Answers
Answer:
Partial pressure of neon = 175 mmHg
Partial pressure of xenon = 564 mmHg
Explanation:
The partial pressure of a gas in a mixture can be calculated as the product of the mole fraction of the gas (Xi) and the total pressure (Pt), as follows:
Pi = Xi Pt
The total pressure is 739 mmHg ⇒ Pt = 739 mmHg
In order to calculate the mole fraction of each gas, we have to first calculate the number of moles of each gas (n) by dividing the mass of the gas into the molar mass (MM):
For neon gas (Ne):
MM(Ne) = 20.18 g/mol
n(Ne)= mass/MM = 0.919 g x 1 mol/20.18 g = 0.045 mol Ne
For xenon gas (Xe):
MM(Xe) = 131.3 g/mol
n(Xe)= mass/MM = 19.1 g x 1 mol/131.3 g = 0.145 mol Xe
Now, we calculate the mole fraction (X) by dividing the number of moles of the gas into the total number of moles (nt):
nt= moles Ne + moles Xe = 0.045 mol + 0.145 mol = 0.190 mol
X(Ne) = moles Ne/nt = 0.045 mol/0.190 mol = 0.237
X(Xe) = moles Xe/nt = 0.145/0.190 mol = 0.763
Finally, we calculate the partial pressures of Ne and Xe as follows:
P(Ne) = X(Ne) x Pt = 0.237 x 739 mmHg = 175 mmHg
P(Xe) = X(Xe) x Pt = 0.763 x 739 mmHg = 564 mmHg
Related Questions
Two containers, one with a volume of 3.0 L and the other with a volume of 2.0 L contain, respectively, argon gas at 1.1 atm and helium at 0.75 atm. The containers are initially separated by a valve, and then the valve is opened to connect the two containers. Assume perfect gases and determine the followings.a. The total pressure of the mixed gasesb. The partial pressure of each gasc. The mole fraction of each gas
The higher the pH, the less acidic the solution
Calculate the pH of a buffer solution made by adding 15.0 g anhydrous sodium acetate (NaC2H3O2) to 100.0 mL of 0.200 M acetic acid. Assume there is no change in volume on adding the salt to the acid. (pKa for acetic acid is 4.74 or Ka is 1.8 x 10-5)3.
This section of the periodic table is called a(n)
Answers
Answer:
Molar concentration of Fe(NO3)3 . 9H2O = 0.12M
Explanation:
Fe(NO3).9H2O --> Fe(NO3)3 + 9H2O
By stoichiometry,
1 mole of Fe(NO3)3 will be absorb water to form 1 mole of Fe(NO3)3 . 9H2O
Therefore, calculating the mass concentration of Fe(NO3)3;
Molar mass of Fe(NO3)3 = 56 + 3*(14 + (16*3))
= 242 g/mol
Mass concentration of Fe(NO3)3 = molar mass * molar concentration
= 242 * 0.2
= 48.4 g/L
Molar mass of Fe(NO3)3 . 9H2O = 56 + 3*(14 + (16*3)) + 9* ((1*2) + 16)
= 242 + 162 g/mol
= 404g/mol
Concentration of Fe(NO3)3 . 9H2O = mass concentration/molar mass
= 48.4 /404
= 0.12 mol/l
Molar concentration of Fe(NO3)3 . 9H2O = 0.12M
C in CH4 :
H in CH4 :
O in O2 :
C in CO2 :
O in CO2 :
H in H2O :
O in H2O :
Which atom is reduced?
Which atom is oxidized?
Answers
The oxidation numbers of the atoms of the specified elements in each of the given atoms are;
1) -4
1) -42) +1
1) -42) +13) 0
1) -42) +13) 04) +4
1) -42) +13) 04) +45) -2
1) -42) +13) 04) +45) -26) +1
1) -42) +13) 04) +45) -26) +17) -2
1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = C
1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = CAtom reduced = O
1) C in CH4
To get the oxidation number of C;
Oxidation state of hydrogen atom is +1 and so if the oxidation state of C is x, then we have;
x + 4(+1) = 0
x + 4 = 0
x = -4
2) H in CH4
Oxidation state on Carbon atom in this case is -4. Thus;
-4 + 4x = 0
4x = 4
x = +1
3) O in O2
This is oxygen gas that exists in it's free state and as such oxidation number is 0.
4) C in CO2
Oxidation state of O here is -2. Thus;
x + 2(-2) = 0
x - 4 = 0
x = +4
5) O in CO2
Oxidation state of C is +4 here. Thus;
4 + 2x = 0
2x = -4
x = -4/2
x = -2
6) H in H2O
Oxidation state of oxygen here is -2. Thus;
2x - 2 = 0
2x = 2
x = 2/2
x = +1
7) O in H2O
Oxidation state of hydrogen here is +1. Thus;
2(1) + x = 0
x = -2
Finally, oxidation number of carbon increased, then it is the atom that was oxidized while the atom reduced is the Oxygen atom.
Read more at; brainly.com/question/22816291
Answer:
1. -4
2. +1
3. 0
4. +4
5. -2
6. +1
7. -2
reduced = H
oxidized = O
Explanation:
Know oxidation rules.
- Hope this helped! Please let me know if you would like to learn this. I could show you the rules and help you work through them.
Answers
Answer: The limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.
Explanation:
To calculate the number of moles, we use the equation:
.....(1)
- For magnesium:
Given mass of magnesium = 41.0 g
Molar mass of magnesium = 24 g/mol
Putting values in equation 1, we get:
- For iron(III) chloride:
Given mass of iron(III) chloride = 175.0 g
Molar mass of iron(III) chloride = 162.2 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of magnesium and iron(III) chloride follows:
By Stoichiometry of the reaction:
3 moles of magnesium reacts with 2 moles of iron(III) chloride
So, 1.708 moles of magnesium will react with = of iron(III) chloride
As, given amount of iron(III) chloride is more than the required amount. So, it is considered as an excess reagent.
Thus, magnesium is considered as a limiting reagent because it limits the formation of product.
Moles of excess reactant left (iron(III) chloride) = [1.708 - 1.114] = 0.594 moles
Now, calculating the mass of iron(III) chloride from equation 1, we get:
Molar mass of iron(III) chloride = 162.2 g/mol
Moles of iron(III) chloride = 0.594 moles
Putting values in equation 1, we get:
Hence, the limiting reactant is magnesium and mass of excess reactant present in the vessel is 96.35 grams.
The answer I got was False, is this correct?
Answers
Answer: yes it is false
Explanation:
The statement is false. A synthetic process with a lower E-factor produces less waste than a process with a higher E-factor.
The E-factor is a measure of the waste generated during a manufacturing process. It is calculated by dividing the total mass of waste produced by the mass of the desired product. A lower E-factor indicates that less waste is generated per unit of product.
In this case, the synthetic process with an E-factor of 3.0 produces less waste than the process with an E-factor of 17.4. This means that the process with an E-factor of 3.0 is more efficient in terms of waste reduction.
Answers
Answer:
(a) The rate constant is 3.61×10^-3 s^-1
(b) 7.12×10^4 s
Explanation:
(a) Log (K2/K1) = Ea/2.303R × [1/T1 - 1/T2]
K1 = 8.33×10^-6 s^-1
Ea = 245 kJ = 245,000 J
R = 8.314 J/mol.K
T1 = 427°C = 427+273 = 700 K
T2 = 545°C = 546+273 = 818 K
Log (K2/8.33×10^-6) = 245,000/2.303 × [1/700 - 1/818]
Log (K2/8.33×10^-6) = 2.637
K2/8.33×10^-6 = 10^2.637
K2 = 8.33×10^-6 × 433.51 = 3.61×10^-3 s^-1
(b) The relationship between temperature and the time required for reactants to be consumed is inverse
t2 = T1t1/T2
T1 = 427 °C = 700 K
t1 = 8.32×10^4 s
T2 = 545 °C = 818 K
t2 = 700×8.32×10^4/818 = 7.12×10^4 s
Answers
Due to property of conduction, conductor allows electrons and electric current to move easily,insulators prevent electric current from moving, electric current is the flow of an electrical charge in a circuit and electric circuit provides a path for electrons to flow.
What is conduction?
Conduction is defined as a process as a means of which heat is transferred from the hotter end of the body to it's cooler end.Heat flows spontaneously from a body which is hot to a body which is cold.
In the process of conduction,heat flow is within the body and through itself.In solids the conduction of heat is due to the vibrations and collisions of molecules while in liquids and gases it is due to the random motion of the molecules .
When conduction takes place, heat is usually transferred from one molecule to another as they are in direct contact with each other.There are 2 types of conduction:1) steady state conduction 2) transient conduction.According to the type of energy conduction is of three types:
1) heat conduction
2) electrical conduction
3)sound conduction
Learn more about conduction,here:
#SPJ5
Answer:
1st box:4
2nd box:2
3rd box:3
4th box:1
Explanation:
I am not 100% sure on this, but i am pretty confident that this is the answer! BUT If this is somehow wrong, please tell me so i can comment a better answer! :)