You want to use a coordinate proof to prove that midsegment DE of ABC is parallel to AC and half the length of AC. Which is the best first step?
Answers
Answer:
the third one answer choice
Step-by-step explanation:
⊕ Place the triangle on a coordinate grid such that vertex A is at the origin, and segment AC lies on the x-axis.
You will be able to see the length of segment AC and length of segment DE, and also will be able to see if AC║DE.
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The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring.What is the constant of the quadratic expression in this equation?x2 + x + ___ = 0
Answers
x= -4 y=16-5=11
x= -2 y=4-5= -1
x= -1 y=1-5= -4
x= 0 y= -5
x= 1 y= 1-5= -4
x= 2 y=4-5= -1
x=3 y=9-5=4
x=4 y=16-5=11
Answers
B. 42 mm3
C. 1176 mm3
D. 196 mm3
Answers
a^3 = 2744 mm^3 ... a = 14 mm
b^3 = 42 mm^3 ... b = 3.48 mm
c^3 = 1176 mm^3 ... c = 10.56 mm
d^3 = 196 mm^3 ... d = 5.81 mm
The correct result would be A. 2744 mm^3.
the correct answer is A.
Trigonometry
Find the value of aBc
Compound shape
Answers
Answer:
∠ ABC = 75°
Step-by-step explanation:
using the sine ratio in right Δ ABD
sin ABD = =
=
=
, then
∠ ABD = (
) = 30°
Using the sine ratio in right Δ CBD
sin CBD = =
=
=
, then
∠ CBD = (
) = 45°
Then
∠ ABC = ∠ABD + ∠ CBD = 30° + 45° = 75°
SOMEONE PLEASE HELP!!
Answers
Remember, one whole circle is 360 degrees. This means that the side that looks to be the same as 43 degrees is 43 degrees. The side that looks the same as (6x+5) should be (6x+5).
Now just set up your equation like this and solve:
43+43+6x+5+6x+5=360
Hope I could be of help! :)
Answers
The number of the boxes can fit in this space if each is 10 cm long, 6 cm wide and 4 cm high will be 125,000.
What is the volume of the rectangular prism?
Let the prism with a length of L, a width of W, and a height of H.
Then the volume of the prism is given as
V = L x W x H
A moving company is trying to store boxes in a storage room with a length of 5 m, width of 3 m and height of 2 m.
Then the volume of the room (in cm) will be
V₁ = 500 x 300 x 200
V₁ = 30,000,000 cubic cm
Then the number of the boxes can fit in this space if each is 10 cm long, 6 cm wide and 4 cm high will be
The volume of each box will be
V₂ = 10 x 6 x 4
V₂ = 240 cubic cm
The number of the boxes can fit in this space if each is 10 cm long, 6 cm wide and 4 cm high will be
V₁ / V₂ = 30,000,000 / 240
V₁ / V₂ = 125,000
More about the volume of the prism link is given below.
#SPJ2
= 30000000 cm³
Volume of 1 box = 10 * 6 * 4
= 240 cm³
Thus, number of boxes in the room
= 30000000/ 240
= 125000 boxes ;
Thus, 125000 boxes can be stored in the room.