Zoe and Josiah are both selling cookie dough for a fundraiser. Although Zoe has already sold 12 tubs, Josiah hasn't sold any yet. If Zoe starts selling 2 tubs per day and Josiah begins selling 4 tubs per day, they will eventually sell the same amount of cookie dough.

Answers

Answer 1
Answer:

Answer:

6 days

Step-by-step explanation:

Given

Zoe

Sold out = 12

Rate = 2 daily

Josiah

Sold out = 0

Rate = 4 daily

Required

Determine when they sell the same number of tubs

Represent days with d

The number of tubs sold in any give day can be calculated using:

Tubs = Sold out + Rate * Number of days

For Zoe:

Expression: 12 + 2 * d

Expression: 12 + 2d

For Josiah

Expression: 0 + 4 * d

Expression: 4 * d

Expression: 4d

Next, we equate both expressions to get the number of days

4d = 12 + 2d

Collect like terms

4d - 2d = 12

2d = 12

Solve for d

d = 12/2

d = 6

Hence, it'll take 6 days


Related Questions

PLEASE help me:( i'm desperate (and dumb):factor 2n^(3)+7n^(2)-2n-7
Xander is taking a 5 question quiz worth 100 points. Each question is worth 20 points. Write an equation in function notation that represents his score for x number of questions answered correctly.
Jack spends 1 and a quarter as long on his homework as Jill. Last week Jill spent 9 and three quarters of a hour on his homework. How long did Jack take??? Write the answer as a mixed number! Thnx!
How do I figure out expressions for example -4×4×4×4×4×4×4×4?​
A zoo keeper wants to fence a rectangular habitat for goats. The length of the habitat should be at least 80 feet, and the perimeter of the habitat should be no more than 300 feet. a. Write and graph a system of linear inequalities b. Write two possible solutions:

Please solve this equation

Answers

The answer is A. 125

Answer:

125

Step-by-step explanation:

Which sum is equal to x^2+6x-5/x^2-25

Answers

Answer: The sum will be given as

1+(6x+20)/(x^2-25)

Step-by-step explanation:

Since we have given that

(x^2+6x-5)/(x^2-25)

We just need to simplify and get the sum :

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^2+6x-5\mathrm{\:and\:the\:divisor\:}x^2-25\mathrm{\::\:}(x^2)/(x^2)=1\n\n\mathrm{Quotient}=1\n\n\mathrm{Multiply\:}x^2-25\mathrm{\:by\:}1:\:x^2-25\n\n\mathrm{Subtract\:}x^2-25\mathrm{\:from\:}x^2+6x-5\mathrm{\:to\:get\:new\:remainder}\n\n\mathrm{Remainder}=6x+20\n\n(x^2+6x-5)/(x^2-25)=1+(6x+20)/(x^2-25)

Hence, the sum will be given as

1+(6x+20)/(x^2-25)

1/x+5 + x/x-5  i think so

Solve each system using substitution.
3x+2y=23
1/2x-4=y

Answers

\left\{\begin{array}{ccc}3x+2y=23&(1)\ny=(1)/(2)x-4&(2)\end{array}\right\n\nsubtitute\ (2)\ to\ (1)\n\n3x+2((1)/(2)x-4)=23\n3x+x-8=23\n4x-8=23\ \ \ \ |add\ 8\ to\ both\ sides\n4x=31\ \ \ \ \ |divide\ both\ sides\ by\ 4\n\boxed{x=7.75}\n\nsubtitute\ the\ value\ of\
1: 3x+2y=23
2: 1/2x-4=y
We have that y=1/2x-4 in 2
So lets substitu y in 1
3x+2(1/2x-4)=23
3x+x-8=23
4x=23+8
4x=31
X = 7,75
Now lets replace x in 2:
1/2.7,75-4=y
3,875-4 + y
Y= - 0,125
So (x;y)=(7,75;-0.125)

How is table helpful when constructing equations?

Answers

Answer:

The numbers in a table are often the x and y values that are true for the line, which means the x and y values correspond to the coordinates of points on the line.

Given that a line equation is y=m x+b, the x and y values are numbers that can be used to arrive at the unknowns, such as the slope(m) and the y-intercept(b).

with the help of two points/coordinates we could find the slope of a line and the 3rd coordinate could be used to find the y-intercept.


Find the quotient.(6x 2 + 23x + 20) ÷ (5 + 2x)

3x - 4
3x + 4
3x +19

Answers

(6x^(2) + 23x + 20)/(2x + 5) = (6x^(2) + 15x + 8x + 20)/(2x + 5) = (3x(2x) + 3x(5) + 4(2x) + 4(5))/(2x + 5) = (3x(2x + 5) + 4(2x + 5))/(2x + 5) = ((3x + 4)(2x + 5))/(2x + 5) = 3x + 4

The answer is B.

Answer:

3x+4

Step-by-step explanation:

1. Use words to write this expression:
9 + 7x

Answers

Answer:

nine added to seven times a number.

Step-by-step explanation:

''x'' is the unknown number which is being multiplied by 7. Than 9 is added to it.