MATHEMATICS COLLEGE

13. Find the slope of any PLZ HELP!!!! 13. Find the slope of any line parallel to the line passing through (1,5) and (-1,0).a. 5/2
b. 2/5
c. -5/2
d. -5/2

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

5- 0 = 5

1- -1 = 2

5/2

Answer 2

Answer: The answer might be B. I’m not entirely sure.

x = - 2/5

Step-by-step explanation:

$3(x+2)=2(2-x)\n\n\mathrm{Expand\:}3\left(x+2\right):\quad 3x+6\n\n\mathrm{Expand\:}2\left(2-x\right):\quad 4-2x\n\n3x+6=4-2x\n\n\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\n\n3x+6-6=4-2x-6\n\n3x=-2x-2\n\n\mathrm{Add\:}2x\mathrm{\:to\:both\:sides}\n\n3x+2x=-2x-2+2x\n\nSimplify\n\n5x=-2\n\nDivide\:both\:sides\:by5\n\n(5x)/(5)=(-2)/(5)\n\nx=-(2)/(5)$

Which statement best describes the relationship between the graphs of the two linear equations below?3
y=-2 +4
2
3x - 2y = -8
The lines are
parallel
5
The lines intersect
and are
perpendicular
The lines intersect
and are not
perpendicular
The lines are the
same

Answers

Answer:

Step-by-step explanation:

According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest. A random sample of 154 executive officers from these companies was selected. What is the probability that more than 20% of this sample is comprised of female employees?

Answers

Using the normal probability distribution and the central limit theorem, it is found that there is a 0.0869 = 8.69% probability that more than 20% of this sample is comprised of female employees.

Normal Probability Distribution

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{(p(1 - p))/(n)}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .

In this problem:

16% of executive officers were women with companies that have company headquarters in the Midwest, hence p = 0.16.

A random sample of 154 executive officers from these companies was selected, hence n = 154.

The mean and the standard error are given by:

$\mu = p = 0.16$

$s = \sqrt{(p(1 - p))/(n)} = \sqrt{(0.16(0.84))/(154)} = 0.0295$

The probability that more than 20% of this sample is comprised of female employees is 1 subtracted by the p-value of Z when X = 0.2, hence:

$Z = (X - \mu)/(\sigma)$

By the Central Limit Theorem

$Z = (X - \mu)/(s)$

$Z = (0.2 - 0.16)/(0.0295)$

$Z = 1.36$

$Z = 1.36$ has a p-value of 0.9131.

1 - 0.9131 = 0.0869.

0.0869 = 8.69% probability that more than 20% of this sample is comprised of female employees.

To learn more about the normal probability distribution and the central limit theorem, you can take a look at brainly.com/question/24663213

Answer: 0.0885

Step-by-step explanation:

Given : According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest.

i.e. p= 0.16

Sample size : n= 154

Now, the probability that more than 20% of this sample is comprised of female employees is given by :-

$P(p>0.20)=P(z>\frac{0.20-0.16}{\sqrt{(0.16(1-0.16))/(154)}})$

[∵ $z=\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}$ ]

$=P(z>1.35)\approx1-P(z\leq1.35)=1-0.9115=0.0885$ [Using the standard z-value table]

Hence, the required probability = 0.0885

Find the parametric and symmetric equations for the line passing through the points P1=(2,2,3) and P2=(1,3,−1) . NOTE: this problem does not have a unique answer unless we specify how to choose the direction vector v (see pages 610 and 611). In order to obtain the required solution for this problem use the vector v=P1−P2 (see page 585). Further, you need to use the given point P1 in the formula. PARAMETRIC: x(t)= y(t)= z(t)= SYMMETRIC: (quotient involving x ) = (quotient involving y) = (quotient involving z ) =

Answers

Answer:

parametric equation: q = (2-t)x + (2+t)y + (3-4t)z

symm equation: $(x-2)/(-1) = (y-2)/(1) = (z-3)/(-4)$

Step-by-step explanation:

Parametric equation is just like the point slope equation:

y= b + mx

but in this case we have multiple variable so it'll be

q= p₀ + dt

p₀ will be any of your point. d will be the vector containing points shared by both your vector. It can be found by subtracting your two points together.

t is just an arbitrary variable.

Solve for d=p₂ - p₁ , you can also do d=p₁ - p₂

Now plug it into your q= p₀ + dt equation.

You can plug p₂ or p₁ in for p₀. I used p₁.

The result should give you the parametric equation.

Now solve for all of them in term of t. This step is just basic algebra.

since they're all t=..., then you can set them all equal to each other to get the symmetric equation.

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Hey can you please help me posted picture of question