Determine the pressure exerted by 0.352 mol of oxygen gas in a 1.75 L container at room temperature (25 degrees Celsius). Show all your work!​

Answers

Answer 1
Answer:

Answer:

P = 4.92 atm

Explanation:

Given data:

Number of mole of oxygen = 0.352 mol

Volume of gas = 1.75 L

Temperature = 25°C

Pressure exerted by gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

P × 1.75 L = 0.352 mol  × 0.0821 atm.L/ mol.K   ×298 K

P = 8.61 atm.L /  1.75 L

P = 4.92 atm


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B. Distance
C. Displacement
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Answers

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Explanation:

What is the molality of a solution in which 3.0 moles of NaCl is dissolved in 1.5 Kg of water?

Answers

The molality of the sodium chloride solution is 2.0 mol/kg.

Given:

3.0 moles of NaCl in 1.5 kilograms of water.

To find:

The molality of the solution

Solution:

The moles of solute that is sodium chloride = 3.0 mol

The mass of solvent that is water = 1.5 kg

The molality of the solution:

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Learn more about molality here:

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density H2O = 1g/cm³
1,5 kg H2O = 1500g = 1500cm³             (1dm³ = 1000cm³)

3moles of NaCl-----in---------1500cm³ H2O
x moles of NaCl ----in--------1000cm³ H2O
x = 2moles of NaCl

answer: 2 mol/dm³

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Answers

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Answers

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Answers

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Answers

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