Answer:
B (Quantitative)
Explanation:
a clever way to remember the difference between quantitative and qualitative is that there is a nin quantitative which is the first letter to the word number.So quantitative is an oberservation with numbers
Answer:
0.0192 mL per min.
Explanation:
IV rate = 36 mg per 30 min.
IV concentration = 125 mg per 2.0 mL
36 mg per 30 min. IV rate = 36/30 = 1.2 mg per min
If 125 mg methylprednisolone is present in 2.0 mL of the IV nag, how many mL would contain 1.2 mg?
= 2x1.2/125
= 0.0192 mL
Therefore, the flow rate of the IV must be 0.0192 mL per min. in order to be able to deliver 36 mg per 30 min.
Answer:
0.278 mol
Explanation:
Step 1: Given and required data
Mass of acetic acid (m): 16.7 g
Chemical formula of acetic acid: CH₃COOH (C₂H₄O₂)
Step 2: Calculate the molar mass (M) of acetic acid
We will use the following expression.
M(C₂H₄O₂) = 2 × M(C) + 4 × M(H) + 2 × M(O)
M(C₂H₄O₂) = 2 × 12.01 g/mol + 4 × 1.01 g/mol + 2 × 16.00 g/mol = 60.06 g/mol
Step 3: Calculate the number of moles (n) of acetic acid
We will use the following expression.
n = m/M
n = 16.7 g/(60.06 g/mol) = 0.278 mol
Answer:
precipitate
Explanation:
Precipitation is the creation of a solid from a solution. When the reaction occurs in a liquid solution, the solid formed is called the 'precipitate'. The chemical that causes the solid to form is called the 'precipitant'.
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Answer:
Explanation:
# moles that exist in 1.9 X 10 23 =
= # of atoms/# of Avogadro 's num
= 1.9 X 10 23 / 6.02x10 23
= 0.266 mole of Pb
now we calculate the mass
mass of lead = # mol x m.wt
= 0.266 X 106.4
= 28.30 gram
Answer:
Explanation:
This question seeks to test the knowledge of Avogadro's law. Avogadro's law states that equal volume of gases, at constant temperature and pressure, contain the same number of molecules. The meaning here is that the volume of a given mass of (ideal) gas is directly proportional to the number of molecules. Thus, an increase in volume of an ideal gas will lead to an increase in the number of molecules of the gas. Also, an increase in the number of molecules of an ideal gas will lead to an increase in the volume of the gas at constant temperature and pressure.
The mass of air in room as per given density is 53.2 kg.
To calculate the mass of air contained in a room, we can use the formula:
mass = density x volume
Here, the given density of air is 1.29 g/dm³ at 25°C. We can convert the dimensions of the room to decimeters (dm) by multiplying by 10:
Length = 2.50 m × 10 = 25 dm
Width = 5.50 m × 10 = 55 dm
Height = 3.00 m × 10 = 30 dm
Now, we can calculate the volume of the room by multiplying the three dimensions:
Volume = length x width x height
Volume = 25 dm x 55 dm x 30 dm
Volume = 41,250 dm³
Finally, we can use the formula to calculate the mass of air:
mass = density x volume
mass = 1.29 g/dm³ x 41,250 dm³
mass = 53,212.5 g or 53.2 kg
Therefore, the mass of air contained in the room is approximately 53.2 kg.
Learn more about density,here:
#SPJ3
Explanation:
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