\underline{16}\ldots

g\left(\frac1{1000}\right)=(1,001,000)/(997,002,999)\approx0.\underline{001}\,\underline{004}\,\underline{009}\,\underline{016}\ldots

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Answers

Answer:

The correct answer is 2.75

Step-by-step explanation:

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The correct awnser is b I think