What is a decryption key?​

Answers

Answer 1
Answer:

Answer:

A decryption key is a digital information used to recover the plain text from the corresponding ciphertext by decryption.


Related Questions

A constructor (check all that apply): Group of answer choices will always result in a run time error and program crash if it fails to test a parameter's value for validity before assigning the parameter's value to member. This will happen the first time we run a program, and alert us to the fact that there is a problem. must use mutators to initialize class data. must use assignment statements to initialize class data. may use assignment statements to initialize class data. may use mutators to initialize class data. will receive a compiler error if it fails to test a parameter's value for validity before assigning the parameter's value to member.
Consider a demand-paging system in which processes are performing sequential data accesses with the following time-measured utilizations: CPU utilization 20% Paging disk 98% Other I/O devices 10% For each of the following, indicate yes or no to say whether or not it will (or is likely to) improve CPU utilization:a. Install a faster CPU b. Install a bigger paging diskc. Increase the degree of multiprogramming d. Decrease the degree of multiprogramming e. Install more main memory f. Install a faster hard diskg. Increase the page size
What are the 21St century competencies or skills required in the information society?​
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What is the earliest version of the present day Internet?

Answers

Answer:

ARPANET is the earliest version of the present-day Internet.

Explanation:

ARPANET is the type of network that is used before the Internet in the year 1967. It was advanced in the control of U.S ARPA(Advanced Research Projects Agency). After the year of 1980, it was given to the military network for the protection of the data network but after all, it is for the small area network and the Internet is the World Wide network.

Consider the following two code segments, which are both intended to determine the longest of the three strings "pea", "pear", and "pearl" that occur in String str. For example, if str has the value "the pear in the bowl", the code segments should both print "pear" and if str has the value "the pea and the pearl", the code segments should both print "pearl". Assume that str contains at least one instance of "pea".I.

if (str.indexOf("pea") >= 0)

{

System.out.println("pea");

}

else if (str.indexOf("pear") >= 0)

{

System.out.println("pear");

}

else if (str.indexOf("pearl") >= 0)

{

System.out.println("pearl");

}

II.

if (str.indexOf("pearl") >= 0)

{

System.out.println("pearl");

}

else if (str.indexOf("pear") >= 0)

{

System.out.println("pear");

}

else if (str.indexOf("pea") >= 0)

{

System.out.println("pea");

}

Which of the following best describes the output produced by code segment I and code segment II?

Both code segment I and code segment II produce correct output for all values of str.

Neither code segment I nor code segment II produce correct output for all values of str.

Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pear" but not "pearl".

Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pearl".

Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".

Answers

Answer:

Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".

Explanation:

The main issue with the first code segment is the way how the if else if condition are arranged. The "pea" is checked at the earliest time in the first code segment and therefore so long as there is the "pea" exist in the string (regardless there is pear or pearl exist in the string as well), the if condition will become true and display "pea" to terminal. This is the reason why the code segment 1 only work for the values of str that contain "pea".

Create a Produceclass that hasan instance variable of type Stringfor the name, appropriate constructors, appropriate accessor and mutator methods, and a public toString() method. Then create a Fruitand a Vegetableclass that are derived from Produce. These classes should have constructors that take the nameas a Stringand invoke the appropriate constructor from the base class to set the name.Also, they should override toStringmethod to display the nameof the produce and its type. For instance, Mangois a Fruitand Caulifloweris a Vegetable. Finally, create a class called TruckOfProducethat will keep track of the boxes of Vegetablesand Fruitsadded in to the truck. This class should use an array of Produceto store both Vegetableand Fruitobjects.

Answers

Answer:

you suck

Explanation:

What do you think is the single greatest physical threat to information systems? Fire? Hurricanes? Sabotage? Terrorism? Something else? Discuss this question and provide support for your answer.

Answers

Answer:

The single greatest physical threat to information systems is:

Sabotage

Explanation:

Sabotage describes the efforts of internal persons to ensure that a system does not operate as intended or is destroyed.  Among the threats to information systems, this is the greatest.  The problem with sabotage is that the operators are internal, they know the system very well.  They understand the weak points and the strengths of the system.  They are internal terrorists to any information system.  These internal saboteurs are capable of using any means to achieve their purpose.  Therefore, it is necessary to scrutinize employees from time to time to discover internal risks.

Residential and business customers are paying different rates for water usage. Residential customers pay $0.005 per gallon for the first 6000 gallons. If the usage is more than 6000 gallons, the rate will be $0.007 per gallon after the first 6000 gallons. Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0.008 per gallon after the first 8000 gallons. For example, a residential customer who has used 9000 gallons will pay $30 for the first 6000 gallons ($0.005 * 6000), plus $21 for the other 3000 gallons ($0.007 * 3000). The total bill will be $51. A business customer who has used 9000 gallons will pay $48 for the first 8000 gallons ($0.006 * 8000), plus $8 for the other 1000 gallons ($0.008 * 1000). The total bill will be $56. Write a program to do the following. Ask the user which type the customer it is and how many gallons of water have been used. Calculate and display the bill.

Answers

Answer:

// here is program in Java.

// import package

import java.util.*;

// class definition

class Main

{

   // main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

   // variable

   int gall;

   double cost=0;

       // object to read value from user

    Scanner scr=new Scanner(System.in);

     // ask user to enter type

    System.out.print("Enter customer type  (R for residential or B for business ):");

    // read type of customer

       char t=scr.next().charAt(0);

       if(t=='r'||t=='R')

       {

           System.out.print("enter the number of gallons:");

           //read number of gallons

           gall=scr.nextInt();

           // if number of gallons are less or equal to 6000

           if(gall<=6000)

            {

           // calculate cost

           cost=gall*0.007;

           // print cost

           System.out.println("total cost is: "+cost);

             }

           else

           {

           // calculate cost

            cost=(6000*0.005)+((gall-6000)*0.007);

            // print cost

            System.out.println("total cost is: "+cost);

           }

       }

       else if(t=='b'||t=='B')

       {

           System.out.print("enter the number of gallons:");

           //read number of gallons

           gall=scr.nextInt();

           // if number of gallons are less or equal to 8000

           if(gall<=8000)

            {

           // calculate cost

           cost=gall*0.006;

           // print cost

           System.out.println("total cost is: "+cost);

             }

           else

           {// calculate cost

            cost=(8000*0.006)+((gall-8000)*0.008);

            // print cost

            System.out.println("total cost is: "+cost);

           }

       }

   }catch(Exception ex){

       return;}

}

}

Explanation:

Ask user to enter the type of customer and assign it to variable "t" with scanner object.If the customer type is business then read the number of gallons from user and assign it to variable "gall". Then calculate cost of gallons, if   gallons are less or equal to 8000 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and   for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 6000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter customer type  (R for residential or B for business ):r

enter the number of gallons:8000

total cost is: 44.0

If you need speeds of 16 Mbps between two corporate sites in the United States, you would need a ________ leased line. T1 T3 OC3 None of these

Answers

Answer:

T3.

Explanation:

A T3 is an acronym for Transmission system 3 and it is also known as Digital Signal Level 3 (DS3). T3 is a point-to-point physical circuit connection which is capable of transmitting up to 44.736Mbps.

This simply means that, when using a Transmission system 3 (T3), it is very much possible or easier to transmit data such as video and audio at the rate of 44.736Mbps.

Please note, Mbps represents megabit per seconds and it is a unit for the measurement of data transmission rate. The Transmission system 3 is an internet connection that has up to 672 circuit channels having 64Kbs.

Also, worthy of note is the fact that a T3 line is made up of twenty-eight (28) Transmission system 1 lines (T1) each having a data transfer rate of 1.544Mbps.

Additionally, Transmission 3 lines are symmetrical and duplex and thus, has equal upload and download speeds. Therefore, transmissions can be done on T3 lines simultaneously without the data lines being clogged or jammed.

If you need speeds of 16 Mbps between two corporate sites in the United States, you would need a T3 leased line.

Generally, the T3 lines are mostly used for multichannel applications and uninterrupted high bandwidth consumptions such as Telemedicine, internet telephony, video conferencing, e-commerce etc.