PHYSICS HIGH SCHOOL

Which of the following is true about light with a single wavelength?1) It can be refracted
II) It cannot be dispersed
III) It can be reflected *

Answers

Answer 1
Answer:

Answer:

It can be refracted

Explanation:

When a single wavelength wave which is known as a monochromatic light is passed from one transparent medium to the other, it can refract. This refraction can only be seen if the light enter the medium at some angle.

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a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m find the effort applied to balance the load​
A car that travels from point A to point B in four hours, and then from point B back to point A in six hours. The road between point A and point B is perfectly straight, and the distance between the two points is 240 km. What is the car’s average velocity?

Slick Willy is in traffic court (again) contesting a $50.00 ticket for running a red light. "You see, your Honor, as I was approaching the light, it appeared yellow to me because of the Doppler effect. The red light from the traffic signal was shifted up in frequency because I was traveling towards it, just like the pitch of an approaching car rises as it approaches you." a. Calculate how fast Slick Willy must have been driving, in meters per second, to observe the red light (wavelength of 687 nm) as yellow (wavelength of 570 nm). (Treat the traffic light as stationary, and assume the Doppler shift formula for sound works for light as well.)

Answers

Answer:

6.11*10^7m/s

Explanation:

The Doppler effect formula for an observer approaching a source is given by equation (1);

f_o=(f(v+v_o))/(v-v_s)...................(1)

where f_o is the frequency perceived by the observer, v is the actual velocity of the wave in air, v_o is the velocity of the observer, v_s is the velocity of the source and f is the actual frequency of the wave.

The actual velocity v of light in air is 3*10^8m/s. The relationship between velocity, frequency and wavelength \lambda is given by equation (2);

v=\lambda f...........(2)

therefore;

f=(v)/(\lambda)...............(3)

We therefore use equation (3) to find the actual frequency of light emitted and the frequency perceived by Slick Willy.

Actual wavelength \lambda of light emitted is 678nm, hence actual frequency is

given by;

f=(3*10^8)/(687*10^(-9))\nf=4.37*10^(14)Hz

Also, the frequency perceived by Slick Willy is given thus;

f_o=(3*10^8)/(570*10^(-9))\nf=5,26*10^(14)Hz

The velocity v_s of the source light is zero since the traffic light was stationary. Substituting all parameters into equation (1), we obtain the following;

5.26*10^(14)=(4.37*10^(14)(3*10^(8)+v_o))/(3*10^8-0)

We then simplify further to get v_o

10^(14)  cancels out from both sides, so we obtain the following;

5.26*3*10^8=4.37(3*10^8+v_o)

15.78*10^8=13.11*10^8+4.37v_o\n4.37v_o=15.78*10^8-13.11*10^8\n4.37v_o=2.67*10^8

Hence;

v_o=(2.67*10^8)/(4.37)\nv_o=6.11*10^7m/s

Answer:

61578948 m/s

Explanation:

λ_(actual) = λ_(observed)(c+v_(o))/(c)

687 = 570 ((3 * 10^(8) +v_(o) )/(3 * 10^(8)) )

v_(o) = 61578948 m/s

So Slick Willy was travelling at a speed of 61578948 m/s to observe this.

How was Bohr's atomic model different from those of previous scientists?

Answers

Answer:Bohr placed the electrons in distinct energy levels.  Rutherford described the atom as consisting of a tiny positive mass surrounded by a cloud of negative electrons. Bohr thought that electrons orbited the nucleus in quantised orbits.

Explanation: also rutherfords was just a hypothesis while Bhor took the time to make his an experiment

ingrid kicks a football with an initial velocity of 12 m/s at an angle 45 relative to the ground. what is the horizontal component of the initial velocity to the nearest tenth

Answers

Let's assume that the coordinate system is defined as positive in the first quadrant.

The system has its origin in the place where Ingrid kicks the football ball.

We have then that the horizontal component is given by:

Rewriting we have:

Rounding the obtained result we have:

x = 8.5 (m)/(s)

Answer:

The horizontal component of the initial velocity to the nearest tenth is:

x = 8.5 (m)/(s)

is correct answer => 8.5 m/s

What was the rule of the sticks on each atom model​

Answers

Answer:

That they must die

Explanation:

Stick = Die
Answer: That they must die


Excellent

A train moves at a constant velocity of 90 km/h. How far will it move in 0.25h?
​

Answers

In 0.25h it will move in 22.5 kilometers.

The law of suggests that the orbit of planets is not circular but .

Answers

Answer:

Kepler's first law suggests that the orbit of planets is not circular but elliptical

Explanation:

The three Kepler's laws explain the motion of the planets orbiting the Sun:

- The first law tells that the orbits of the planets around the Sun are ellipses, with the Sun located at one of the two focii

- The second law tells that a line connecting the Sun with the planet sweeps out equal areas in equal amounts of time

- The third law tells that the square of the orbital periods of the planets is proportional to the cube of their average distance from the Sun

As we can read, the first law tells us that the orbit of the planets is not circular, but elliptical.
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