Helpp hurry plzzz!! Which is an equation of the line parallel to 4y - 7x = 8 and passes through (-4, 0)?

A. y = 7/4x + 7
B. y = - 7x - 28
C. y = - 7/4x - 7
D. y = 7x + 28

Answer:

A. y = 7/4x + 7

Step-by-step explanation:

y = mx +c

4y -7x = 8

(make y the subject of formulae)

4y = 8 + 7x

divide through by the coefficient of y (4)

y = 2 + 7/4x

7/4 = m1

since the line is parallel m1 = m2

let see :{y -y¹}÷ {x-x1} = 7/4

x¹= -4 , y¹ = 0

{y - 0} ÷ {x- (-4) } = 7/4

cross multiply

4(y - 0) = 7(x+4)

4y - 0 = 7x + 28

4y = 7x +28 +0

4y = 7x + 28

(divide both sides by the coefficient of y)

y = 7/4x +28/4

y = 7/4x + 7