Answer: 600 m
Step-by-step explanation:
Imagine we have measured a distance as 1.5 cm on this map, and we want to find out how far this is in real life.
To work out the distance in real life, we need to multiply this length by 40,000.
This gives 1.5 cm × 40,000 = 60,000 cm which is 600 m or 0.6 km.
Sol b : Alternatively, we could have just remembered that each 1 cm on the map is 0.4 km in real life.
Hence, 1.5 cm on the map must be 1.5 × 0.4 km = 0.6 km in real life.
Answer:
X × $75000 = $75000
Step-by-step explanation:
Brainliest would be appreciated
a. If the sample variance is s^2=32 , are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha=.05
b. If the sample variance is s^2=72 , are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha=.05 ?
c. Comparing your answer for parts a and b, how does the variability of the scores in the sample influence the outcome of a hypothesis test?
A hypothesis test was conducted to evaluate the treatment's effect. For both variances, we failed to reject the null hypothesis, so we can't conclude that the treatment had a significant effect. The variability of scores plays a crucial role, as more variability makes it harder to identify a significant effect.
To determine if the treatment has a significant effect, we perform a hypothesis test using the sample mean (M), sample variance (s^2), and population mean (μ). The null hypothesis is that there's no effect from the treatment (μ=M), while the alternative hypothesis is that there is an effect (μ≠M).
a. For sample variance s^2=32, we can use the formula for the t score: t = (M - μ)/(s/√n) = (35 - 40)/(√32/√8) = -2.24. Based on a two-tailed t-distribution table, the critical t values for α=.05 and 7 degrees of freedom (n-1) are approximately -2.365 and 2.365. Our t value (-2.24) lies within this range, so we fail to reject the null hypothesis. We cannot conclude that the treatment has a significant effect.
b. Repeat the same process with sample variance s^2=72. The t value is now (35 - 40)/(√72/√8) = -1.48, again falling within the range of the critical t values. We can't conclude that the treatment has a significant effect.
c. As the variability (s^2) of the sample scores increases, it becomes more difficult to find a significant effect. Higher variability introduces more uncertainty, which can mask actual changes caused by the treatment.
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To evaluate the effect of a treatment using a two-tailed test with alpha = 0.05, we compare the calculated t-value to the critical t-value. The sample variance influences the outcome of the hypothesis test, with a larger variance leading to a wider critical region.
a. To test if the treatment has a significant effect, we will conduct a two-tailed hypothesis test using the t-distribution. The null hypothesis states that the treatment has no effect (μ = 40), while the alternative hypothesis states that the treatment has an effect (μ ≠ 40). With a sample size of 8, degrees of freedom (df) will be n-1 = 7. We will use the t-test formula to calculate the t-value, and compare it to the critical t-value from the t-table with α = 0.05/2 = 0.025. If the calculated t-value falls outside the critical region, we reject the null hypothesis and conclude that the treatment has a significant effect.
b. Similar to part a, we will conduct a two-tailed t-test using the same null and alternative hypotheses. With a sample size of 8, df = n-1 = 7. We will calculate the t-value using the sample mean, population mean, and sample variance. Comparing the calculated t-value to the critical t-value with α = 0.05/2 = 0.025, if the calculated t-value falls outside the critical region, we reject the null hypothesis and conclude that the treatment has a significant effect.
c. The variability of the scores in the sample, as indicated by the sample variance, influences the outcome of the hypothesis test. In both parts a and b, the sample variance is given. A larger sample variance (s^2 = 72 in part b) indicates more variability in the data, meaning the scores in the sample are more spread out. This leads to a larger t-value and a wider critical region. Therefore, it becomes easier to reject the null hypothesis and conclude that the treatment has a significant effect.
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The height of the water when poured into the empty wide cylinder is;
Option A; To the 7¹/₃ mark
Formula for volume of a cylinder is;
V = πr²h
where;
r is radius
h is height
We are told that water is poured into the wide cylinder up to the 4th mark. Thus, for the wide cylinder, h = 4. Thus;
V_wide = 4πR²
Similarly, we are told that water is poured into the narrow cylinder up to the 6th mark. Thus, for the narrow cylinder, h = 6. Thus;
V_narrow = 6πr²
Now, the volume of the water will be the same since it was the same quantity that was poured. Thus;
V_wide = V_narrow
4πR² = 6πr²
⇒ R²/r² = 6/4
simplifies to get; R²/r² = ³/₂
Now both cylinder were emptied and water poured rises to the 11th mark for the narrow cylinder. Thus;
πR²H = 11πr²
R²/r² = 11/H
Earlier, we saw that R²/r² = ³/₂. Thus;
11/H = ³/₂
H = 22/3
H = 7¹/₃
The complete question is;
Attached are the drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?
A) To the 7¹/₃ mark
B)To the 8th mark
C) To the 7¹/₂mark
D)To the 9th mark
E) To the 11th mark
Read more at; brainly.com/question/16760517
Answer:
COMPLETE QUESTION:
To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?
a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark
e)To the 11th mark
ANSWER : Option D (To the 7 1/3 mark)
Step-by-step explanation:
First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e
Volume of cylinders
π x R² x 4 = πxr²x 6
R²/r² = 6/4
after both cylinder were emptied
π x R² x h = π x r² x 11
R²/r² = 6/4 = 11/h
h = (4 x 11) /6 = 22/3 = 7 1/3 mark
Therefore, the height of the water in the wide cylinder is 7 1/3
Part A Write an expression with two terms for the number of baskets that Kari makes. Explain how you found your expression.
Part B Write an expression with three terms for the number of baskets that Kari and Julie make in all. Explain how you found your expression.
Answer:
X= 2y - 3
Kari makes X tryouts. She also makes 3 less than twice as many as Julie which would be X= 2y - 3
Julie makes y tryouts and twice would be 2y.
Step-by-step explanation: hope this helps!!! :)
Answer:
X= 2y - 3
Kari makes X tryouts. She also makes 3 less than twice as many as Julie which would be X= 2y - 3
Julie makes y tryouts and twice would be 2y.
Step-by-step explanation:
would you get from £1
if you spent 77p?
You would get 23p as change from £1 if you spent 77p.
To find how much change you would get from £1 if you spent 77p, you need to subtract the amount you spent from the total amount you have.
Total amount = £1
Amount spent = 77p
To find the change, we need to convert both amounts to the same unit (pence) before performing the subtraction.
1 pound (£1) is equal to 100 pence, so:
Total amount = 100p
Amount spent = 77p
Now, subtract the amount spent from the total amount to find the change:
Change = Total amount - Amount spent
Change = 100p - 77p
Change = 23p
So, you would get 23p as change from £1 if you spent 77p.
To know more about change:
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$150 table; 40% discount
Answer:
$60
Step-by-step explanation:
40% of 150=60
40 × 150= $60
100 1