What formulas can be used to find a triangular prism

Answers

Answer 1

Answer: the formula to find a triangular prism is V = 0.5 X b X a X h

Related Questions

find the area of a triangle with the following dimensions: a = 12 yards b=16 yards and c=24 yards round to the nearest square yard
Lia wants to estimate 4 1/7 x 3 3/5 To estimate, she simplifies the expression 4 x 3 1/2 .Is Lia’s estimate a close estimate, an underestimate, or an overestimate? A.underestimate B.overestimate C.close estimate
Find the slope of the line containing the points whose coordinates are (2, 3) and (4, 3).
Carl has three lengths of cable,5/6 yard long,1/4 yard long and 2/3 yard long.he needs at least one yard of cable. Which two pieces together Make a k Length at least 1 yard and closest to one yard
Factor the expression given below. Write each factor as a polynomial indescending order. Enter exponents using the caret (^). 125x^3+343y^3

What is the value of x?

Answers

Answer:

x=70

Step-by-step explanation:

Since they are supplementary angles (180°)

45° + (2x-5)° = 180°

(2x-5)° = 180° - 45°

(2x-5)° = 135°

2x° = 135° + 5°

2x° = 140°

x° = 140/2°

x° = 70°

Since they are supplementary angles (180°)

45° + (2x-5)° = 180°

(2x-5)° = 180° - 45°

(2x-5)° = 135°

2x° = 135° - 5°

2x° = 130°

x° = 130/2°

x° = 65°

The hypotenuse AB of a right triangle ABC is 5 ft, and one leg, AC, is decreasing at the rate of 2 ft/sec. The rate, in square feet per second, at which the area is changing when AC = 3 is?

Answers

Answer: $-(7)/(4) \quad \text{ft}^(2)/\sec$

Step-by-step explanation:

Since ABC is a right triangle, at any moment it holds that

$5^2=(AC)^2+(BC)^2$

Moreover, the area A of the triangle is given by

$A= (1)/(2)(AC)(BC)$

and we know that the rate of change of the length (AC) is

constant decreasing 2, which may be written using the Leibniz

notation as

$(d(AC))/(dt)=-2$ .

Using the chain rule and the product rule for derivation, the two

first equations tell us

that

$0 = 2 (d(AC))/(dt)(AC) + 2 (d(BC))/(dt)(BC)$

and

$(dA)/(dt) = (1)/(2) \left( (d(AC))/(dt) \cdot (BC) + (d(BC))/(dt) \cdot (AC)\right)$

Moreover, using the first of the last two equations we get

$(AC)(d(AC))/(dt) = -(BC)(d(BC))/(dt) \Rightarrow\n\n\n(AC)(-2) = -(BC) (d(BC))/(dt) \quad \Rightarrow \quad (d(BC))/(dt)=2 ((AC))/((BC))$

Now, when (AC)=3, we have that

$25=(AC)^2 + (BC)^2 \quad \Rightarrow 25 = 9 + (BC)^2\n \n\Rightarrow \quad 16=(BC)^2 \quad \Rightarrow (BC)=4$

and

$(d(BC))/(dt) = 2 ((AC))/((BC))=2 (3)/(4)=(3)/(2)$ .

Hence, at this moment the rate of change of the area of the triangle is

$(dA)/(dt) = (1)/(2) \left( (d(AC))/(dt) \cdot (BC) + (d(BC))/(dt) \cdot(AC) \right)=(1)/(2)\left( -2 \cdot 4 + (3)/(2)\cdot 3\right ) = -(7)/(4)$

okay
we have the rate of change of AC = d(AC)/dt = -2
the rate of change od BC = d(BC)/dt
area = (1/2) *AC) (BC)
taking differential on both sides we ge
d(A)/dt = 1/2){ (BC) d(AC)/dt + (AC) d(BC)/dt)}....(1)
again
when AC= 3
applying pythagorous thm
we get
(5)^2 =(3)^2 +(BC)^2
hence we get BC = 4
now we need to find d(BC)/dt
we have
(5)^2 = (AC)^2 +(BC)^2
taking differenial
0=2(AC) d(AC/dt) +2BC d(BC)/dt
that is
d(BC)/dt = -(3) *(-2)/4 ..(at AC =3)
hence
d(BC)/dt = 3/2
substituting these values in equation (1)
d(A)/dt = (1/2) {4 * -2 + 3 *3/2}

which gives
d(A)/dt = -7/4

The rate, in square feet per second, at which the area is changing when AC = 3 is -7/4 ft/sec.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

Write the equation for each transformation of f(x)= |x| described below.a. translate left 9 units, stretch vertically by a factor of 5, and translate down 23 units.

b. translate left 12 units, stretch horizontally by a factor of 4, and reflect over the x-axis.

need steps don't understand how to do!

Answers

okay, original equation of an absolute value function is:
a. f(x) = a |x-h| + k
a is the stretch or shrink
h is horizontal movement (watch the negative!!)
k is vertical shift

Translate left 9 units means horizontal shift so the h changes. When you move to the left, the numbers become negative so y = a|x-(-9)| + k which becomes
y = a|x+9| + k Then the vertical stretch of 5 becomes y = 5|x+9| + k And then a translation down 23 units means a negative shift down (which is your vertical shift) so:
f(x) = 5(x+9) - 23

b. translate left 12 units meaning a negative horizontal shift. y = a|x-(-12)| + k
so then it becomes y = a|x+12| + k
a stretch horizontally by 4 is your a, so y = 4|x+12| (you can just forget about the k since there is no vertical shift so your k = 0)
a reflection over the x-axis means that your horizontal axis is taken and folded and the reflection from the graph is your new graph. So basically, the whole equation becomes negative.
y = -4|x+12|

Final answer:

For a, the transformed function is 5*|x+9| - 23 after translating 9 units to the left, stretching vertically by a factor of 5, and translating down 23 units. For b, the transformed function is -|(x+12)/4|, after translating 12 units to the left, stretching horizontally by a factor of 4, and reflecting over the x-axis.

Explanation:

The given function is f(x) = |x|. To write the equation for each transformation, you need to understand how they influence the function.

a. To translate the function left 9 units, the value 9 needs to be added inside the absolute value brackets creating f(x) = |x+9|. To stretch it vertically by a factor of 5, we multiply the entire function by 5 - 5 * f(x) = 5*|x+9|. Lastly, to translate down 23 units, we subtract 23 from the entire function, leading us to 5*|x+9| - 23.

b. To translate left 12 units, we change the function to |x+12|. To stretch horizontally by a factor of 4, divide the x inside the absolute value by 4, getting |(x+12)/4|. To reflect over the x-axis, we multiply the entire function by -1, leading to -|(x+12)/4|.

Learn more about Function Transformation here:

brainly.com/question/37849754

Will mark brainliest

Answers

Answer:

the answer would be 270

Step-by-step explanation:

i can explain later:

since x = 5, you plug it in f = 4x +7, and you get f = 27 and since 1/2x is in the denominator, it will flip over and become 2x. 2x is 10, so you multiply f by g and get 270 which is if f/g(5) is the question.

An athletics track has a circular shape and its diameter measures 80 m. An athlete training on this track wants to run 10 km daily. Determine the minimum number of complete turns that it should take this track every day

Answers

Answer:

Step-by-step explanation:

First, we need to find the length of the circular track,

area of circle = $\pi d$

in this case,

$\pi d=80\pi$ meters

10km = 10000 meters

he needs to run $(10000)/(80\pi ) = 392.6\n$ times to complete his goal.

In the coordinate plane, three vertices of rectangle MNOP are M(0, 0), N(0, c), and P(d, 0). What are the coordinates of point O?. a.(d, c). b.(2d, 2c). c.(c/2, d/2). d.(c, d)

Answers

MNOP is a rectangle.
In the coordinate plane, three vertices are: M ( 0, 0 ), N ( 0, c ) and P ( d, 0 ).
The coordinates of point O is:
A ) ( d, c )

Answer:

The coordinates of O is (d,c) .

Option (a) is correct .

Step-by-step explanation:

As given

In the coordinate plane, three vertices of rectangle MNOP are M(0, 0), N(0, c), and P(d, 0).

As MNOP is a rectangle .

Thus opposite sides of the rectangles are equal .

Formula

$Distance\ formula = \sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2) }$

$NM = \sqrt{(0-0)^(2)+(c-0)^(2)}$

$NM = \sqrt{c^(2)}$

NM = c units

$MP = \sqrt{(d-0)^(2)+(0-0)^(2)}$

$MP = \sqrt{d^(2)}$

MP = d units

Thus the coordinate of the O (d,c) .

(This is because opposit sides of the rectangle are equal thus distance of point O from point P must be d and distance of point O from point N must be c .)

Therefore the coordinates of O is (d,c) .

Option (a) is correct .

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