MATHEMATICS HIGH SCHOOL

How do I solve this?

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

2•3=6 +2=8 8 squared is 8•8 which is 64. This problem is quite simple.

Answer 2

Answer:

Answer:

X=3

Step-by-step explanation:

Step 1: Find the square root of 64

since there is an exponent of 2 around your paranthesis, you must get rid of that first, by finding the square root of the first part of the equation and 64. then you will have (2x+2)=8

Step 2: Subtract 2

next subtract 2 from both sides of the equation, and you will have 2x=6

Step 3: divide by 2

lastly, divide each side by 2. you will get x=3

Related Questions

Find the product of (4x − 3)(2x2 − 7x + 1).8x3 − 22x2 + 17x− 3

8x3 + 8x2 + 4x − 3

8x3 − 34x2 + 25x − 3

8x3 − 42x2 + 25x − 3

Find the product of 2x4(4x2 + 3x + 1).

8x6 + 6x5 + 2x4

8x8 + 3x4 + 2x4

2x4 + 6x5 + 8x6

6x6 + 5x5 + 3x4

Which statement shows that when two polynomials 4x + 6 and 2x2 − 8x demonstrates the closure property when multiplied?

8x3 − 20x2 − 48x is a polynomial

8x3 − 20x2 + 48x may or may not be a polynomial

8x2 − 32x2 − 14x is a polynomial

8x3 − 32x2 + 14x may or may not be a polynomial

Answers

The correct answers are:

(1) $~8x^3 -34x^2 + 25x -3 ~~$ (Option C)

(2) $~ 8x^(6) + 6x^(5) + 2x^4 ~~$ (Option A)

(3) $~ 8x^3 - 20x^2-48x ~~$ is a polynomial (Option A)

Explanations:

(1) Given Expression:

$(4x-3)(2x^2-7x + 1)$

Now simplify as follows:

$4x(2x^2 - 7x + 1) - 3(2x^2 - 7x + 1) \n8x^3 - 28x^2 + 4x - 6x^2 + 21x - 3 \n8x^3 -34x^2 + 25x -3$

Therefore, the correct answer is $8x^3 -34x^2 + 25x -3$ (Option C)

(2) Given Expression:

$2x^4(4x^2 + 3x + 1)$

Now simplify as follows:

$2x^4(4x^2 + 3x + 1) \n2x^4(4x^2) + 2x^4(3x) + 2x^4(1) \n8x^((4+2)) + 6x^((4+1)) + 2x^4 \n8x^(6) + 6x^(5) + 2x^4$

Therefore, the correct answer is $8x^(6) + 6x^(5) + 2x^4$ (Option A)

(3) Given Data:

Polynomial one: 4x + 6

Polynomial two: $2x^2-8x$

First multiply both polynomials:

$(4x + 6) * (2x^2-8x) \n(4x) * (2x^2-8x) + (6) * (2x^2-8x) \n8x^3-32x^2+12x^2-48x \n8x^3-20x^2-48x$

Now as we can see, if we multiply two polynomials, the resultant expression is also a polynomial. Therefore, it does demonstrate the closure property (closed set). Hence, the correct answer is $8x^3-20x^2-48x ~~$ (Option A)

1. The correct answer among the choices provided is 8x3 − 34x2 + 25x − 3.
2. The correct answer among the choices provided is 8x6 + 6x5 + 2x4.
3. The correct answer among the choices provided is 8x3 − 20x2 − 48x. It is a polynomial.

How many decigrams are in 14 hectograms

Answers

Answer: 14000 decigrams

Step-by-step explanation:

Answer:

14000 decigrams

Step-by-step explanation:

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenths place.

Answers

Answer:

153.1 square unit

Step-by-step explanation:

for rectangle

length = 16

breadth = 8

area of rectangle = l*b

=16*8

=128 square unit

semicircle

diameter =8

area of semicircle =πd^2/8

=3.14 * 8^2 /8

=3.14 *64/8

=200.96/8

=25.12 square unit

area of the givem figure = area of rectangle + area of semicircle

=128 + 25.12

=153.12

=153.1 square unit

Final answer:

To find the area of the figure made up of a rectangle and a semicircle, calculate the areas of both shapes and add them together. Use the formula for the area of a rectangle, and calculate the area of the semicircle by finding half the area of a full circle with the same radius. Finally, sum up the areas to find the total area of the figure.

Explanation:

To find the area of the figure, we need to find the areas of the rectangle and the semicircle, and then add them together. The area of the rectangle is found by multiplying its length by its width. The area of the semicircle is half the area of a full circle with the same radius. Finally, we add the two areas together to get the total area of the figure.

Let's assume the length of the rectangle is 10 units and the width is 5 units. The area of the rectangle is then 10 units * 5 units = 50 units^2. If the radius of the semicircle is 3 units, the area of the semicircle is half the area of a full circle with radius 3 units, which is 1/2 * 3.14 * 3^2 = 14.13 units^2 (rounded to the nearest tenths place).

Therefore, the total area of the figure is 50 units^2 + 14.13 units^2 = 64.13 units^2 (rounded to the nearest tenths place).

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Multiply 8 times the square root of 3 by 9 times the square root of 27.

Answers

8 times the square root of 3 multiplied by 9 times the square root of 27 is equal to 1944.

To multiply 8 times the square root of 3 by 9 times the square root of 27, we can simplify the expression using the properties of square roots and perform the multiplication.

First, let's simplify the square roots:

Square root of 3 can be written as √3.

Square root of 27 can be written as √(9 * 3), which further simplifies to √9 * √3 = 3 * √3.

Now, we have:

8 * √3 * 9 * √27 = 8 * √3 * 9 * (3 * √3) = 8 * 9 * 3 * √3 * √3 = 216 * 3 * √3 * √3.

Since the square root of 3 multiplied by itself (√3 * √3) simplifies to 3, we have:

216 * 3 * 3 = 1944.

Therefore, 8 times the square root of 3 multiplied by 9 times the square root of 27 is equal to 1944.

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8√3 · 9√27
8 · 9 ·√3 · √27
72 · √81
72 · 9
648

The answer is 648. :)

The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms.How long will it take for the population of the bacteria to reach 800?

Round your answer to the nearest tenth of an hour.

Answers

Answer:

16.3h

Step-by-step explanation:

population 2x in 24 h

going from 500 to 800 is less than double so ans is <24h

solving t: 2^(t/24)=800/500

t/24=ln(8/5)/ln2

t=24*ln(8/5)/ln2

=16.3

How many odd numbers greater than 60000 can be formed, using numbers 2,3,4,5 and 6 if each digit is used only once in each number?

Answers

Hello,

All the numbers must begin with 6.

There are still 2,3,4,5 digits : 4 possibilities.

4!=4*3*2*1=24

The first is 62345 and the last 65432.

Final answer:

To find the number of odd numbers greater than 60000 that can be formed using the given numbers with each digit used only once, you can determine the number of possibilities for each digit and multiply them together. The answer is 96.

Explanation:

To find the number of odd numbers greater than 60000 that can be formed using the numbers 2, 3, 4, 5, and 6 with each digit used only once, we need to consider the possible arrangements of these digits. First, we can determine the number of possibilities for the leftmost digit, which must be either 3, 4, 5, or 6. Next, we can determine the number of possibilities for the remaining four digits, which can be arranged in 4! (4 factorial) ways. Multiplying these two values gives us the total number of odd numbers greater than 60000 that can be formed using these digits with each digit used only once.

Thus, the number of odd numbers greater than 60000 that can be formed using the numbers 2, 3, 4, 5, and 6 with each digit used only once is 4 * 4! = 4 * 4 * 3 * 2 * 1 = 96.

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Other Questions

Solve x2 − 3x = −8.x equals quantity of 3 plus or minus I square root of 29 all over 2 x equals quantity of 3 plus or minus I square root of 23 all over 2 x equals quantity of negative 3 plus or minus I square root of 29 all over 2 x equals quantity of negative 3 plus or minus I square root of 23 all over 2

When are triangles considered similar?

Which of the following is a polynomial with roots 3, 5i, and −5i?f(x) = x3 − 3x2 + 25x − 75f(x) = x3 − 3x2 + 15x − 25f(x) = x3 − 15x2 + 25x − 75f(x) = x3 − 3x2 + 15x − 75

The points of a line can be put into one-to-one correspondence with the real numbers so that the distance between any two points is the _____ of the _____ of the corresponding numbers.A. product, absolute valuesB. absolute value, differenceC. difference, valuesD. sum, squares