PHYSICS HIGH SCHOOL

Elements that are what tend to be in the what state at room temperature.

Answers

Answer 1
Answer:

Answer:

hot

Explanation:

cause the room temperature is higher

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What do the stars in the main sequence have in common

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The following lists of stars in order from least density to greatest density are giant, main sequence star, white dwarf, neutron star. Aside from neutron star being the densest star, it is also the smallest star compared to the giant star, as its name implied.

Which of the following changes would make a heat engine less efficient

Answers

A heat engine would be less efficient due to many factors 
For instance, a heat engine is more efficient when it uses in cold weather because there is a greater temperature difference ( Carnot Efficient )
A heat engine could be less efficient because of friction
Hope it helps I am a beginner

In the series circuit below the power source is a 9-volt battery and three resistors are R1 = 7 ohm, R2 = 9 ohm and R3 = 2 ohm. What is the total resistance in the series circuit? R1 7 ohm + R2 9 ohm + R3 2 ohm = 18
Is this correct?

Answers

Yes indeed. You're on your way. In a series circuit, the total resistance is the sum of the individuals no matter what order they're in. Now, if the question goes on to ask what is the current in the circuit, that will be the source voltage divided by the total resistance that you have calculated.

Is paper a good water absorbent ?

Answers

paper is not a good water absorbant.

A car that is initially moving to the right with a velocity of 4 m/s is pushed by a -5 N force as it moves from 5 meters to 20 meters. How much work is done to the car by this force?

Answers

Answer:

the work done on the car by the applied force is 75 J.

Explanation:

Given;

initial velocity of the car, v = 4 m/s

applied force in opposite direction, F = 5N

initial position of the car, x₀ = 5 m

final position of the car, x₁ = 20 m

displacement of the car, Δx = x₁ - x₀ = 20 m - 5m

                                                            = 15 m

The work done on the car by the applied force is calculated as follows;

W = F.Δx

W = 5 x 15

W = 75 J

Therefore, the work done on the car by the applied force is 75 J.

Two objects with different masses collide and bounce back after an elastic collision. Before the collision, thetwo objects were moving at velocities equal in magnitude but opposite in direction. After the collision,
A. the less massive object had gained momentum.
B. the more massive object had gained momentum.
C. both objects had the same momentum.
D. both objects lost momentum.

Answers

The more massive object will lose momentum after collision while the less massive object will gain momentum after collision.

  • Let the mass of the first object = m₁
  • Let the mass of the second object = m₂
  • let the initial velocities of the two objects = u
  • let the final velocity of the first object after collision = v₁
  • Let the final velocity of the second object after collision = v₂

Apply theprinciple of conservation of linear momentum for elastic collision;

let the heavier object = m₁

m₁u + m₂(-u) = m₁(-v₁) + m₂v₂

m₁u  - m₂u = -m₁v₁ + m₂v₂

where;

m₁u and m₂u  are initial momentum of both objects before collision

m₁v₁ and  m₂v₂ are final momentum of both objects after collision

Thus, from the equation above we can conclude the following, the more massive object will lose momentum after collision while the less massive object will gain momentum after collision.

Learn more here:brainly.com/question/11214803

Answer:A

Explanation:

Given

mass of two objects are  m_1 and m_2

taking m_1>m_2

Suppose u_1  and  u_2 are the velocities of m_1 and

u_1=u and  u_2=-u

therefore after elastic collision velocity of m_1 and m_2/[tex] are [tex]v_1 and v_2

v_1=(m_1-m_2)/(m_1+m_2)\cdot u_1+(2m_2)/(m_1+m_2)\cdot u_2

v_2=(2m_1)/(m_1+m_2)\cdot u_1-(m_1-m_2)/(m_1+m_2)\cdot u_2

for u_1 and u_2

v_1=(m-m)/(m+m)\cdot u+(2m)/(m+m)\cdot (-u)

v_1=(m_1+m_2)/(m_1+m_2)\cdot u=u

v_2=(2m)/(m+m)\cdot u-(m-m)/(m+m)\cdot (-u)

v_2=(3m_1-m_2)/(m_1+m_2)\cdot u

v_2=u+2\cdot (m_1-m_2)/(m_1+m_2)\cdot u

so velocity of mass m_2 is more as compared to m_1

so less massive object gained some momentum
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