If somebody answered my question i will give them thanks and brill and vote
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Answer:
which out of those you want answer for? happy to help
Step-by-step explanation:
Related Questions
A welding drawing shows that the weld-root reinforcement cannot exceed " in thickness. Your weld measurement tools are metric, so this value needs to be converted to millimeters. You know that one inch equals 2.54 centimeters. What is the maximum weld-root reinforcement allowed in millimeters? Round your answer to the nearest tenth of a millimeter.
Don completes the square for the function y = x2 + 6x + 3. Which of the following functions reveals the vertex of the parabola?A. y = (x + 3)2 – 3 B. y = (x + 3)2 – 6 C. y = (x + 2)2 – 6 D. y = (x + 2)2 – 3
Help please whats the answer
Western Company allocates $10 overhead to products based on the number of machine hours used. The company uses a plantwide overhead rate with machine hours as the allocation base. Given the amounts below, how many machine hours does the company expect in department 2?
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I hope this helped!! Brainliest? :) -Raven❤️
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Answer:
the probability that he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)
Step-by-step explanation:
Since the random variable X= length of component chosen at random , is normally distributed, we can define the following standardized normal variable Z:
Z= (X- μ)/σ
where μ= mean of X , σ= standard deviation of X
for a length between 4.98 cm and 5.02 cm , then
Z₁= (X₁- μ)/σ = (4.98 cm - 5 cm)/0.02 cm = -1
Z₂= (X₂- μ)/σ = (5.02 cm - 5 cm)/0.02 cm = 1
therefore the probability that the length is between 4.98 cm and 5.02 cm is
P( 4.98 cm ≤X≤5.02 cm)=P( -1 ≤Z≤ 1) = P(Z≤1) - P(Z≤-1)
from standard normal distribution tables we find that
P( 4.98 cm ≤X≤5.02 cm) = P(Z≤1) - P(Z≤-1) = 0.841 - 0.159 = 0.682 (68.2%)
therefore the probability that he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)
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I hope this helps!
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Explanation: divide 42 by 4 to get that amount of groups (10.5) then multiply that number by 6 so (10.5 • 6) and that should give the apple tree total.
What does the confidence interval suggest about the population means?
A. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
C. The confidence interval includes only positive values which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
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This question is not complete, I got the complete one from google as below:
A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded.
The summary statistics are as follows.
Type A Type B
x1 = 76.3 hrs x2 = 65.1 hrs
s1 = 4.5 hrs s2 = 5.1 hrs
n1 = 11 n2 = 9
The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:
4.90 hrs < μ1 - μ2 < 17.50 hrs
What does the confidence interval suggest about the population means?
A. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
C. The confidence interval includes only positive values which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
Answer:
Option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
Step-by-step explanation:
The 98% confidence interval for the difference in mean drying times of the two types of paints is (4.90, 17.50). This implies that Type A takes between 4.90 and 17.50 hours more to dry than type B paint.
Thus, option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
(hog)(x)
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Step-by-step explanation:
(hog)(x) = h(g(x))
= h(3x + 7)
h(x) = x + 8
h(3x + 7) = 3x + 7 + 8
h(3x + 7) = 3x + 15
(hog)(x) = 3x + 15