A sport car moving at constant speed travels 110m in 5.0 s. if it then brakes and comes to a stop in 4.0 s, what is the magnitude of its acceleration in m/s2, and in g’s (g=9.80 m/s2)? 2

Answers

Answer 1

Answer: d = 110 m, t = 5 s
v o = 110 cs : 5 m = 22 m/s
-------------------------------------
v = v o - a t
v = 0 m/s, v o = 22 m/s, t = 4 s
0 = 22 - 4 a
4 a = 22
a = 22 : 4
a = 5.5 m/s²
g = 9.80 m/s²
9.80 : 5.5 = 0.56
Answer:
The magnitude of its acceleration is 5.5 m/s or 0.56 g.

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If 2.0 x 10^-4 C charge passes a point in 5.0 x 10^-5 s, what is the rate of current flow?4.0 x 10^-1 A
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Answers

Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:

I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
I = 4 A or 4.0 x 10^0 A

Answer:

Explanation:

Resolve the following two forces into horizontal and vertical components.

Answers

All components of both forces have zero magnitudes.

A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the value of work being done on the object?

Answers

The total work done is 957.56 joules. This is calculated as work is equal to 25N time 50 meters time cosine 40 degrees.

Answer:

Work being done on the object = 766.04J

Explanation:

Work done by a force is calculated by finding dot product of force and displacement.

W = F . s

F = 25 N

s = 50 m

θ = 40.0°

W = F . s = Fs cosθ = 25 x 40 x cos 40 = 766.04J

Work being done on the object = 766.04J

Four wire AB,BC,CD and DA each resistance 4 ohm and a fifth wire BD of resistance 8 ohm are joined to form a rectangle to which BD is a diagonal.The effective resistance between the points A and B is?

Answers

Since it's so late, and it's way past my bedtime, and I'm tired and hungry,
and I still have real work to do, and I don't think you're really a legitimate
asker of Brainly questions anyway, I'm going to do something that's against
my principles and I almost never do. I'm going to violate my own personal
Prime Directive, and give you the answer without any explanation of where
it comes from.

Ready ?

Here goes:

The effective resistance between points 'A' and 'B' is (2 and 2/3) Ω .

FASTA ball has 116.62 J of gravitational potential energy at a height of 85 m. What is the mass of the ball?

a.0.14 kg
b.0.37 kg
c.11.9 kg
d.21.82 kg

Answers

Answer:

a)0,14 kg

Explanation:

Formula to calculate the gravitational potential energy:

U= m *g*h : equation (1)

U: It's gravitational potential energy in Joules (J)

m: body mass in kilograms (kg)

g= the acceleration of gravity ( $m/s^(2)$ )

h= the body heigt measured from the floor (m)

Known information:

U= 116.62 J

g = 9.8 $m/s^(2)$

h =85m

mass calculation:

We replace the known information in equation 1 :

116.62 = m*9.8*85

m =116.62/(9.8*85)

m= 0,14 kg

The mass of the ball is 0,14 kg

The answer is a. 0.14 kg

PE = mgh
116.62 = m•(9.8)•(85)
m = 116.62/(9.8•85)
= 0.14 kg

Two balls, each with a mass of 0.844 kg,exert a gravitational force of 8.45 × 10−11 Non each other.How far apart are the balls? The value of the universal gravitational constant is 6.673 × 10−11 N m2/kg2.

Answers

The Universal Gravitation law is F=GMm/d^2
So: 8.45x10^-11=6,673x10^-11x0,844x0,844/d^2
d^2=1,78, so finale d=1,33m

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